Problem 36
Question
The binding energy of an element is \(64 \mathrm{MeV}\). If BE per nucleon is \(6.4\), the number of nucleons are (a) 10 (b) 64 (c) 16 (d) 6
Step-by-Step Solution
Verified Answer
The number of nucleons is 10.
1Step 1: Understanding the Concept
The binding energy (BE) of an element refers to the amount of energy required to disassemble the element into its individual nucleons, which are protons and neutrons. The BE per nucleon is the binding energy divided by the total number of nucleons in the nucleus. We will use this relationship to find the total number of nucleons.
2Step 2: Setting up the Equation
You are given that the total binding energy of the element is 64 MeV and the binding energy per nucleon is 6.4 MeV. To find the number of nucleons (let's call this number 'N'), we use the equation: \[ BE = N imes BE_{per\, nucleon} \] where \( BE_{per\, nucleon} = 6.4 \text{ MeV} \) and \( BE = 64 \text{ MeV} \).
3Step 3: Solving the Equation
Substitute the given values into the equation: \[ 64 = N imes 6.4 \] Now solve for \( N \) by dividing both sides by 6.4: \[ N = \frac{64}{6.4} \]
4Step 4: Calculating the Number of Nucleons
Perform the division: \[ N = \frac{64}{6.4} = 10 \] Thus, the number of nucleons in the element is 10.
Key Concepts
NucleonsBinding Energy per NucleonNuclear Physics Concepts
Nucleons
Nucleons are the building blocks of the atomic nucleus. These include protons and neutrons.
Protons are positively charged particles, while neutrons have no charge. Despite the difference in charge, both types of particles are roughly equal in mass, and together they create the mass of an atomic nucleus.
In any given nucleus, the sum of protons and neutrons is called the mass number or nucleon number.
Understanding the concept of nucleons is essential for grasping more complex topics in nuclear physics.
Protons are positively charged particles, while neutrons have no charge. Despite the difference in charge, both types of particles are roughly equal in mass, and together they create the mass of an atomic nucleus.
In any given nucleus, the sum of protons and neutrons is called the mass number or nucleon number.
- This reveals the total number of nucleons in the nucleus.
- The number of protons determines the element's identity on the periodic table.
- The number of neutrons can vary within atoms of the same element, creating different isotopes.
Understanding the concept of nucleons is essential for grasping more complex topics in nuclear physics.
Binding Energy per Nucleon
Binding energy per nucleon is a way to measure how tightly each nucleon is held within the nucleus.
It is the total binding energy of the nucleus divided by the number of nucleons.
This value is significant because it gives an insight into the stability of a nucleus. For example:
Such calculations help physicists understand nuclear reactions and energy release phenomena.
It is the total binding energy of the nucleus divided by the number of nucleons.
This value is significant because it gives an insight into the stability of a nucleus. For example:
- If the binding energy per nucleon is high, it means that the nucleus is more stable.
- A lower value suggests a less stable nucleus that could be more susceptible to breaking apart.
Such calculations help physicists understand nuclear reactions and energy release phenomena.
Nuclear Physics Concepts
Nuclear physics explores the core principles governing atomic nuclei. It's a field that delves into powerful forces and energy levels unique to the subatomic realm.
Key concepts include:
This field of study not only aids scientific exploration but also has practical benefits in medicine and energy.
Key concepts include:
- Strong Nuclear Force: This force binds nucleons together, overcoming the repulsive electrostatic forces between protons.
- Radioactivity: Certain nuclei are unstable and release energy by emitting radiation, transforming into different elements.
- Fission and Fusion: These nuclear reactions involve splitting a heavy nucleus or combining light nuclei, respectively, both releasing copious amounts of energy.
This field of study not only aids scientific exploration but also has practical benefits in medicine and energy.
Other exercises in this chapter
Problem 33
The projectile used to bombard \({ }_{7} \mathrm{~N}^{14}\) to get \({ }_{8} \mathrm{O}^{17}\) and a proton is (a) \({ }_{2} \mathrm{He}^{4}\) (b) \({ }_{0} \ma
View solution Problem 34
The half-life of a radioactive isotope is \(1.5\) hours. The mass of it that remains undecayed after 6 hours is (the initial mass of the isotope is \(64 \mathrm
View solution Problem 37
The reaction \({ }_{5} \mathrm{~B}^{8} \longrightarrow \mathrm{Be}^{8}+{ }_{1} \mathrm{e}^{0}\) takes place due to (a) \(\alpha\) decay (b) \(\beta\) decay (c)
View solution Problem 38
The common moderator of a nuclear reactor (a) \(\mathrm{D}_{2} \mathrm{O}\) (b) graphite (c) beryllium (d) all are correct
View solution