Problem 36
Question
Solve each proportion. $$\frac{a}{15}=\frac{12}{60}$$
Step-by-Step Solution
Verified Answer
The solution is \(a = 3\).
1Step 1: Understand the Proportion
The given proportion is \( \frac{a}{15} = \frac{12}{60} \). This means that the ratio of \(a\) to 15 is the same as the ratio of 12 to 60.
2Step 2: Simplify the Known Ratio
Simplify the ratio on the right side of the equation. The fraction \( \frac{12}{60} \) can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is 12. This gives \( \frac{12 \div 12}{60 \div 12} = \frac{1}{5} \).
3Step 3: Set the Proportions Equal
After simplifying, the proportion becomes \( \frac{a}{15} = \frac{1}{5} \). Now, these two fractions are set equal to each other again.
4Step 4: Solve for the Variable
To find \(a\), cross-multiply the fractions. This gives: \(a \times 5 = 1 \times 15\). Carry out the multiplication to get \(5a = 15\).
5Step 5: Isolate the Variable
Solve for \(a\) by dividing both sides of the equation \(5a = 15\) by 5, which gives: \(a = \frac{15}{5} = 3\).
Key Concepts
Simplifying RatiosCross-MultiplicationIsolate Variable
Simplifying Ratios
Simplifying ratios is a fundamental skill in solving proportions, and it can make complex problems easier to handle. Ratios are often presented as fractions, and simplifying them involves reducing the fraction to its lowest terms. This process requires identifying the greatest common divisor (GCD) of the numerator and the denominator.
- For example, consider the ratio \( \frac{12}{60} \). The GCD of 12 and 60 is 12.
- We simplify the fraction by dividing both numerator and denominator by 12: \( \frac{12 \div 12}{60 \div 12} = \frac{1}{5} \).
Cross-Multiplication
Cross-multiplication is a powerful tool for solving proportions. It allows you to find an unknown number in a proportion by converting the proportion into a simple equation. In cross-multiplication, you multiply diagonally across the equal sign.
- Consider the proportion \( \frac{a}{15} = \frac{1}{5} \).
- Cross-multiply by multiplying each pair of opposite numerators and denominators: \( a \times 5 = 1 \times 15 \).
- This creates the equation \( 5a = 15 \).
Isolate Variable
To solve for the unknown variable after using cross-multiplication, you need to isolate the variable. Isolating the variable means getting the variable alone on one side of the equation. In our equation \( 5a = 15 \), here's how you can isolate \( a \):
- Divide both sides of the equation by 5, the coefficient of \( a \).
- Thus, \( a = \frac{15}{5} \).
- Calculate the division to find \( a = 3 \).
Other exercises in this chapter
Problem 35
Sketch each triangle. If it is not possible to sketch the triangle, write not possible. acute scalene
View solution Problem 36
Solve each equation. Round to the nearest tenth, if necessary. $$y^{2}=22$$
View solution Problem 36
If \(c\) is the measure of the hypotenuse, find each missing measure. Round to the nearest tenth, if necessary. (lesson \(9-4\) ) $$a=?, b=27, c=82$$
View solution Problem 36
Order \(\sqrt{77},-8,-\sqrt{83}, 9,-10,-\sqrt{76}, \sqrt{65}\) from least to greatest.
View solution