Problem 36
Question
Solve the nonlinear inequality. Express the solution using interval notation and graph the solution set. $$ (x-5)(x+4) \geq 0 $$
Step-by-Step Solution
Verified Answer
The solution is \([-4, -4] \cup [5, \infty)\).
1Step 1: Identify the Critical Points
Find the values of \( x \) that make the expression \((x-5)(x+4)\) equal to zero. These critical points are found by setting each factor equal to zero: \(x-5=0\) and \(x+4=0\). This gives the critical points \(x=5\) and \(x=-4\).
2Step 2: Determine the Test Intervals
The critical points \(x=-4\) and \(x=5\) divide the number line into three intervals: \((-\infty, -4)\), \([-4, 5)\), and \([5, \infty)\).
3Step 3: Test Each Interval
Choose a test point from each interval and substitute it into the inequality \((x-5)(x+4) \geq 0\) to check where the inequality holds. For example, test \(x = -5\) for \((-\infty, -4)\), \(x = 0\) for \([-4, 5)\), and \(x = 6\) for \([5, \infty)\).
4Step 4: Analyze the Test Results
For \((-\infty, -4)\): \(x = -5\,\rightarrow\, ((-5)-5)((-5)+4) = 25\geq0\), false. \([-4, 5]\): \(x = 0\,\rightarrow\, ((0)-5)((0)+4) = -20\geq0\), false. \([5, \infty)\): \(x = 6\,\rightarrow\, ((6)-5)((6)+4) = 10\geq0\), true.
5Step 5: Include Critical Points in the Analysis
Check the inequality at the critical points themselves. At \(x=-4\), \((-4-5)(-4+4)=0\geq0\), true. At \(x=5\), \((5-5)(5+4)=0\geq0\), true.
6Step 6: Interpret the Results and Write the Solution
From the testing, the solution set in interval notation where the inequality holds is \([-4, -4] \cup [5, \infty)\).
7Step 7: Graph the Solution Set
On the number line, shade the regions corresponding to \([-4, -4]\) and \([5, \infty)\). Use closed circles at \(-4\) and \(5\) to indicate these points are included in the solution.
Key Concepts
Critical Points in InequalitiesInterval NotationGraphical Representation of Inequalities
Critical Points in Inequalities
Critical points are essential in solving inequalities, especially nonlinear ones. These points are the values that turn the expression into zero. By finding these critical points, we can further analyze the inequality and its solution. In our exercise, the inequality is \[ (x-5)(x+4) \geq 0 \] To find the critical points, we set each factor equal to zero:
- For \( x-5=0 \), the critical point is \( x=5 \).
- For \( x+4=0 \), the critical point is \( x=-4 \).
Interval Notation
Interval notation is a convenient way to express a range of values that solve an inequality. It describes the set of numbers between two endpoints. The key is to indicate whether the endpoints are included or excluded. In our exercise, we've identified the solution intervals as follows:
- \([-4, -4]\) includes just the point \(-4\), meaning it's a part of the solution due to intersection at zero.
- \([5, \infty)\) includes the point \(5\) and extends to infinity, showing a continuous range starting from 5.
Graphical Representation of Inequalities
Graphical representation brings inequalities to life on the number line. This visual depiction helps in understanding where an inequality is satisfied. To graph our solution, we follow these steps:1. **Identify key points:** Draw a number line and mark the critical points \(-4\) and \(5\).2. **Shade the solution intervals:**
- Shade the point \(-4\) with a closed circle, indicating it's included in the solution set (-4≤ x ≤ -4).
- Shade the interval from \(5\) to the right towards infinity with a closed circle at \(5\).
Other exercises in this chapter
Problem 36
Evaluate the expression and write the result in the form a bi. $$ \frac{1}{1+i} $$
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\(23-48\) Solve the inequality. Express the answer using interval notation. $$ \left|\frac{x+1}{2}\right| \geq 4 $$
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Find all real solutions of the equation. $$ 2 x^{2}-8 x+4=0 $$
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\(5-60\) Find all real solutions of the equation. $$ \left(\frac{x+1}{x}\right)^{2}+4\left(\frac{x+1}{x}\right)+3=0 $$
View solution