Problem 36
Question
Simplify each side of the following equations before applying the addition property. $$7 a-6-6 a=-3+1$$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(a = 4\).
1Step 1: Simplify Both Sides
First, we simplify both sides of the equation. Start with the left side, which is \(7a - 6 - 6a\). We combine like terms by subtracting \(6a\) from \(7a\), resulting in \(a - 6\). The equation now becomes: \(a - 6 = -3 + 1\).
2Step 2: Simplify the Right Side
Next, simplify the right side of the equation, which is \(-3 + 1\), adding these numbers gives us \(-2\). The equation now reads \(a - 6 = -2\).
3Step 3: Apply the Addition Property
To solve for \(a\), we use the addition property of equality to isolate \(a\). Add 6 to both sides of the equation to eliminate the \(-6\) on the left side. This gives us \(a - 6 + 6 = -2 + 6\), simplifying to \(a = 4\).
Key Concepts
Addition PropertyCombining Like TermsPrealgebra
Addition Property
The addition property of equality is a fundamental principle used to solve equations. It states that if you add the same number to both sides of an equation, the equality remains unchanged. This property helps to simplify equations and find the value of unknown variables.
Let's think of it like a balanced scale. Imagine you have a balance scale with equal weights on both sides. If you add or remove the same amount from each side, the scale remains balanced. Similarly, in an equation, when you add or subtract the same value on both sides, the equation remains true.
In our exercise, we used this property in Step 3. We had the equation, \(a - 6 = -2\). To isolate \(a\), we added 6 to both sides, like this: \(a - 6 + 6 = -2 + 6\). This simplified to \(a = 4\), giving us the solution. Next time you encounter an equation, remember that you can freely add or subtract the same number to both sides—this powerful tool keeps the equation balanced and helps you solve for the variable.
Let's think of it like a balanced scale. Imagine you have a balance scale with equal weights on both sides. If you add or remove the same amount from each side, the scale remains balanced. Similarly, in an equation, when you add or subtract the same value on both sides, the equation remains true.
In our exercise, we used this property in Step 3. We had the equation, \(a - 6 = -2\). To isolate \(a\), we added 6 to both sides, like this: \(a - 6 + 6 = -2 + 6\). This simplified to \(a = 4\), giving us the solution. Next time you encounter an equation, remember that you can freely add or subtract the same number to both sides—this powerful tool keeps the equation balanced and helps you solve for the variable.
Combining Like Terms
Combining like terms is a method used to simplify equations or expressions by merging terms that contain the same variable raised to the same power. This step makes mathematical problems easier to handle, especially when dealing with complex equations.
For instance, in Step 1 of our example, we simplified the left side of the equation, \(7a - 6 - 6a\), by combining like terms. Both \(7a\) and \(-6a\) belong to the same variable \(a\). By subtracting \(6a\) from \(7a\), we simplified it to \(a\). Thus, the left side of the equation became \(a - 6\).
Here are a few helpful tips when combining like terms:
For instance, in Step 1 of our example, we simplified the left side of the equation, \(7a - 6 - 6a\), by combining like terms. Both \(7a\) and \(-6a\) belong to the same variable \(a\). By subtracting \(6a\) from \(7a\), we simplified it to \(a\). Thus, the left side of the equation became \(a - 6\).
Here are a few helpful tips when combining like terms:
- Identify terms with the same variable and the same exponent.
- Add or subtract the coefficients of these terms.
- Maintain the variable and its exponent in the final term.
Prealgebra
Prealgebra serves as an introduction to the basic concepts and skills needed for algebra. It lays the foundation for solving equations and understanding more advanced math topics. Prealgebra involves operations with numbers, basic geometry, understanding integers, fractions, and beginning to work with variables and simple equations.
In our example, the equation given is a perfect exercise for practicing prealgebra skills. You get to work with variables, simplify expressions, and use properties such as the addition property of equality to solve equations. Each of these steps is a crucial part of developing the mathematical reasoning prepared in prealgebra.
Transitioning into algebra is easier with a solid grasp of prealgebra concepts. You build the confidence to approach problems methodically. Remember that making mistakes and learning from them is part of the learning process. By practicing exercises like the one we've solved, your skills in working with variables and simplifying equations will grow, preparing you for more complex math tasks in the future.
In our example, the equation given is a perfect exercise for practicing prealgebra skills. You get to work with variables, simplify expressions, and use properties such as the addition property of equality to solve equations. Each of these steps is a crucial part of developing the mathematical reasoning prepared in prealgebra.
Transitioning into algebra is easier with a solid grasp of prealgebra concepts. You build the confidence to approach problems methodically. Remember that making mistakes and learning from them is part of the learning process. By practicing exercises like the one we've solved, your skills in working with variables and simplifying equations will grow, preparing you for more complex math tasks in the future.
Other exercises in this chapter
Problem 36
Indicate which of the given ordered pairs are solutions for each equation. $$y=-3 x \quad(0,0),(-3,0),(-1,3)$$
View solution Problem 36
As you know, the volume \(V\) enclosed by a rectangular solid with length \(I,\) width \(w,\) and height \(h\) is \(V=I \cdot w \cdot h .\) Find \(V\) if: \(I=1
View solution Problem 36
Stacey is selling tickets to the school play. The tickets are \(\$ 6\) for adults and \(\$ 4\) for children. She sells twice as many adult tickets as children's
View solution Problem 36
Using the addition property of equality first, solve each of the following equations. $$-12 a+1=-47$$
View solution