Problem 36
Question
Solve each equation. Check your solutions. \(-9=-3|2 n+5|\)
Step-by-Step Solution
Verified Answer
The solutions are \(n = -1\) and \(n = -4\).
1Step 1: Understand the Absolute Value Equation
Given the equation \(-9 = -3|2n + 5|\). The absolute value equation is of the form \(-a = -b|c|\)."
2Step 2: Eliminate Negative Coefficient
Divide both sides by \(-3\) to get \(3 = |2n + 5|\). This isolates the absolute value.
3Step 3: Set Up Two Cases
Since \(|x| = a\) implies \(x = a\) or \(x = -a\), set up two equations: \(2n + 5 = 3\) and \(2n + 5 = -3\).
4Step 4: Solve Case 1
Solve the equation \(2n + 5 = 3\). Subtract \(5\) from both sides to obtain \(2n = -2\). Next, divide by \(2\) to get \(n = -1\).
5Step 5: Solve Case 2
Solve the equation \(2n + 5 = -3\). Subtract \(5\) from both sides to obtain \(2n = -8\). Divide by \(2\) to get \(n = -4\).
6Step 6: Check Solutions
Substitute \(n = -1\) back into the original equation: \(-9 = -3|2(-1) + 5| \rightarrow -9 = -3|3| \rightarrow -9 = -9\). This is correct. Next, substitute \(n = -4\): \(-9 = -3|2(-4) + 5| \rightarrow -9 = -3|-3| \rightarrow -9 = -9\). This is also correct.
Key Concepts
Solving EquationsChecking SolutionsAlgebraic Manipulation
Solving Equations
To solve an absolute value equation like \(-9 = -3|2n + 5|\), we first need to isolate the absolute value expression. The goal here is to simplify any coefficient outside the absolute value bars. This simplifies the equation greatly.
Start by dividing both sides by \(-3\). This action is crucial because it transforms the equation into a more manageable form: \(3 = |2n + 5|\). Once the absolute value is isolated, the next step involves creating two separate equations to solve. This is because \(|x| = a\) implies two potential solutions, \(x = a\) and \(x = -a\), due to the nature of absolute values.
Start by dividing both sides by \(-3\). This action is crucial because it transforms the equation into a more manageable form: \(3 = |2n + 5|\). Once the absolute value is isolated, the next step involves creating two separate equations to solve. This is because \(|x| = a\) implies two potential solutions, \(x = a\) and \(x = -a\), due to the nature of absolute values.
- Set up \(2n + 5 = 3\)
- Set up \(2n + 5 = -3\)
Checking Solutions
Whenever you solve an equation, especially involving absolute values, it's important to check your solutions by plugging them back into the original equation. This confirms correctness and checks any possible errors made during the solving steps.
To verify the solution for \(n = -1\), substitute it back: \(-9 = -3|2(-1) + 5|\). Substitute and simplify inside the absolute value to get \(-9 = -3|3|\), which holds true as \(-9 = -9\).
To verify the solution for \(n = -1\), substitute it back: \(-9 = -3|2(-1) + 5|\). Substitute and simplify inside the absolute value to get \(-9 = -3|3|\), which holds true as \(-9 = -9\).
- Next, check \(n = -4\). Substitute: \(-9 = -3|2(-4) + 5|\). Simplifying gives \(-9 = -3|-3|\). This also holds as \(-9 = -9\).
Algebraic Manipulation
Algebraic manipulation is the process of using various algebraic methods to simplify or solve an equation. In this context, it involves rearranging and simplifying the equation in several steps.
When dealing with absolute values like \(-9 = -3|2n + 5|\), algebraic manipulation begins by first isolating the absolute value expression through division. This turns \(-9 = -3|2n + 5|\) into \(3 = |2n + 5|\).
When dealing with absolute values like \(-9 = -3|2n + 5|\), algebraic manipulation begins by first isolating the absolute value expression through division. This turns \(-9 = -3|2n + 5|\) into \(3 = |2n + 5|\).
- Next, solve each equation derived from removing the absolute value by isolating \(n\). For \(2n + 5 = 3\), subtract \(5\) and divide by \(2\) gives \(n = -1\).
- For \(2n + 5 = -3\), subtract \(5\) and divide by \(2\) yields \(n = -4\).
Other exercises in this chapter
Problem 36
Simplify each expression. $$ 7 a+3 b-4 a-5 b $$
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Solve each equation. Check your solution. $$ -7(p+7)+3(p-4)=-17 $$
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Write an algebraic expression in which subtraction is performed before division, and the symbols ( ), [ ], or { } are not used.
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Solve each inequality. Then graph the solution set on a number line. \(6 d+3 \geq 5 d-2\)
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