Problem 36
Question
Solve each equation. \(|8-5 x|-8=10\)
Step-by-Step Solution
Verified Answer
The solutions are \(x = -2\) and \(x = \frac{26}{5}\).
1Step 1: Isolate the Absolute Value
First, add 8 to both sides of the equation to isolate the absolute value expression:\[ |8 - 5x| - 8 + 8 = 10 + 8 \]This simplifies to:\[ |8 - 5x| = 18 \]
2Step 2: Set Up Two Scenarios
Since the absolute value of an expression can be either the expression itself or the negative of the expression, set up two separate equations to consider both possibilities:1. \( 8 - 5x = 18 \)2. \( 8 - 5x = -18 \)
3Step 3: Solve for x (First Scenario)
Solve the equation \(8 - 5x = 18\):Subtract 8 from both sides:\[ 8 - 8 - 5x = 18 - 8 \]This simplifies to:\[ -5x = 10 \]Divide both sides by -5:\[ x = -2 \]
4Step 4: Solve for x (Second Scenario)
Solve the equation \(8 - 5x = -18\):Subtract 8 from both sides:\[ 8 - 8 - 5x = -18 - 8 \]This simplifies to:\[ -5x = -26 \]Divide both sides by -5:\[ x = \frac{26}{5} \]
5Step 5: Check Solutions
Substitute \(x = -2\) back into the original equation:\[ |8 - 5(-2)| - 8 = 10 \]Calculate:\[ |8 + 10| - 8 = |18| - 8 = 10 \]True. Now check \(x = \frac{26}{5}\):\[ \left|8 - 5 \left(\frac{26}{5}\right)\right| - 8 = 10 \]Calculate:\[ |8 - 26| - 8 = |-18| - 8 = 10 \]Both solutions satisfy the original equation.
Key Concepts
Equation SolvingAlgebraic ConceptsStep-by-Step Solutions
Equation Solving
Equation solving is at the heart of algebra and involves finding the unknown variable that satisfies the given equation. In the case of an equation with an absolute value, like \(|8-5x|-8=10\), we need to first isolate the absolute value portion. Equation solving requires a strategic approach, and you often must perform operations such as addition or subtraction to move terms around, ensuring the expression containing the absolute value stands alone on one side of the equation.
This can be done by:
This systematic approach ensures clarity and accuracy when determining the values of \(x\) that satisfy the equation.
This can be done by:
- Adding 8 to both sides to remove it from the left side, leaving \(|8 - 5x| = 18\).
This systematic approach ensures clarity and accuracy when determining the values of \(x\) that satisfy the equation.
Algebraic Concepts
Algebraic concepts are crucial in solving absolute value equations. The first concept is the absolute value itself, which represents the distance of a number from zero on a number line. It is always non-negative. In our equation, \(|8-5x|-8=10\), the absolute value \(|8-5x|\) must first be isolated so it can be accurately evaluated.
Understanding absolute values:
Such algebraic concepts are built step-by-step, helping to identify the nature of solutions and ensuring all possibilities are explored thoroughly.
Understanding absolute values:
- The absolute value is represented as \(|a|\) and can be understood as:
- \(a\) if \(a\geq0\)
- \(-a\) if \(a<0\)
Such algebraic concepts are built step-by-step, helping to identify the nature of solutions and ensuring all possibilities are explored thoroughly.
Step-by-Step Solutions
Step-by-step solutions are an effective way to tackle complex equations by breaking them down into manageable parts. Solving the given absolute value equation involves a clear sequence of steps to ensure each aspect of the solution is understandable.
The first step is to isolate the absolute value expression, ensuring we deal with it cleanly. Once isolated, set up two scenarios to handle the nature of absolute values:
After solving each equation:
Step-by-step solutions shine as they break a problem down, making complex problems approachable and ensuring reliable results through systematic calculation.
The first step is to isolate the absolute value expression, ensuring we deal with it cleanly. Once isolated, set up two scenarios to handle the nature of absolute values:
- First scenario: \(8 - 5x = 18\)
- Second scenario: \(8 - 5x = -18\)
After solving each equation:
- \(x = -2\) for the first scenario
- \(x = \frac{26}{5}\) for the second scenario
Step-by-step solutions shine as they break a problem down, making complex problems approachable and ensuring reliable results through systematic calculation.
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