Problem 36
Question
Use Cramer's rule, whenever applicable, to solve the system. $$\left\\{\begin{array}{rr} 7 x-8 y= & 9 \\ 4 x+3 y= & -10 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
The solution is \( x = -1 \) and \( y = -2 \).
1Step 1: Write the System in Matrix Form
The given system of equations can be represented using matrices. The coefficient matrix, variable matrix, and constant matrix are: \[ A = \begin{pmatrix} 7 & -8 \ 4 & 3 \end{pmatrix}, \quad X = \begin{pmatrix} x \ y \end{pmatrix}, \quad B = \begin{pmatrix} 9 \ -10 \end{pmatrix} \].So, the system in matrix form is \( AX = B \).
2Step 2: Calculate the Determinant of the Coefficient Matrix
To apply Cramer's rule, we first compute the determinant of the coefficient matrix, \( A \). The determinant is calculated as:\[\text{det}(A) = \begin{vmatrix} 7 & -8 \ 4 & 3 \end{vmatrix} = (7 \cdot 3) - (-8 \cdot 4) = 21 + 32 = 53.\] Since \( \text{det}(A) eq 0 \), Cramer's rule is applicable.
3Step 3: Calculate Determinants for Variables using Cramer's Rule
Using Cramer's rule, we calculate the determinants needed for \( x \) and \( y \):For \( x \): Replace the first column of the matrix \( A \) with \( B \):\[A_x = \begin{pmatrix} 9 & -8 \ -10 & 3 \end{pmatrix}\]\[\text{det}(A_x) = (9 \cdot 3) - (-8 \cdot -10) = 27 - 80 = -53\]For \( y \): Replace the second column of the matrix \( A \) with \( B \):\[A_y = \begin{pmatrix} 7 & 9 \ 4 & -10 \end{pmatrix}\]\[\text{det}(A_y) = (7 \cdot -10) - (9 \cdot 4) = -70 - 36 = -106\]
4Step 4: Solve for the Variables using Cramer's Rule
Now, we use Cramer's rule to solve for \( x \) and \( y \):\( x = \frac{\text{det}(A_x)}{\text{det}(A)} = \frac{-53}{53} = -1 \)\( y = \frac{\text{det}(A_y)}{\text{det}(A)} = \frac{-106}{53} = -2 \)
Key Concepts
DeterminantsSystems of EquationsMatrix Algebra
Determinants
Determinants serve as a function that takes a square matrix and produces a single number, often crucial in solving systems of linear equations, particularly in Cramer's rule. For a 2x2 matrix, the determinant is calculated using the formula:\[\text{det}(A) = ad - bc\]where \(A\) is a matrix \( \begin{pmatrix} a & b \ c & d \end{pmatrix} \). The determinant provides important information about the matrix, such as if the matrix is invertible or if a system of equations has a unique solution. If a matrix has a determinant of zero, it indicates that the matrix is singular and does not have an inverse, meaning the system of equations may not have a unique solution.
- Non-zero Determinants: Suggest a unique solution.
- Zero Determinants: Indicate either no solutions or infinitely many solutions.
Systems of Equations
Systems of equations consist of multiple equations that share the same set of unknowns. The goal is to find values for these unknowns that satisfy all equations simultaneously. Systems can be represented in different ways, including algebraically, graphically, or in matrix form. In linear algebra, most systems can be encapsulated by matrices and solved through various methods, such as:
- Graphical methods
- Substitution and elimination
- Matrix methods like Gaussian elimination and Cramer's rule
Matrix Algebra
Matrix algebra is a branch of mathematics that deals with matrices and the operations that can be performed on them. This includes addition, subtraction, multiplication, and the computation of determinants and inverses. When handling systems of equations like the one in this exercise, matrices serve to streamline the computation.
- Matrix Representation: Transforms systems of equations into an easy-to-manage structure.
- Operations: Allow for various manipulations such as multiplication, useful for transforming and solving systems.
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