Problem 36
Question
Name the curve with the given polar equation. If it is a conic, give its eccentricity. Sketch the graph. $$ r=\frac{4}{3 \cos (\theta-\pi / 3)} $$
Step-by-Step Solution
Verified Answer
The curve is a hyperbola with eccentricity \( e = \frac{4}{3} \).
1Step 1: Identify the Type of Curve
The given polar equation is \[ r = \frac{4}{3 \cos(\theta - \pi/3)} \]This fits the standard form for polar equations of conics:\[ r = \frac{ed}{1 + e\cos(\theta - \theta_0)} \]Here, the equation suggests a direct relation to this form, indicating a conic centered at an offset angle \(\theta = \pi/3 \) with cosine as the trigonometric function involved. This implies a directrix related to this orientation.
2Step 2: Determine Eccentricity and Conic Type
In the general polar equation form for a conic, \[ r = \frac{ed}{1 + e \cos(\theta - \theta_0)} \]where "e" is the eccentricity. By comparing with the given equation, we note:\[ e \times 3 = 4 \]Thus, the eccentricity \( e \) can be calculated as \( e = \frac{4}{3} \). Since the eccentricity \( e > 1 \), this conic is a hyperbola.
3Step 3: Understand Conic Graphing
A hyperbola is characterized by two separate curves that mirror each other, originating from points (foci) that are equidistant from a center. The polar equation specifies angular orientation with \( \theta - \pi/3 \), which directs the hyperbola across that axis line.
4Step 4: Sketch the Graph
Start by plotting the line associated with \( \theta = \pi/3 \) in a polar grid. Due to the hyperbolic nature and given the equation, the arms of the hyperbola will open away from this line. Since the equation format indicates a hyperbola, expect it to extend into two distinct branches equidistantly reflecting from the focus at the given orientation.
5Step 5: Final Verification
Review the calculations and improvements to ensure the eccentricity is pertinent to hyperbolas \( e = \frac{4}{3} \), ensuring accuracy. The outcome aligns with the criteria defining a hyperbolic conic in polar form.
Key Concepts
EccentricityConic SectionsHyperbola
Eccentricity
Eccentricity is a fundamental concept in the study of conic sections and helps classify the type of conic section that a curve represents. In the context of polar equations, eccentricity, denoted by \( e \), measures how much a conic section deviates from being circular. It is a constant value that determines the shape of the conic:
- If \( e = 0 \), the conic is a circle.
- If \( 0 < e < 1 \), it's an ellipse.
- If \( e = 1 \), the conic is a parabola.
- If \( e > 1 \), the conic is a hyperbola.
Conic Sections
Conic sections are curves obtained by intersecting a plane with a double-napped cone. These sections create different types of curves depending on the angle of the intersection. The main types include:
- Circle: If the plane intersects the cone parallel to its base, we obtain a circle.
- Ellipse: When the intersection is at an angle but does not pass through the base, the result is an ellipse.
- Parabola: A parabola is formed when the plane is parallel to the slant height of the cone.
- Hyperbola: If the plane cuts through both halves of the cone, creating two separate curves, a hyperbola is formed.
Hyperbola
A hyperbola is one of the conic sections that occurs when a plane intersects both halves of a double cone. Like other conic sections, hyperbolas have distinct features:
- Foci: Two distinct points on the interior of each curve from which distances are measured to define the hyperbola.
- Asymptotes: Lines that the hyperbola approaches but never meets as it extends infinitely.
- Symmetry: Hyperbolas are symmetric about their center, splitting into two mirror-image branches.
Other exercises in this chapter
Problem 35
Find the equation of the tangent line to the given curve at the given point. $$ \frac{x^{2}}{27}+\frac{y^{2}}{9}=1 \text { at }(3, \sqrt{6}) $$
View solution Problem 36
Sketch the given curves and find their points of intersection. $$ r=5, r=\frac{5}{1-2 \cos \theta} $$
View solution Problem 36
, find the length of the parametric curve defined over the given interval. $$ x=2-t, y=2 t-3 ;-3 \leq t \leq 3 $$
View solution Problem 36
Find the equation of the tangent line to the given curve at the given point. $$ \frac{x^{2}}{24}+\frac{y^{2}}{16}=1 \text { at }(3 \sqrt{2},-2) $$
View solution