Problem 36
Question
Solve each equation and check. \(5+7^{x}=6\)
Step-by-Step Solution
Verified Answer
The solution is \(x = 0\).
1Step 1: Isolate the Exponential Term
First, subtract 5 from both sides of the equation to isolate the exponential term. This gives us:\[7^{x} = 6 - 5\]Simplifying the right side, we find:\[7^{x} = 1\]
2Step 2: Solve the Exponential Equation
Since the equation is now \(7^{x} = 1\), we need to find the value of \(x\) that makes this true. Recall that any non-zero number raised to the power of 0 is 1. Thus:\[7^{x} = 7^{0}\]This implies that:\[x = 0\]
3Step 3: Check the Solution
Substitute \(x = 0\) back into the original equation to verify:\[5 + 7^{0} = 6\]Since \(7^{0} = 1\), the left-hand side becomes:\[5 + 1 = 6\]This simplifies to \(6 = 6\), confirming our solution is correct.
Key Concepts
Isolating the Exponential TermExponential EquationChecking Solutions
Isolating the Exponential Term
When faced with an exponential equation, the initial task is to isolate the exponential term, which is vital in simplifying the problem. For instance, in the equation we began with:
- We had: \(5 + 7^x = 6\)
- To isolate the exponential term \(7^x\), subtract 5 from both sides, leaving: \(7^x = 6 - 5\).
- The equation simplifies to \(7^x = 1\).
Exponential Equation
Once the exponential part of your equation is isolated, you encounter what is known as an exponential equation. In our context, we have the simplified equation:
- \(7^x = 1\).
- Since \(7^0 = 1\), it implies \(x = 0\) right away.
Checking Solutions
Even after solving an exponential equation, it's crucial to check your solution to ensure its accuracy. Substituting your result back into the original equation is a foolproof way to verify it. Here’s how we did it:
- Substitute \(x = 0\) back into the original equation: \(5 + 7^0 = 6\).
- Recognize that \(7^0 = 1\), so the equation becomes: \(5 + 1 = 6\).
- This simplifies to \(6 = 6\), confirming that our solution is indeed correct.
Other exercises in this chapter
Problem 36
In \(35-63,\) write each expression with only positive exponents and express the answer in simplest form. The variables are not equal to zero. $$ a^{-6} $$
View solution Problem 36
In \(3-37,\) express each power as a rational number in simplest form. $$ \left(2.3 \times 10^{-1}\right)\left(5.2 \times 10^{-3}\right) $$
View solution Problem 37
In \(35-63,\) write each expression with only positive exponents and express the answer in simplest form. The variables are not equal to zero. $$ y^{-5} $$
View solution Problem 37
In \(3-37,\) express each power as a rational number in simplest form. $$ \frac{\left(2(3)^{2}+\frac{1}{3^{-2}}\right)^{\frac{2}{3}}}{6\left(2+\frac{1}{4}\right
View solution