Problem 36
Question
In the following exercises, solve each number word problem. One number is eight more than another. If their sum is increased by \(17,\) the result is \(95 .\) Find the numbers.
Step-by-Step Solution
Verified Answer
The numbers are 35 and 43.
1Step 1 - Define Variables
Let's define the two unknown numbers. Let the first number be denoted as \(x\). Since one number is eight more than another, the second number will be \(x + 8\).
2Step 2 - Set Up the Equation
According to the problem, the sum of these two numbers increased by 17 equals 95. Therefore, we set up the equation: \(x + (x + 8) + 17 = 95\)
3Step 3 - Simplify the Equation
Combine like terms in the equation: \(x + x + 8 + 17 = 95\) This simplifies to: \(2x + 25 = 95\)
4Step 4 - Isolate the Variable
Subtract 25 from both sides of the equation to isolate the term with the variable: \(2x = 70\)
5Step 5 - Solve for \(x\)
Divide both sides by 2 to find the value of \(x\): \(x = 35\)
6Step 6 - Find the Second Number
The second number is eight more than the first number, so: \(x + 8 = 35 + 8 = 43\)
7Step 7 - Verify the Solution
Check the solution by verifying the conditions of the problem. The sum of the two numbers is \(35 + 43 = 78\). Increasing this sum by 17 gives: \(78 + 17 = 95\). Therefore, the solution is correct.
Key Concepts
algebraic equationvariable isolationproblem-solving stepsverification of solutions
algebraic equation
An algebraic equation is a mathematical statement that shows the equality between two expressions. In this number word problem, we used an algebraic equation to represent the relationship between two unknown numbers. By translating the word problem into a mathematical form, we created the equation:
- \( x + (x + 8) + 17 = 95 \)
variable isolation
Variable isolation is the process of rearranging an equation to get the unknown variable by itself on one side. This is one of the essential steps in solving algebraic equations. In our example, we work through these steps:
- First, we simplified the equation: \( x + x + 8 + 17 = 95 \) to \( 2x + 25 = 95 \)
- Next, we isolated the term with the variable: \( 2x = 70 \) by subtracting 25 from both sides.
- Finally, we solved for \( x \) by dividing both sides by 2: \( x = 35 \).
problem-solving steps
Solving algebraic word problems involves a series of logical steps. These steps help break down the problem into manageable parts, making finding the solution easier. Let's review our steps:
- **Define Variables**: Start by letting one unknown number be \( x \), and the second number be \( x + 8 \), based on the problem statement.
- **Set Up the Equation**: Translate the word problem into an algebraic equation: \( x + (x + 8) + 17 = 95 \).
- **Simplify the Equation**: Combine like terms to make the equation simpler: \( 2x + 25 = 95 \).
- **Isolate the Variable**: Rearrange the equation to solve for \( x \): \( 2x = 70 \), and then \( x = 35 \).
- **Find the Second Number**: Use the value of \( x \) to find the second number: \( 35 + 8 = 43 \).
verification of solutions
Verifying your solutions is a crucial last step in problem-solving. It ensures accuracy and builds confidence in your solution. Let's verify our solution:
- We found the numbers to be 35 and 43.
- Sum of these numbers: \( 35 + 43 = 78 \).
- Increasing the sum by 17 should give us 95: \( 78 + 17 = 95 \).
Other exercises in this chapter
Problem 34
In the following exercises, solve each number word problem. One number is 11 less than another. If their sum is increased by eight, the result is 71 . Find the
View solution Problem 35
In the following exercises, solve each number word problem. One number is five more than another. If their sum is increased by nine, the result is 60 . Find the
View solution Problem 37
In the following exercises, solve each number word problem. One number is one more than twice another. Their sum is -5 . Find the numbers.
View solution Problem 38
In the following exercises, solve each number word problem. One number is six more than five times another. Their sum is six. Find the numbers.
View solution