Problem 37
Question
Area of an ellipse The area of an ellipse with axes of length \(2 a\) and \(2 b\) is \(A=\pi a b\). Approximate the percent change in the area when \(a\) increases by \(2 \%\) and \(b\) increases by \(1.5 \%\)
Step-by-Step Solution
Verified Answer
Answer: The area of the ellipse has approximately increased by 3.53% when the major axis length increases by 2% and the minor axis length increases by 1.5%.
1Step 1: Determine the new lengths of the axes after the increase
First, let us find the new lengths of the axes after the increase in percentage. To do so, we multiply each axis length by \((1 + \textit{percentage increase})\).
New length of \(2a\): \((1+0.02)(2a) = 2a(1.02)\)
New length of \(2b\): \((1+0.015)(2b) = 2b(1.015)\)
2Step 2: Calculate the new area of the ellipse after the increase
Next, we use the new axis lengths to calculate the new area of the ellipse. To do this, we use the ellipse area formula, \(A = \pi a b\), and substitute the new axis lengths.
New area, \(A_{new} = \pi (a(1.02))(b(1.015)) = \pi (1.02)(1.015)ab\)
3Step 3: Calculate the percentage change in the area
We will now calculate the percentage change in the area of the ellipse. To do this, we use the percent change formula:
Percent change = \(\frac{\text{New area - Old area}}{\text{Old area}} \times 100\)
\(\text{Percent change} = \frac{A_{new} - A}{A} \times 100\)
Substitute the values of \(A\) and \(A_{new}\):
\(\text{Percent change} = \frac{\pi (1.02)(1.015)ab - \pi ab}{\pi ab} \times 100\)
Factor out \(\pi ab\) from both terms in the numerator:
\(\text{Percent change} = \frac{\pi ab((1.02)(1.015) - 1)}{\pi ab} \times 100\)
Cancel out the \(\pi ab\) terms:
\(\text{Percent change} = ((1.02)(1.015) - 1) \times 100\)
4Step 4: Calculate the numerical value of the percent change
Finally, compute the numerical value of the percent change using the expression we derived:
\(\text{Percent change} = ((1.02)(1.015) - 1) \times 100 \approx 3.53 \%\)
The area of the ellipse has approximately increased by \(3.53\%\) when \(a\) increases by \(2\%\) and \(b\) increases by \(1.5\%\).
Key Concepts
Understanding Percent ChangeExploring Axis Lengths in an EllipseCalculating Percentage Increase
Understanding Percent Change
Percent change measures how much a quantity has increased or decreased in relation to its original value. It's commonly used to compare the initial state to a changed state. To calculate percent change, use the formula:\[ \text{Percent change} = \frac{\text{New value} - \text{Old value}}{\text{Old value}} \times 100 \]This formula helps in determining the relative increase or decrease in a value.
- If the result is positive, it indicates a percentage increase.
- If the result is negative, it shows a percentage decrease.
Exploring Axis Lengths in an Ellipse
An ellipse is defined by its two axes:
- The major axis, stretching across the widest part of the ellipse.
- The minor axis, crossing the shortest section.
Calculating Percentage Increase
Percentage increase is a specific type of percent change, focusing on how much a quantity has grown compared to its original measure. To find the percentage increase, one might calculate:\[ \text{Percentage increase} = \frac{\text{New value - Old value}}{\text{Old value}} \times 100 \]This formula highlights the growth in a quantity when additional attributes are applied. In our ellipse problem:
- Axis \(a\) increases by 2%.
- Axis \(b\) grows by 1.5%.
Other exercises in this chapter
Problem 37
Find an equation of the line of intersection of the planes \(Q\) and \(R\). $$Q: 2 x-y+3 z-1=0 ; R:-x+3 y+z-4=0$$
View solution Problem 37
Interpreting directional derivatives A function \(f\) and a point \(P\) are given. Let \(\theta\) correspond to the direction of the directional derivative. a.
View solution Problem 37
Graph several level curves of the following functions using the given window. Label at least two level curves with their \(z\) -values. $$z=3 \cos (2 x+y) ;[-2,
View solution Problem 37
The \(x\) - and \(y\) -components of a fluid moving in two dimensions are given by the following functions u and \(v\). The speed of the fluid at \((x, y)\) is
View solution