Problem 36
Question
$$\text { Solve each equation analytically. Check it analytically, and then support your solution graphically.}$$ $$6[x-(2-3 x)+1]=4 x-6$$
Step-by-Step Solution
Verified Answer
The solution is \( x = 0 \).
1Step 1: Simplify the Expression Inside the Brackets
Start by simplifying the brackets: \( x - (2 - 3x) + 1 \). Distribute the negative sign inside the brackets to get \( x - 2 + 3x + 1 \). Combine like terms to simplify it to \( 4x - 1 \).
2Step 2: Distribute and Set Up Equation
Substitute the simplified expression back into the equation: \( 6[4x - 1] = 4x - 6 \). Distribute the 6 to both terms inside the brackets, resulting in \( 24x - 6 = 4x - 6 \).
3Step 3: Solve for x
To isolate \( x \), start by subtracting \( 4x \) from both sides: \( 24x - 4x - 6 = -6 \). Simplify to \( 20x - 6 = -6 \). Next, add 6 to both sides: \( 20x - 6 + 6 = -6 + 6 \), resulting in \( 20x = 0 \). Divide both sides by 20 to find \( x = 0 \).
4Step 4: Check the Solution Analytically
Substitute \( x = 0 \) back into the original equation: \( 6[0 - (2 - 3(0)) + 1] = 4(0) - 6 \). Simplify inside the bracket to get \( 6[-1] = -6 \). This simplifies to \( -6 = -6 \), confirming that \( x = 0 \) is a solution.
5Step 5: Support the Solution Graphically
To graphically support the solution, draw the graph of both sides of the equation. The left side \( 6(4x - 1) \) is a linear function. The right side \( 4x - 6 \) is also a linear function. Both graphs intersect at \( x = 0 \), which confirms the solution.
Key Concepts
Graphical SolutionLinear FunctionsAnalytical Solution
Graphical Solution
When we solve equations graphically, we aim to find the point where two functions intersect by plotting them on a graph. In the given exercise, we have two linear functions: the left side of the equation, \( 6(4x - 1) \), and the right side, \( 4x - 6 \).
Your task is to plot these on a graph and visually determine where the two lines meet. This intersection point represents the solution to the equation. If the lines intersect at \( x = 0 \), as verified by our analytical solution, this graphical solution presents a visual confirmation of the algebraic solution. Graphical solutions are especially helpful for verifying complex algebraic solutions or understanding how different linear functions relate to one another.
To graph:
Your task is to plot these on a graph and visually determine where the two lines meet. This intersection point represents the solution to the equation. If the lines intersect at \( x = 0 \), as verified by our analytical solution, this graphical solution presents a visual confirmation of the algebraic solution. Graphical solutions are especially helpful for verifying complex algebraic solutions or understanding how different linear functions relate to one another.
To graph:
- Draw a horizontal axis (x-axis) and a vertical axis (y-axis).
- Plot the function \( y = 6(4x - 1) \). This function will be a straight line (because it is linear).
- Next, plot \( y = 4x - 6 \). This line should also be straight.
- Observe the point of intersection—the coordinates of this point give the x-value solution.
Linear Functions
A linear function is a function that creates a straight line when plotted on a graph. These functions are generally expressed in the form \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept.
In the original exercise, both sides of the equation are linear functions:
In the original exercise, both sides of the equation are linear functions:
- The left side, \( 6(4x - 1) \), can be rewritten as \( y = 24x - 6 \).
- The right side, \( 4x - 6 \), is already in the form of a linear equation.
Analytical Solution
Solving equations analytically involves using algebraic methods to find the exact solution. In our exercise, this method was applied to solve for \( x \) step by step, which led to the solution \( x = 0 \).
Here's a simplified overview of the analytical approach:
Here's a simplified overview of the analytical approach:
- Start by simplifying expressions inside any brackets or parentheses.
- Move on to collecting like terms and working to isolate the variable, \( x \), on one side of the equation.
- Distribute and simplify where necessary, in this case, multiplying out the bracket \( 6[4x - 1] \) to get \( 24x - 6 \).
- Next, perform operations to simplify further until you isolate \( x \). This may include moving terms across the equals sign and solving for \( x \).
- Finally, verify your solution by substituting back into the original equation. The simplified check should hold true, confirming \( x = 0 \) as the correct solution.
Other exercises in this chapter
Problem 36
\(f(x)=-5 x+30\) Window A: \([-10,10]\) by \([-10,40]\) Window B: \([-5,5]\) by \([-5,40]\)
View solution Problem 36
Exercises \(33-36\) (a) Express the cost \(C\) as a function of \(x,\) where \(x\) represents the number of items as described. (b) Express the revenue \(R\) as
View solution Problem 36
Name the possible quadrants in which the point ( \(x, y\) ) can lie if the given condition is true. $$x y
View solution Problem 37
Write equation in the form \(y=m x+b .\) (A suggested window for a comprehensive graph of the equation is given. \(5 x+3 y=15\) \([-10,10]\) by \([-10,10]\)
View solution