Problem 36
Question
The average orbital radius of a star around a galactic black hole has an angular size of 0.25 arcsecond when observed from a distance of 6.2 kpc. What is the orbital radius in kilometers? in astronomical units?
Step-by-Step Solution
Verified Answer
The orbital radius is approximately 2.32 billion kilometers or 155 AU.
1Step 1: Convert Angular Size to Radians
First, we convert the angular size from arcseconds to radians, because astronomical calculations typically use radians. 1 arcsecond is equal to \( \frac{1}{3600} \) of a degree and \( 1 \) degree is \( \frac{\pi}{180} \) radians. Thus, the conversion formula is: \(\theta_{radians} = 0.25 \times \frac{1}{3600} \times \frac{\pi}{180} \)Calculating this gives:\[ \theta_{radians} = 0.25 \times \frac{\pi}{648000} \approx 1.212 \times 10^{-6} \text{ radians}\]
2Step 2: Use Small Angle Formula to Find Distance
The small angle formula relates the angular size \( \theta \) in radians to the physical size \( D \) and the distance \( d \) by \( \theta = \frac{D}{d} \). Given \( d = 6.2 \text{ kpc} \) (which we convert to kilometers using the conversion 1 kpc = 3.086 \times 10^{16} \text{ km}), we solve for \( D \):\[ D = \theta \times d = 1.212 \times 10^{-6} \times 6.2 \times 3.086 \times 10^{16} \]Calculating this gives:\[ D \approx 2.32 \times 10^{10} \text{ km}\]
3Step 3: Convert Kilometers to Astronomical Units
Next, we need to convert the orbital radius from kilometers to astronomical units (AU). 1 AU is approximately equal to 1.496 \times 10^{8} kilometers. So, we use the conversion:\[ D_{AU} = \frac{2.32 \times 10^{10}}{1.496 \times 10^{8}} \]Calculating this gives:\[ D_{AU} \approx 155 AU\]
Key Concepts
Angular Size ConversionSmall Angle FormulaKiloparsec to Kilometers ConversionKilometers to Astronomical Units Conversion
Angular Size Conversion
When observing objects in the sky, astronomers often need to convert the object's apparent size from angles measured in arcseconds to radians. This conversion is crucial because radians are the standard unit used in many astronomical calculations.
- 1 arcsecond is defined as \( \frac{1}{3600} \) of a degree because there are 60 arcseconds in a minute of arc and 60 minutes in a degree.
- 1 degree is \( \frac{\pi}{180} \) radians since there are \( 2\pi \) radians in a circle (360 degrees).
Small Angle Formula
The small angle formula is a handy tool in astronomy connecting three parameters: angular size \( \theta \), physical size \( D \), and distance \( d \). This formula is particularly helpful because it allows us to find one of these parameters if the other two are known, using:\[ \theta = \frac{D}{d} \]
- \( \theta \) is the angular size in radians.
- \( D \) is the actual size of the object.
- \( d \) is the distance to the object.
- Given \( \theta = 1.212 \times 10^{-6} \) radians and \( d = 6.2 \text{ kpc} \).
- Substitute these into the formula to solve for physical size \( D \).
Kiloparsec to Kilometers Conversion
In astronomical terms, a kiloparsec (kpc) is often used to describe large distances between cosmic objects. To perform calculations involving kiloparsecs, converting them into kilometers (km) is necessary because kilometers are more prevalent in detailed calculations.
- 1 parsec is equivalent to approximately 3.086 \( \times 10^{13} \) kilometers.
- Therefore, 1 kiloparsec equals 3.086 \( \times 10^{16} \) kilometers.
Kilometers to Astronomical Units Conversion
Astronomical units (AU) are often more convenient for expressing large distances within the solar system or nearby stars.One AU is equivalent to the average distance from Earth to the Sun, about 1.496 \( \times 10^{8} \) kilometers.
- To convert from kilometers to astronomical units, divide the distance in kilometers by 1.496 \( \times 10^{8} \).
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