Problem 36
Question
Use a table of values to evaluate each function as \(x\) approaches the value indicated. If the function seems to approach a limiting value, write the relationship in words and using the limit notation. $$g(x)=10 x-x^{2} ; x \rightarrow-2$$
Step-by-Step Solution
Verified Answer
As \(x\) approaches \(-2\), \(g(x)\) approaches \(-24\): \(\lim_{{x \to -2}} g(x) = -24\).
1Step 1: Setting Up the Table
To evaluate the function \(g(x) = 10x - x^2\) as \(x\) approaches \(-2\), we will create a table of values for \(x\) around \(-2\). Choose values slightly less than \(-2\), slightly more than \(-2\), and equal to \(-2\). Values such as \(-2.1\), \(-2\), and \(-1.9\) are good starting points.
2Step 2: Calculating \(g(x)\) Values
Calculate \(g(x)\) for each chosen \(x\).1. For \(x = -2.1\): \(g(-2.1) = 10(-2.1) - (-2.1)^2 = -21 - 4.41 = -25.41\) 2. For \(x = -2\): \(g(-2) = 10(-2) - (-2)^2 = -20 - 4 = -24\) 3. For \(x = -1.9\): \(g(-1.9) = 10(-1.9) - (-1.9)^2 = -19 - 3.61 = -22.61\)
3Step 3: Analyzing \(g(x)\) Values
By examining the values calculated:- As \(x\) approaches \(-2\), \(g(x)\) seems to approach \(-24\) since \(g(-2) = -24\), and the calculated values move towards that as \(x\) nears \(-2\).
4Step 4: Writing the Limit Notation
Since \(g(x)\) approaches \(-24\) as \(x\) approaches \(-2\), we can write: \[\lim_{{x \to -2}} g(x) = -24\]In words, as \(x\) nears \(-2\), the function \(g(x)\) gets closer to \(-24\).
Key Concepts
Evaluating FunctionsTable of ValuesLimit Notation
Evaluating Functions
Evaluating functions is a core aspect of understanding how a mathematical relationship behaves over different inputs. In this exercise, we were given the function \( g(x) = 10x - x^2 \), which is a quadratic function. This means that the function maps each \( x \) value in the domain to a unique \( g(x) \) output based on the equation provided. To evaluate this function at specific points, you substitute the specific \( x \) values directly into the function. For instance, when substituting \( x = -2 \) into our function, you calculate \( g(-2) = 10(-2) - (-2)^2 = -20 - 4 = -24 \). By repeating this process for values near \( x = -2 \), you can predict how the function behaves around that point. This is essential for understanding concepts such as continuity and approaching limits in precalculus.Evaluating functions involves:
- Inserting chosen \( x \) values into the function equation.
- Performing arithmetic operations as defined by the function rule.
- Interpreting the result to understand the function's behavior at and near specific points.
Table of Values
When trying to evaluate a function as \( x \) approaches a particular value, using a table is a powerful visual tool. It helps organize the data for each \( x \) value you choose to evaluate and provides a clear picture of how the function behaves around that point.Creating a table of values involves choosing \( x \) values near the point of interest—in this case, \( -2 \). You then calculate the corresponding \( g(x) \) values based on the function. For instance:
- For \( x = -2.1 \), find \( g(x) \).
- For \( x = -2 \), find \( g(x) \).
- For \( x = -1.9 \), find \( g(x) \).
Limit Notation
Limit notation is a concise way to express the behavior of a function as its input (\( x \)) approaches a specific value. In this exercise, as we observed that \( g(x) \) approaches \(-24\) as \( x \) approaches \(-2\), limit notation allows us to describe this behavior mathematically as \( \lim_{{x \to -2}} g(x) = -24 \).Understanding limit notation involves:
- The limit symbol \( \lim \) which signifies approaching behavior.
- The subscript \( x \to -2 \), showing the input approaching the value -2.
- The function \( g(x) \) on which the limit operates.
- The resulting limit value of \(-24\) which the function approaches.
Other exercises in this chapter
Problem 36
Graph each function over the interval [0,7]. Then use geometry to find the area of the region below the graph, and above the \(x\) -axis in the interval [0,6].
View solution Problem 36
Evaluate the following limits by rewriting the given expression as needed. $$\lim _{x \rightarrow 3} \frac{2 x^{3}-12 x^{2}+18 x}{x^{2}-7 x+12}$$
View solution Problem 37
Determine whether the statement is true or false. Explain your answer. If \(f(x) \cos x=\sin x,\) then \(f^{\prime}(x)=\sec ^{2} x\)
View solution Problem 37
Evaluate the following limits. Write your answer in simplest form. $$\lim _{h \rightarrow 0} \frac{\left[2(x+h)^{2}-(x+h)\right]-\left(2 x^{2}-x\right)}{h}$$
View solution