Problem 36
Question
Involve equations with multiple angles. Solve each equation on the interval \([0,2 \pi)\) $$ \cot \frac{3 \theta}{2}=-\sqrt{3} $$
Step-by-Step Solution
Verified Answer
Solutions are \(\theta = \frac{4k\pi}{3}\), \(\theta = \frac{2\pi}{3} + \frac{4k\pi}{3}\), \(\theta = \frac{10\pi}{9} + \frac{4k\pi}{3}\), and \(\theta = \frac{4\pi}{3} + \frac{4k\pi}{3}\) for some integer \(k\), and where the value of \(\theta\) is in the interval [0, 2\(\pi\)).
1Step 1: Identify the corresponding angle
First, identify the positive angle whose cotangent is \(\sqrt{3}\). Using the trigonometric ratios, you can determine that \(\cot \frac{\pi}{3} = \sqrt{3}\). So, \(\cot \alpha = \sqrt{3}\) where \(\alpha = \frac{\pi}{3}\).
2Step 2: Find the cotangent's negative values
The cotangent is negative in the second and fourth quadrants. Therefore, the negative solutions for cotangent are \(\alpha_1 = \pi - \frac{\pi}{3} = \frac{2\pi}{3}\) and \(\alpha_2 = 2\pi - \frac{\pi}{3} = \frac{5\pi}{3}\) where \(0 \leq \alpha_1 < 2\pi\). The set of all solutions is \(\frac{3\theta}{2} = \alpha_1 + 2k\pi\) and \(\frac{3\theta}{2} = \alpha_2 + 2l\pi\) where \(k\) and \(l\) are integers.
3Step 3: Solve for all possible values of \(\theta\)
Now solving for \(\theta\) we get the two following set of solutions: \(\theta = \frac{2\alpha_1}{3} + \frac{4k\pi}{3}\) and \(\theta = \frac{2\alpha_2}{3} + \frac{4l\pi}{3}\). Substituting the values of \(\alpha_1\) and \(\alpha_2\) and simplifying, we get the set of solutions on the interval [0, 2\(\pi\)) is \(\theta = \frac{4k\pi}{3}\), \(\frac{2\pi}{3} + \frac{4k\pi}{3}\), \(\frac{10\pi}{9} + \frac{4k\pi}{3}\) and \(\frac{4\pi}{3} + \frac{4k\pi}{3}\) where \(k\) is an integer and \(0 \leq \theta < 2\pi\).
Key Concepts
Understanding the Cotangent FunctionFinding Angle SolutionsNavigating Multiple Angle EquationsExploring Trigonometric Ratios
Understanding the Cotangent Function
The cotangent of an angle in trigonometry is a fundamental concept that often gets overlooked. It's the reciprocal of the tangent function. In mathematical terms, the cotangent of an angle \( \theta \) is defined as \( \cot \theta = \frac{1}{\tan \theta} \) or equivalently \( \cot \theta = \frac{\cos \theta}{\sin \theta} \).
This means the cotangent tells us the ratio between the adjacent side and the opposite side of a right-angled triangle when considering the given angle in that triangle.
This means the cotangent tells us the ratio between the adjacent side and the opposite side of a right-angled triangle when considering the given angle in that triangle.
- When solving trigonometric equations with cotangent, understanding its relationship with other ratios like sine and cosine is crucial.
- The value of \( \cot \theta \) can be positive or negative, depending on the quadrant in which the angle \( \theta \) is situated.
Finding Angle Solutions
In trigonometric equations, finding angle solutions involves determining all possible angles that satisfy the equation within a given range—in this case, \([0, 2\pi)\).
When you see an equation like \( \cot \frac{3\theta}{2} = -\sqrt{3} \), finding solutions depends heavily on understanding where the cotangent function takes specific values.
When you see an equation like \( \cot \frac{3\theta}{2} = -\sqrt{3} \), finding solutions depends heavily on understanding where the cotangent function takes specific values.
- First, we need to identify reference angles from known cotangent values. For example, \( \cot \frac{\pi}{3} = \sqrt{3} \).
- Next, we assess in which quadrants the cotangent is negative, since the original problem involves a negative cotangent value.
Navigating Multiple Angle Equations
When dealing with multiple angle equations like \( \cot \frac{3\theta}{2} = -\sqrt{3} \), the process involves an extra step of considering the multiple factor before solving for \( \theta \).
- The given equation is of the form \( \cot(n\theta) = a \). Here, \( n = \frac{3}{2} \).
- Once you find the reference angles (\( \alpha_1 \) and \( \alpha_2 \)), you need to adjust for the angle's multiplication by solving \( \frac{3\theta}{2} = \alpha + 2k\pi \).
Exploring Trigonometric Ratios
Trigonometric ratios are the backbone of solving equations like \( \cot \frac{3\theta}{2} = -\sqrt{3} \). These ratios—sine, cosine, tangent, cotangent, secant, and cosecant—define the relationship between the sides and angles of triangles.
- Each ratio has specific values for standard angles such as \( 0, \pi/6, \pi/4, \pi/3, \pi/2, \) that allow us to deduce the solutions to trigonometric equations.
- Understanding trigonometric identities and reciprocal identities (e.g., \( \cot \theta = \frac{1}{\tan \theta} \)) enriches our ability to manipulate and solve equations.
Other exercises in this chapter
Problem 35
Verify each identity. \(\frac{\sec x-\csc x}{\sec x+\csc x}=\frac{\tan x-1}{\tan x+1}\)
View solution Problem 36
Use one or more of the six sum and difference identities to solve Exercises \(13-54\) Verify each identity. $$ \cos (\pi-x)=-\cos x $$
View solution Problem 36
Use the power-reducing formulas to rewrite each expression as an equivalent expression that does not contain powers of trigonometric functions greater than 1. $
View solution Problem 36
Verify each identity. \(\frac{\csc x-\sec x}{\csc x+\sec x}=\frac{\cot x-1}{\cot x+1}\)
View solution