Problem 36
Question
Verify each identity. $$\cos (\pi-x)=-\cos x$$
Step-by-Step Solution
Verified Answer
After evaluating the identity using the cosine of difference formula, we find that indeed \(\cos (\pi-x)=-\cos x\).
1Step 1: Setup
We are asked to prove, for any angle \(x\), that \(\cos (\pi-x)=-\cos x\).
2Step 2: Using the cosine of difference identity
We know that the cosine of difference of two angles is given by \(\cos(a - b) = \cos a \cos b + \sin a \sin b\). So we can rewrite our expression as \(cos(\pi - x) = \cos\pi \cos x + \sin\pi \sin x\).
3Step 3: Evaluate
We know that \(\cos\pi = -1\) and \(\sin\pi = 0\). So our expression becomes \(-1 \cdot \cos x + 0 = -\cos x\).
Other exercises in this chapter
Problem 36
In Exercises \(35-38,\) use the power-reducing formulas to rewrite each expression as an equivalent expression that does not contain powers of trigonometric fun
View solution Problem 36
Involve equations with multiple angles. Solve each equation on the interval \([0,2 \pi)\) $$\cot \frac{3 \theta}{2}=-\sqrt{3}$$
View solution Problem 37
Verify each identity. $$\frac{\sin ^{2} x-\cos ^{2} x}{\sin x+\cos x}=\sin x-\cos x$$
View solution Problem 37
In Exercises \(35-38,\) use the power-reducing formulas to rewrite each expression as an equivalent expression that does not contain powers of trigonometric fun
View solution