Problem 36
Question
The following substances undergo complete combustion in a bomb calorimeter. The calorimeter assembly has a heat capacity of \(5.136 \mathrm{kJ} /^{\circ} \mathrm{C} .\) In each case, what is the final temperature if the initial water temperature is \(22.43^{\circ} \mathrm{C} ?\) \(\begin{array}{lllll}\text { (a) } 0.3268 & \text { g caffeine, } & \mathrm{C}_{8} \mathrm{H}_{10} \mathrm{O}_{2} \mathrm{N}_{4} & \text { (heat of }\end{array}\) combustion \(=-1014.2 \mathrm{kcal} / \mathrm{mol} \text { caffeine })\) (b) \(1.35 \mathrm{mL}\) of methyl ethyl ketone, \(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}(1)\) \(d=0.805 \mathrm{g} / \mathrm{mL}\) (heat of combustion \(=-2444 \mathrm{kJ} / \mathrm{mol}\) methyl ethyl ketone).
Step-by-Step Solution
Verified Answer
The final temperature of the water after the combustion of caffeine is 22.747°C, and for methyl ethyl ketone it is 29.575°C.
1Step 1: Calculate number of moles of the first substance
Calculate the number of moles (n₁) for caffeine as the molecular weight of caffeine is 194.19 g/mol.\n\n\[ n₁ = 0.3268/194.19 = 0.001682 mol \]
2Step 2: Calculate change in temperature for the first substance
Next, the change in temperature (∆t₁) due to combustion of caffeine can be calculated using the relation ∆t = - ( ∆Hc ⋅ n ) / C.\n\n\[ ∆t₁ = - ( -1014.2 × 0.001682 ) / 5.136 = 0.317°C \]
3Step 3: Final temperature for the first substance
Now we can find the final temperature of the water (T₁) for caffeine combustion, by adding the initial temperature to ∆t₁.\n\n\[ T₁ = 22.43 + 0.317 = 22.747°C \]
4Step 4: Calculate number of moles of the second substance
Now, calculate the number of moles (n₂) for methyl ethyl ketone (C₄H₈O). The molecular weight of C₄H₈O is 72.105 g/mol, and the given volume is 1.35 mL with a density of 0.805 g/mL, from which we get the mass.\n\n\[ m = 1.35 × 0.805 = 1.08675 g \]\n\n\[ n₂ = 1.08675/72.105 = 0.015064 mol \]
5Step 5: Calculate change in temperature for the second substance
Now, the change in temperature (∆t₂) due to combustion of methyl ethyl ketone can be calculated in a similar manner as in Step 2. However, we use 2444 kJ/mol instead of kcal/mol and also insert the heat of combustion with a negative value.\n\n\[ ∆t₂ = - ( -2444 × 0.015064 ) / 5.136 = 7.145°C \]
6Step 6: Final temperature for the second substance
Finally, the final temperature of the water upon combustion of methyl ethyl ketone (T₂) can be calculated by adding the initial temperature to ∆t₂.\n\n\[ T₂ = 22.43 + 7.145 = 29.575°C \]
Key Concepts
Combustion ReactionsHeat CapacityTemperature ChangeCaffeine CombustionMethyl Ethyl Ketone Combustion
Combustion Reactions
Combustion reactions are chemical processes where a substance combines with oxygen, releasing energy in the form of heat and sometimes light. We commonly refer to these as burning. These reactions are exothermic, meaning they produce heat as they proceed. Combustion is vital in energy production, such as in car engines, power plants, and even for heating our homes.
- The reaction generally involves hydrocarbons or other organic compounds.
- Oxygen from the air is the typical reactant that fuels the combustion process.
- The products typically include carbon dioxide (CO₂) and water (H₂O).
Heat Capacity
Heat capacity is an important concept in thermodynamics and refers to the amount of heat required to change the temperature of a system by one degree Celsius. This property tells us how well a system can hold and absorb heat. Specifically, in our exercise, we use the heat capacity of the calorimeter to determine how much the temperature changes during a reaction.
- Heat capacity can be expressed in units of joules per degree Celsius (J/°C) or kilojoules per degree Celsius (kJ/°C).
- A higher heat capacity means that more heat is required to change the temperature of the system.
- In a bomb calorimeter, the heat capacity often includes the calorimeter's components and any water surrounding the reaction vessel.
Temperature Change
Temperature change is a key indicator of the energy exchanged in a chemical reaction. In the context of bomb calorimetry, the temperature change of the water in the calorimeter indicates how much energy is released during combustion.
- The formula to calculate temperature change (\( \Delta t \)) is: \( \Delta t = \frac{- ( \Delta H_c \cdot n )}{C} \), where \( \Delta H_c \) is the heat of combustion, \( n \) is the number of moles, and \( C \) is the heat capacity of the calorimeter.
- A positive \( \Delta t \) indicates that the temperature rises as the reaction proceeds, signifying an exothermic reaction.
- By knowing the initial and final temperatures, one can deduce how much heat was released in physical terms during the reaction.
Caffeine Combustion
Caffeine combustion refers to the reaction where caffeine (\( \text{C}_8 \text{H}_{10} \text{O}_2 \text{N}_4 \)) is burned or oxidized in the presence of oxygen, typically done in a bomb calorimeter to measure the energy released. In our exercise, we learned how to calculate the temperature change resulting from caffeine combustion.
- First, determine the number of moles of caffeine using its molecular weight, calculated as \( \frac{0.3268}{194.19} \approx 0.001682 \text{mol}. \)
- The heat of combustion (\(-1014.2 \text{kcal/mol} \)) tells us how much energy is released per mole of substance.
- By substituting values into the formula for \( \Delta t \), we find the temperature change due to caffeine combustion is 0.317°C, signifying a rise in temperature.
Methyl Ethyl Ketone Combustion
Methyl ethyl ketone (MEK) is a flammable liquid often used as a solvent. Its combustion in a bomb calorimeter provides insight into its energetic properties. In our exercise, we calculated the temperature change resulting from the combustion of MEK.
- First, the mass of MEK is determined by multiplying its volume (1.35 mL) by its density (0.805 g/mL), resulting in 1.08675 g.
- The number of moles is then calculated using its molecular weight (72.105 g/mol), yielding \( \frac{1.08675}{72.105} \approx 0.015064 \text{mol}. \)
- Using the heat of combustion (\(-2444 \text{kJ/mol} \)), we find a temperature rise of 7.145°C, indicating significant energy release.
Other exercises in this chapter
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