Problem 36
Question
To answer Exercises \(33-40\), consider the following numbers. \(\begin{array}{rrrr}305 & 313,332 & 876 & 64,000 \\ 1101 & 7624 & 1110 & 9990 \\\ 13,205 & 111,126 & 5128 & 126,111\end{array}\) Which of the above are divisible by \(5 ?\)
Step-by-Step Solution
Verified Answer
305, 64,000, 1110, 9990, 13,205
1Step 1 - Identify criteria for divisibility by 5
A number is divisible by 5 if its last digit is either 0 or 5.
2Step 2 - List the given numbers
The given numbers are: 305, 313,332, 876, 64,000, 1101, 7624, 1110, 9990, 13,205, 111,126, 5128, 126,111.
3Step 3 - Check each number's last digit
Examine the last digit of each number:1. 305 ends with 52. 313,332 ends with 23. 876 ends with 64. 64,000 ends with 05. 1101 ends with 16. 7624 ends with 47. 1110 ends with 08. 9990 ends with 09. 13,205 ends with 510. 111,126 ends with 611. 5128 ends with 812. 126,111 ends with 1
4Step 4 - Determine which numbers are divisible by 5
Numbers from the list that end with 0 or 5 are divisible by 5. These numbers are:1. 3052. 64,0003. 11104. 99905. 13,205
Key Concepts
Divisibility by 5Number PropertiesStep-by-Step Problem Solving
Divisibility by 5
Divisibility rules help us quickly determine if one number is divisible by another without performing long division.
For a number to be divisible by 5, its last digit must be either 0 or 5. This rule is simple but very useful.
For example, consider the number 305. Since it ends in 5, it meets the criterion and is divisible by 5.
Similarly, the number 64,000 ends with 0, making it also divisible by 5.
Exercises that ask you to determine if numbers are divisible by 5 will always follow this straightforward rule. Checking the last digit can save you a lot of time and effort.
For a number to be divisible by 5, its last digit must be either 0 or 5. This rule is simple but very useful.
For example, consider the number 305. Since it ends in 5, it meets the criterion and is divisible by 5.
Similarly, the number 64,000 ends with 0, making it also divisible by 5.
Exercises that ask you to determine if numbers are divisible by 5 will always follow this straightforward rule. Checking the last digit can save you a lot of time and effort.
Number Properties
Properties of numbers are fundamental in various mathematical operations and problem-solving scenarios.
Understanding number properties can help you predict behaviors and outcomes without extensive calculation.
For example, even and odd numbers have unique properties:
Recognizing these properties helps simplify problems and arrive at the solution more efficiently.
Understanding number properties can help you predict behaviors and outcomes without extensive calculation.
For example, even and odd numbers have unique properties:
- Adding two even numbers or two odd numbers always gives an even number.
- Adding an even number to an odd number always results in an odd number.
Recognizing these properties helps simplify problems and arrive at the solution more efficiently.
Step-by-Step Problem Solving
Breaking down problems into smaller, manageable steps is crucial in mathematics.
This method provides clarity and supports systematic thinking.
Let's revisit our problem about divisibility by 5 for a practical approach:
This method can be applied to various types of problems, making problem-solving easier and more structured.
This method provides clarity and supports systematic thinking.
Let's revisit our problem about divisibility by 5 for a practical approach:
- Step 1: Identify the criteria for divisibility by 5 (last digit is either 0 or 5).
- Step 2: List the given numbers.
- Step 3: Examine the last digit of each number to check if they meet the criteria.
- Step 4: List the numbers that are divisible by 5.
This method can be applied to various types of problems, making problem-solving easier and more structured.
Other exercises in this chapter
Problem 36
A gasoline can holds \(\frac{5}{2}\) gal. How much will the can hold when it is \(\frac{1}{2}\) full?
View solution Problem 36
Multiply and simplify. $$ 150 \cdot \frac{1}{5} $$
View solution Problem 36
Solve. \(\frac{4}{9} \cdot m=\frac{8}{3}\)
View solution Problem 37
Determine whether each number is prime, composite, or neither. $$ 1 $$
View solution