Problem 36
Question
Use a truth table to determine whether each statement is a tautology, a self- contradiction, or neither. \([(p \rightarrow q) \wedge \sim p] \rightarrow \sim q\)
Step-by-Step Solution
Verified Answer
After evaluating the given statement using truth table, one can conclude whether the statement is Tautology, Self-contradiction, or Neither.
1Step 1: Formation of a truth table with every possibility of the variables
The first step involves the creation of a truth table to present all possible combinations of p and q. That means p and q can either be true (T) or false (F), thus yielding to four possible combinations.
2Step 2: Calculation of the compound statements
In this step, evaluate each individual operation, starting from individual negations, implications, and finally the overall expression. Here, first calculate \(p \rightarrow q\), then \(\sim p\), after that evaluate the conjunction operation \([(p \rightarrow q) \wedge \sim p]\), and finally the implication operation with \(\sim q\).
3Step 3: Inspection and Conclusion
Check the final column of your table. If all values are true, then the statement is a tautology. If all values are false, the statement is a self-contradiction. If there are both true and false values, the statement is neither a tautology nor a self-contradiction.
Key Concepts
TautologyLogical ContradictionImplication in Logic
Tautology
A tautology in logic refers to a statement that is always true, no matter what the truth values of the individual components are. It is one of the cornerstones of logical analysis because a tautological statement is immutable and serves as a reliable foundation for reasoning and constructing logical arguments.
Consider the expression \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q. To determine whether it's a tautology, one would use a truth table to systematically evaluate the statement's truth value under all possible truth values of its components (p and q). If every possible combination yields a 'true' result, then the expression is indeed a tautology. However, in the case of our given exercise, the truth table will show that the statement isn't always true, thereby confirming that it isn't a tautology.
Consider the expression \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q. To determine whether it's a tautology, one would use a truth table to systematically evaluate the statement's truth value under all possible truth values of its components (p and q). If every possible combination yields a 'true' result, then the expression is indeed a tautology. However, in the case of our given exercise, the truth table will show that the statement isn't always true, thereby confirming that it isn't a tautology.
Logical Contradiction
A logical contradiction is the antithesis of a tautology. This occurs when a statement is always false, regardless of the truth values of its constituent parts. In effect, contradictions can never be true and represent a fundamental dissonance within the statement's logic.
In the exercise given, using a truth table helps reveal whether \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q is a contradiction by checking if all outcomes are false. If they are, it confirms the statement as a contradiction. However, for this particular statement, the truth table would show a mix of true and false outcomes across its possible interpretations, which tells us that it isn't a contradiction.
In the exercise given, using a truth table helps reveal whether \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q is a contradiction by checking if all outcomes are false. If they are, it confirms the statement as a contradiction. However, for this particular statement, the truth table would show a mix of true and false outcomes across its possible interpretations, which tells us that it isn't a contradiction.
Implication in Logic
Implication in logic, often represented as '\((p \rightarrow q)\)', is a fundamental concept used to describe a conditional statement that asserts 'if p, then q.' It suggests a logical relationship where the truth of q is guaranteed if p is true, but if p is false, q can be either true or false without affecting the implication's truth value.
When constructing the truth table for \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q, one of the critical steps is calculating the truth value of the implication \(p \rightarrow q\). Understanding the dynamics of implication is essential because it allows one to grasp the flow of logic from premises to conclusion. Nonetheless, in our exercise, since the overall expression includes negations and conjunctions alongside the implication, the truth table will indicate that the final outcome is dependent on the interplay of these operations, not solely on the principle of implication.
When constructing the truth table for \( (p \rightarrow q) \wedge \sim p \) \rightarrow \sim q, one of the critical steps is calculating the truth value of the implication \(p \rightarrow q\). Understanding the dynamics of implication is essential because it allows one to grasp the flow of logic from premises to conclusion. Nonetheless, in our exercise, since the overall expression includes negations and conjunctions alongside the implication, the truth table will indicate that the final outcome is dependent on the interplay of these operations, not solely on the principle of implication.
Other exercises in this chapter
Problem 36
Write the negation of each statement. \(\sim p \vee q\)
View solution Problem 36
Express each statement in "if ... then" form. (More than one correct wording in "if... then" form may be possible.) Then write the statement's converse, inverse
View solution Problem 36
Construct a truth table for the given statement. \((p \vee \sim q) \wedge(p \vee q)\)
View solution Problem 36
Let \(p\) and \(q\) represent the following simple statements: \(p\) : The heater is working. \(q:\) The house is cold. Write each symbolic statement in words.
View solution