Problem 36
Question
Solve. $$ \left(\frac{1}{9}\right)^{x}=27^{2-x} $$
Step-by-Step Solution
Verified Answer
The solution is \(x = 6\).
1Step 1: Convert to Same Base
The first step is to express both sides of the equation with the same base. Notice that 9 and 27 can be written as powers of 3: - 9 is equal to \(3^2\)- 27 is equal to \(3^3\)Now, rewrite the equation: \[\left(\frac{1}{9}\right)^{x} = 27^{2-x} \Rightarrow \left(3^{-2}\right)^x = (3^3)^{2-x}\].
2Step 2: Apply Power of a Power Property
Apply the property of exponents \((a^m)^n = a^{mn}\). This simplifies the equation to\[3^{-2x} = 3^{6-3x}\].
3Step 3: Remove the Base
Since the bases are the same, we can set the exponents equal to each other: \[-2x = 6 - 3x\].
4Step 4: Solve for x
Add \(3x\) to both sides:\[-2x + 3x = 6\]This simplifies to:\[x = 6\].
Key Concepts
Base ConversionPower of a PowerProperties of ExponentsSolving Equations
Base Conversion
Base conversion is a crucial technique when working with exponential equations. It involves rewriting numbers so that they share the same base, which allows us to compare and manipulate their exponents more easily. In our exercise, we were given an equation with numbers 9 and 27. By recognizing that both can be expressed as powers of 3 (since 9 is \(3^2\) and 27 is \(3^3\)), we converted the original equation into a form with a common base:
- Convert \(\frac{1}{9}\) to \((3^{-2})\) because \(9 = 3^2\), so \(\frac{1}{9} = 3^{-2}\).
- Convert \(27\) to \(3^3\) as already noted.
Power of a Power
The power of a power property is one of the basic rules of exponents, which states that when you raise an exponent to another power, you multiply the exponents together. This is beautifully expressed as \((a^m)^n = a^{mn}\). In our example, this rule is applied after converting to a common base:
- On the left side, \((3^{-2})^x = 3^{-2x}\).
- On the right side, \((3^3)^{2-x} = 3^{3(2-x)} = 3^{6-3x}\).
Properties of Exponents
Understanding the properties of exponents is essential when working with equations of this nature. Here are some key properties as applied in our problem:
- Power of a Product: \((ab)^m = a^m b^m\)
- Power of a Power: \((a^m)^n = a^{mn}\)
- Equal Bases: If \(a^m = a^n\), then \(m = n\)
Solving Equations
Solving exponential equations often involves a few strategic steps. Upon simplifying our equation so that both sides share a common base, we were left with the simple equation \(-2x = 6 - 3x\), using the property of equal exponents. Solving this linear equation involves straightforward algebraic manipulation:
- Add \(3x\) to both sides: \(-2x + 3x = 6\).
- Simplify the equation: \(x = 6\).
Other exercises in this chapter
Problem 36
Find \(f(x)\) and \(g(x)\) so that the given function \(h(x)=(f \circ g)(x)\). $$ h(x)=\frac{1}{x+10} $$
View solution Problem 36
Find the inverse of each one-to-one function. $$ f(x)=\frac{7}{2 x+4} $$
View solution Problem 36
Write each as a single logarithm. Assume that variables represent positive numbers. $$ 2 \log _{5} x+\frac{1}{3} \log _{5} x-3 \log _{5}(x+5) $$
View solution Problem 37
Use the formula \(A=P\left(1+\frac{r}{n}\right)^{n t}\) to solve these compound interest problems. Round to the nearest tenth. How long does it take for a \(\$
View solution