Problem 36
Question
$$ \left|\frac{c^{2}-c}{\cos c}\right| ;\left[0, \frac{\pi}{4}\right] $$
Step-by-Step Solution
Verified Answer
The expression is zero at \( c = 0 \), positive for \( 0 < c \leq \frac{\pi}{4} \).
1Step 1: Understand the Expression
The given mathematical expression is \( \left| \frac{c^{2}-c}{\cos c} \right| \). It involves a real number \( c \) and we are looking for its values in the interval \( \left[ 0, \frac{\pi}{4} \right] \). The expression inside the absolute values can change sign, which we will explore in subsequent steps.
2Step 2: Determine where \( \cos c \) equals zero
First, we need to ensure \( \cos c eq 0 \) because division by zero is undefined. Within the interval \( \left[ 0, \frac{\pi}{4} \right] \), the cosine function does not equal zero. Thus, the expression is defined for this entire interval.
3Step 3: Analyze the Quadratic Expression
The quadratic expression in the numerator is \( c^{2} - c \). For values where \( c^{2} - c = 0 \), we solve for \( c \):\[ c(c-1) = 0 \]Thus, \( c = 0 \) or \( c = 1 \). Only \( c = 0 \) lies within the interval \( \left[ 0, \frac{\pi}{4} \right] \).
4Step 4: Evaluate and Interpret Solutions
The expression becomes zero when \( c = 0 \). For other values in the interval \( \left(0, \frac{\pi}{4}\right] \), we need to calculate \( \frac{c^{2} - c}{\cos c} \) and apply absolute value. Calculations at different points in the interval confirm that we need to consider the sign of \( c^{2} - c \): negative leads to a positive absolute value.
5Step 5: Consider Properties Across the Interval
Since \( c^2 < c \) for values \( c \in (0, 1) \), the fraction within the absolute value is negative, leading to a positive absolute value of the entire expression. For \( c \geq 1 \), the expression is positive, hence its absolute value equals the expression itself. However, these values do not lie inside \([0, \frac{\pi}{4}]\) since \( \frac{\pi}{4} < 1 \).
Key Concepts
Absolute ValueQuadratic ExpressionsTrigonometric FunctionsInequalities
Absolute Value
Absolute value is a fundamental concept in mathematics, often symbolized by two vertical bars (| |) surrounding a number or expression, such as \( |x| \). It represents the distance of a number from zero on the number line, which means it is always non-negative.
- The absolute value of a positive number is the number itself, \( |5| = 5 \).
- The absolute value of a negative number is its opposite, \( |-3| = 3 \).
- If the number is zero, its absolute value is also zero, \( |0| = 0 \).
Quadratic Expressions
Quadratic expressions are polynomial expressions of degree two, generally represented as \( ax^2 + bx + c \). In the exercise, the quadratic expression \( c^2 - c \) forms the numerator of the given fraction.
- Quadratics can take various forms when graphed, typically as a parabola.
- The zeros of the quadratic \( c^2 - c \) can be found by solving the equation \( c(c-1) = 0 \).
- This results in the solutions \( c = 0 \) and \( c = 1 \).
Trigonometric Functions
Trigonometric functions like sine and cosine are periodic functions that relate angles to sides in right triangles or unit circles. In this exercise, \( \cos c \) is crucial as it's in the denominator of the fraction, \( \frac{c^2 - c}{\cos c} \).
- \( \cos c \) represents the x-coordinate on the unit circle as \( c \) varies as an angle.
- It is crucial to ensure that \( \cos c eq 0 \) because division by zero is undefined.
- Within the interval \( [0, \frac{\pi}{4}] \), \( \cos c \) remains positive and does not reach zero.
Inequalities
Inequalities help determine the sign of an expression across a given range. In this exercise, inequalities are used to assess when the quadratic expression \( c^2 - c \) changes sign.
- The inequality \( c^2 - c < 0 \) holds true for \( c \in (0, 1) \).
- For this interval, the fraction \( \frac{c^2 - c}{\cos c} \) is negative, which the absolute value converts to positive.
- Beyond this interval, \( \c >= 1 \), the expression becomes positive, although it isn't relevant since \( \frac{\pi}{4} < 1 \).
Other exercises in this chapter
Problem 35
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