Problem 36
Question
Write an equation of each line. Write the equation in the form \(x=a, y=b\), or \(y=m x+b\). See Examples 5 and \(6 .\) Through (2,-3)\(;\) parallel to \(x-5 y=10\)
Step-by-Step Solution
Verified Answer
The equation is: \[ y = \frac{1}{5}x - \frac{17}{5} \].
1Step 1: Identify the form of the given line
The given line equation is in the form of a linear equation: \( x - 5y = 10 \). This can be rewritten in the slope-intercept form \( y = mx + b \).
2Step 2: Rewrite the given equation in slope-intercept form
Starting from the equation \( x - 5y = 10 \), we need to convert it to the slope-intercept form.Subtract \(x\) from both sides to get:\[-5y = -x + 10\]Next, divide every term by \(-5\) to solve for \(y\):\[y = \frac{1}{5}x - 2\]Thus, the slope \(m\) of the line is \(\frac{1}{5}\).
3Step 3: Use the slope for the parallel line
Lines that are parallel have the same slope. Therefore, the line we are looking for will also have a slope of \(\frac{1}{5}\).
4Step 4: Use point-slope form
To find the equation of the line that passes through the point (2, -3) and has a slope of \(\frac{1}{5}\), use the point-slope form of the line equation:\[ y - y_1 = m(x - x_1) \]where \((x_1, y_1)\) is the point (2, -3) and \(m\) is \(\frac{1}{5}\).
5Step 5: Substitute the known values into the point-slope equation
Substitute \(x_1 = 2\), \(y_1 = -3\), and \(m = \frac{1}{5}\) into the equation:\[ y - (-3) = \frac{1}{5}(x - 2) \]This simplifies to:\[ y + 3 = \frac{1}{5}x - \frac{2}{5} \]
6Step 6: Simplify to slope-intercept form
Solving for \(y\), subtract 3 from both sides of the equation to simplify:\[ y = \frac{1}{5}x - \frac{2}{5} - 3 \]Convert \(-3\) to a fraction with the same denominator:\[-3 = -\frac{15}{5}\]Now combine the fractions:\[ y = \frac{1}{5}x - \frac{2}{5} - \frac{15}{5} \]\[ y = \frac{1}{5}x - \frac{17}{5} \]
7Step 7: Write the final equation
Thus, the equation of the line parallel to \( x - 5y = 10 \) and passing through (2, -3) is:\[ y = \frac{1}{5}x - \frac{17}{5} \].
Key Concepts
Slope-Intercept FormPoint-Slope FormParallel Lines
Slope-Intercept Form
The slope-intercept form of a linear equation is one of the most common ways to express a straight line. It is written as \( y = mx + b \), where:
- \( m \) is the slope of the line, which represents the steepness or incline. A positive slope means the line rises as it moves from left to right, and a negative slope means it falls.
- \( b \) is the y-intercept, where the line crosses the y-axis.
Point-Slope Form
Another way to express a linear equation is through the point-slope form, which is particularly useful for writing equations when a point on the line and the slope are known. The point-slope formula is \( y - y_1 = m(x - x_1) \), where:
- \((x_1, y_1)\) is a specific point on the line. This point can be any point the line passes through.
- \( m \) is the slope of the line.
Parallel Lines
Parallel lines are a fascinating concept in geometry, known for maintaining a constant distance apart, never meeting no matter how far they extend. This unique property is mathematically reflected by their slopes.
- Parallel lines have identical slopes. This means if you have a line with a slope \( m \), any line parallel to it will share the same slope \( m \).
Other exercises in this chapter
Problem 36
If \(f(x)=\frac{x^{2}+5}{x}\) and \(g(x)=\frac{x^{2}+2 x}{x+3},\) find each function value. $$ f(2) $$
View solution Problem 36
Simplify. $$ y^{7} \cdot y^{11} $$
View solution Problem 36
Graph each piecewise-defined function. Use the graph to determine the domain and range of the function. $$ g(x)=\left\\{\begin{array}{rll} -3 x & \text { if } &
View solution Problem 37
If \(f(x)=\frac{x^{2}+5}{x}\) and \(g(x)=\frac{x^{2}+2 x}{x+3},\) find each function value. $$ \text { Find the domain of } f(x) \text { . } $$
View solution