Problem 36
Question
Solve the logarithmic equation and eliminate any extraneous solutions. If there are no solutions, so state. $$\ln x=1$$
Step-by-Step Solution
Verified Answer
The solution to the equation \(\ln x = 1\) is \(x = e\).
1Step 1: Rewrite in Exponential Form
Begin by rewriting the logarithmic equation in exponential form. The base of a natural logarithm is the constant \(e\). So the equation \(\ln x = 1\) becomes \(e^1 = x\).
2Step 2: Solve for x
With this equation \(e^1 = x\), solving for \(x\) becomes straightforward. The number \(e\) raised to the power of \(1\) is just \(e\), so therefore \(x = e\).
3Step 3: Check for Extraneous Solutions
Any solutions should be checked to ensure they do not violate the domain of the logarithmic function. In this case, since \(x = e\) and \(e > 0\), the solution is valid and there are no extraneous solutions.
Key Concepts
Exponential FormNatural LogarithmExtraneous Solutions
Exponential Form
When you encounter a logarithmic equation, such as \( \ln x = 1 \), a useful method for solving it is to rewrite it in exponential form. This approach stems from the basic properties of logarithms and exponents. The natural logarithm, denoted as \( \ln \), always has a base of \( e \), where \( e \approx 2.71828 \). Therefore, you can express \( \ln x = 1 \) exponentially as \( e^1 = x \). Essentially, this means "\( x \) is the number you get when you raise \( e \) to the power of 1".
By converting a logarithmic equation to exponential form, you make it easier to solve as it becomes a straightforward calculation. In this case, because \( e^1 \) simplifies directly to \( e \), we find \( x = e \). Using exponential form not only simplifies the equation but gives you a direct path to finding the solution.
By converting a logarithmic equation to exponential form, you make it easier to solve as it becomes a straightforward calculation. In this case, because \( e^1 \) simplifies directly to \( e \), we find \( x = e \). Using exponential form not only simplifies the equation but gives you a direct path to finding the solution.
Natural Logarithm
The natural logarithm, often written as \( \ln \), is a logarithm that uses the constant \( e \) as its base. The constant \( e \) is a crucial number in mathematics, specifically in calculus and complex systems. The natural log is useful for modeling growth processes like population growth or interest compounding
- \( \ln(e) = 1 \) because any base raised to the power of 1 is itself.
- Natural logs turn multiplication inside the log into addition outside: \( \ln(ab) = \ln a + \ln b \).
Extraneous Solutions
Extraneous solutions are results that come from solving an equation but don't actually satisfy the original equation. They typically arise when squaring both sides of an equation, taking even roots, or introducing division by an unknown that might be zero.
In logarithmic equations, it's important to check that any solution found is within the domain of the log function. For example, \( \ln x \) is only defined for \( x > 0 \). Therefore, when you solve \( \ln x = 1 \) and find \( x = e \), you need to ensure \( e > 0 \), which is true by definition as \( e \approx 2.71828 \). This confirms the solution is not extraneous.
Thus, checking for extraneous solutions guarantees that your calculations remain meaningful and correct within the problem's constraints. This step is crucial because it prevents errors and ensures the validity of your final answers in mathematical reasoning.
In logarithmic equations, it's important to check that any solution found is within the domain of the log function. For example, \( \ln x \) is only defined for \( x > 0 \). Therefore, when you solve \( \ln x = 1 \) and find \( x = e \), you need to ensure \( e > 0 \), which is true by definition as \( e \approx 2.71828 \). This confirms the solution is not extraneous.
Thus, checking for extraneous solutions guarantees that your calculations remain meaningful and correct within the problem's constraints. This step is crucial because it prevents errors and ensures the validity of your final answers in mathematical reasoning.
Other exercises in this chapter
Problem 35
Evaluate the expression to four decimal places using a calculator. $$2 \log 4$$
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Sketch the graph of each function. $$f(x)=2^{-x}-1$$
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The spread of the flu in an elementary school can be modeled by a logistic function. The number of children infected with the flu virus \(t\) days after the fir
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Find the inverse of the given function. Then graph the given function and its inverse on the same set of axes. $$g(x)=\frac{4}{3} x$$
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