Problem 37
Question
\(1000 \mathrm{~g}\) calcium carbonate solution contains \(10 \mathrm{~g}\) carbonate. The concentration of solution is (a) \(10 \mathrm{ppm}\) (b) \(100 \mathrm{ppm}\) (c) \(1000 \mathrm{ppm}\) (d) \(10,000 \mathrm{ppm}\)
Step-by-Step Solution
Verified Answer
The concentration of the solution is 10,000 ppm, so the answer is (d).
1Step 1: Understand Parts Per Million (ppm)
Understand that ppm is a way to express very dilute concentrations of substances. 1 ppm means 1 part of solute (carbonate in this case) per 1 million parts of the solution. Mathematically, this can be expressed as \( \text{ppm} = \frac{\text{mass of solute}}{\text{total mass of solution}} \times 10^6 \).
2Step 2: Insert Values into the ppm Formula
The given values are 10 g of carbonate as solute and 1000 g of the total solution. Inserting these into the ppm formula, we have \( \text{ppm} = \frac{10}{1000} \times 10^6 \).
3Step 3: Calculate the ppm
Perform the division and multiplication: \( \text{ppm} = 0.01 \times 10^6 = 10,000 \).
4Step 4: Choose the Correct Option
The calculated concentration is 10,000 ppm. Thus, option (d) \(10,000 \mathrm{ppm}\) is correct.
Key Concepts
Understanding Parts Per MillionExploring Solute ConcentrationIntroduction to Calcium Carbonate Solutions
Understanding Parts Per Million
The term "parts per million" (ppm) is a way to specify very dilute concentrations of substances. It is similar to other fraction-based measurements like percentages or parts per billion, but ppm is specifically used when dealing with minute amounts of one component within a vast amount of another.
This unit is commonly used in chemistry and environmental science when measuring pollutant levels, solute measurements in solutions, or even in atmospheric sciences.
This unit is commonly used in chemistry and environmental science when measuring pollutant levels, solute measurements in solutions, or even in atmospheric sciences.
- 1 ppm implies that there is 1 part of solute per 1 million parts of the solution.
- Mathematically, it translates to: \( ext{ppm} = \frac{\text{mass of solute}}{\text{total mass of solution}} \times 10^6 \).
Exploring Solute Concentration
The solute concentration determines how much solute is present in a solution compared to the amount of solvent. A solute is the substance dissolved, while the solvent is what it's dissolved into. For instance, in a sugar-water mixture, sugar is the solute, and water is the solvent.
Concentration can be expressed in various forms like molarity, mass percentage, or ppm—each depending on how dilute or concentrated the solution is.
Concentration can be expressed in various forms like molarity, mass percentage, or ppm—each depending on how dilute or concentrated the solution is.
- Low concentrations often use ppm, especially when the solute's presence is barely perceptible.
- To calculate solute concentration in ppm: you use the formula \( ext{ppm} = \frac{\text{mass of solute}}{\text{total mass of solution}} \times 10^6 \).
Introduction to Calcium Carbonate Solutions
Calcium carbonate is a common chemical compound found in rocks as minerals like calcite or limestone. It is often encountered in various applications ranging from industrial uses to food additives.
In aqueous solutions, calcium carbonate can dissolve slightly but remains mostly as a suspension or precipitate due to its low solubility in water.
In aqueous solutions, calcium carbonate can dissolve slightly but remains mostly as a suspension or precipitate due to its low solubility in water.
- In scientific studies, it is crucial to determine its concentration precisely, often using ppm, especially when evaluating solubility or biological effects.
- In the provided exercise, a solution of calcium carbonate was used, highlighting the way ppm can specify its concentration in a large mixture.
Other exercises in this chapter
Problem 34
A compound possess \(8 \%\) sulphur by mass. The least molecular mass is (a) 200 (b) 400 (c) 155 (d) 355
View solution Problem 35
The vapour density of ozone is (a) 24 (b) 16 (c) 48 (d) 72
View solution Problem 38
One mole of \(\mathrm{CH}_{4}\) contains (a) \(4.0 \mathrm{~g}\) atoms of hydrogen (b) \(3.0 \mathrm{~g}\) atom of carbon (c) \(6.02 \times 10^{23}\) atoms of h
View solution Problem 40
The maximum number of molecules is present in (a) \(15 \mathrm{~L}\) of \(\mathrm{H}_{2}\) gas at STP (b) \(5 \mathrm{~L}\) of \(\mathrm{N}_{2}\) gas at STP (c)
View solution