Problem 36
Question
Sketch the graph of the function. Label the coordinates of the vertex. $$ y=-2 x^{2} $$
Step-by-Step Solution
Verified Answer
The graph of the function \(y = -2x^2\) is a downward opening parabola with the vertex at the origin (0,0).
1Step 1: Identify the function and its form
The given function \(y = -2x^2\) is a quadratic function in the form \(y=ax^2\), where \(a\) is the coefficient of the \(x^2\), in this case \(a = -2\)
2Step 2: Identify the vertex
For quadratic function in the form of \(y=ax^2\), the vertex is always at the origin (0,0). So, the vertex of this function is (0,0)
3Step 3: Sketch the graph
Now we graph the function. As a is less than 0, the parabola opens downward. The vertex is at the origin (0,0), and as x moves away from 0 in either direction, y becomes more negative since we multiply x^2 (which is always positive) by -2.
Key Concepts
Graphing ParabolasVertex of a ParabolaDownward Opening Parabola
Graphing Parabolas
Understanding how to graph a parabola can seem challenging at first, but it’s quite simple when broken down into steps. Parabolas are the graphs of quadratic functions, which generally take the form \( y = ax^2 + bx + c \). For our specific function, \( y = -2x^2 \), it's in its simplest form, \( y = ax^2 \), where only the \( ax^2 \) component is present.
To graph a parabola:
To graph a parabola:
- Identify the vertex (in the simplest form \( y = ax^2 \), it's at the origin (0,0) unless shifted).
- Determine the direction it opens; this depends on the sign of \( a \): a positive \( a \) opens upwards, while a negative \( a \) opens downwards.
- Plot the vertex and use additional points to map out the curve of the parabola. These can include easy-to-calculate points for small values of \( x \).
Vertex of a Parabola
The vertex of a parabola is one of its most defining features. It is essentially the peak or the lowest point on the graph, depending on whether the parabola opens upwards or downwards. In quadratic functions presented as \( y = ax^2 \), the vertex lies at the origin (0,0).
Here's a breakdown of the vertex:
Here's a breakdown of the vertex:
- It represents the maximum or minimum value of the function.
- In \( y = ax^2 + bx + c \), you can find it using the formula \( x = -\frac{b}{2a} \) when both \( b \) and \( c \) are present.
- For \( y = -2x^2 \), the vertex is at (0,0), as \( b \) and \( c \) are absent, simplifying calculations.
Downward Opening Parabola
When working with parabolas, it is important to determine which way they open. For our function \( y = -2x^2 \), the parabola opens downward. This behavior is dictated by the coefficient \( a \), which is '-2' in this case. Here's how you can conclude this and what it means for the graph:
Signs and implications:
Signs and implications:
- The negative \( a \) value indicates that the parabola opens downwards. If \( a \) were positive, it would open upwards.
- This means the vertex is the highest point on the graph, as opposed to the lowest in upward-opening parabolas.
- As you move away from the vertex along the \( x \)-axis, the \( y \)-values decrease.
Other exercises in this chapter
Problem 35
Solve the equation or write no real solution. Write the solutions as integers if possible. Otherwise, write them as radical expressions. $$ 3 x^{2}=6 $$
View solution Problem 36
Sketch the graph of the inequality. $$ y \leq-x^{2}+3 x+4 $$
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Solve the equation algebraically. Check your solutions by graphing. $$4 x^{2}=16$$
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Find the value of \(b^{2}\)- 4ac for the equation. $$-8 m^{2}-6 m+3=0$$
View solution