Problem 37
Question
Can \(C(n, r)\) ever equal \(P(n, r) ?\) Explain.
Step-by-Step Solution
Verified Answer
Yes, when \(r = 1\).
1Step 1: Understanding Combinations
The expression for combinations, denoted as \(C(n, r)\), is given by \(\frac{n!}{r!(n-r)!}\). This represents the number of ways to choose \(r\) items from \(n\) items without considering the order.
2Step 2: Understanding Permutations
The expression for permutations, represented as \(P(n, r)\), is given by \(\frac{n!}{(n-r)!}\). This counts the number of ways to arrange \(r\) items from a total of \(n\) items, so the order does matter.
3Step 3: Analyzing When Combinations Equals Permutations
For \(C(n, r)\) to equal \(P(n, r)\), their expressions must be equivalent: \(\frac{n!}{r!(n-r)!} = \frac{n!}{(n-r)!}\). If we simplify this equation, we find that it only holds when \(r! = 1\). This implies \(r = 1\) since the factorial of 1 is 1.
4Step 4: Conclusion
\(C(n, r) = P(n, r)\) when \(r = 1\). In this case, combinations and permutations are equivalent because selecting one item from \(n\) items doesn't involve multiple orders.
Key Concepts
PermutationsCombinationsFactorial
Permutations
Permutations are an important concept in combinatorics, focusing on the arrangements of a set of items. They emphasize the order of these arrangements. For example, consider arranging letters or numbers where the position is crucial. When we talk about permutations mathematically, we use the notation \( P(n, r) \), where \( n \) is the total number of items and \( r \) is the number of items we're choosing to arrange. The formula for permutations is:\[P(n, r) = \frac{n!}{(n-r)!}\]
- Factorial Use: The factorial function, represented by \( n! \), helps calculate the permutation by reducing possibilities as slots are filled.
- Order Matters: In permutations, rearranging the same items will give a different result, unlike combinations.
Combinations
Combinations differ from permutations by ignoring the order of the arranged items, focusing solely on selection. This is like selecting a group of friends to go out, where the individual choice is important, but the order doesn't change the group.Combinations are denoted as \( C(n, r) \), where \( n \) is the number of available items and \( r \) is how many items we pick. The formula for combinations is:\[C(n, r) = \frac{n!}{r!(n-r)!}\]
- No Order Concern: Combinations care only about which items you take, not the sequence of selection.
- Simple Calculations for Outcomes: Useful in situations like lottery selection where the drawing order doesn't matter.
Factorial
Factorials are a key mathematical concept used in permutations and combinations, often denoted by \( n! \), which means the product of all positive integers up to \( n \). For instance, \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \).Factorials grow extremely fast and play a critical role in calculating permutations and combinations:
- Permutations: Factorials help determine different orderings of items by factoring down for each position.
- Combinations: Factorials adjust for the lack of order significance, dividing out repeated arrangements.
Other exercises in this chapter
Problem 37
For the following exercises, two dice are rolled, and the results are summed. Find the probability of rolling a sum greater than or equal to 15 .
View solution Problem 37
For the following exercises, find the indicated term of each binomial without fully expanding the binomial. The ninth term of \(\left(a-3 b^{2}\right)^{11}\)
View solution Problem 37
For the following exercises, use the formula for the sum of the first \(n\) terms of an arithmetic series to find the sum. \(\sum_{k=1}^{11}\left(\frac{k}{2}-\f
View solution Problem 37
For the following exercises, write an explicit formula for each geometric sequence. \(a_{n}=\\{0.8,-4,20,-100, \ldots\\}\)
View solution