Problem 36
Question
In Exercises \(29-44\), perform the indicated operations and write the result in standard form. $$ (-2+\sqrt{-11})^{2} $$
Step-by-Step Solution
Verified Answer
So, the complex number \((-2+\sqrt{-11})^{2}\) in standard form is \(-7 - 4i\sqrt{11}\)
1Step 1: Convert the Number Under Root to Complex Number
Replace \(\sqrt{-11}\) with \(i\sqrt{11}\). So, \(-2+ \sqrt{-11}\) becomes \(-2+ i\sqrt{11}\).
2Step 2: Apply the Exponent
Now, square \(-2 + i\sqrt{11}\) to get \(( -2 + i\sqrt{11})^2 = (-2)^2 + 2*(-2 * i\sqrt{11}) + (i\sqrt{11})^2\)
3Step 3: Simplification
Evaluate and simplify each term to get \(4 -4i\sqrt{11} - 11\)
4Step 4: Further Simplification
By combining the real parts, \(4 - 11\) is simplified to get \(-7 -4i\sqrt{11}\)
Key Concepts
Imaginary UnitStandard FormAlgebraic OperationsComplex Conjugate
Imaginary Unit
The imaginary unit, denoted as \(i\), is a fundamental concept in the world of complex numbers. It is defined as the square root of \(-1\). In mathematical terms, this means \(i^2 = -1\). The introduction of the imaginary unit allows us to extend the real number system to include solutions to equations that have no solutions in the realm of real numbers, such as \(x^2 + 1 = 0\).
Without \(i\), the square root of negative numbers would be undefined in real numbers. Here's a simple explanation of how \(i\) works:
Without \(i\), the square root of negative numbers would be undefined in real numbers. Here's a simple explanation of how \(i\) works:
- If \(x^2 = -1\), then \(x = i\).
- Any negative number's square root can be expressed as a multiple of \(i\). For example, \(\sqrt{-11}\) can be rewritten as \(i\sqrt{11}\).
Standard Form
The standard form of a complex number is a way of expressing them as \(a + bi\), where \(a\) and \(b\) are real numbers.\(a\) is the real part and \(bi\) is the imaginary part. This form makes complex numbers easy to understand and useful for various calculations.
For example, if we have a complex number like \(-2 + i\sqrt{11}\), it is expressed in standard form with the real part being \(-2\) and the imaginary part being \(i\sqrt{11}\).
For example, if we have a complex number like \(-2 + i\sqrt{11}\), it is expressed in standard form with the real part being \(-2\) and the imaginary part being \(i\sqrt{11}\).
- It's simpler to perform operations like addition or subtraction between complex numbers in this form.
- In algebra, expressing numbers this way allows us to clearly identify and differentiate between the real and imaginary components.
Algebraic Operations
Algebraic operations with complex numbers follow some rules that are similar to those for real numbers but also include considerations for the imaginary unit \(i\). Here's how they work:
- Addition and Subtraction: Add or subtract the real parts and the imaginary parts separately. For example, \((a + bi) + (c + di) = (a+c) + (b+d)i\).
- Multiplication: Use the distributive property to multiply complex numbers. Remember, \(i^2 = -1\). For example, \((a + bi)(c + di) = ac + adi + bci + bdi^2\), which simplifies to \((ac-bd) + (ad+bc)i\).
- Squaring: When squaring a complex number like \(-2 + i\sqrt{11}\), use the formula: \((a + bi)^2 = a^2 + 2abi + (bi)^2\)
Complex Conjugate
The complex conjugate of a complex number is obtained by changing the sign of its imaginary part. If we have a complex number \(a + bi\), its complex conjugate is \(a - bi\).
Complex conjugates have some interesting properties that make them especially useful in mathematics:
Complex conjugates have some interesting properties that make them especially useful in mathematics:
- Multiplying a complex number by its conjugate always results in a real number: \((a + bi)(a - bi) = a^2 + b^2\).
- They can be used to simplify division of complex numbers: To divide by a complex number, multiply the numerator and the denominator by the conjugate of the denominator.
- Conjugates preserve the magnitude: While they change the sign of the imaginary part, the overall size or magnitude of the complex number remains unchanged.
Other exercises in this chapter
Problem 35
Contain rational equations with variables in denominators. For each equation, a. write the value or values of the variable that make a denominator zero. These a
View solution Problem 36
Including \(5 \%\) sales tax, an inn charges \(\$ 252\) per night. Find the inn's nightly cost before the tax is added.
View solution Problem 36
In Exercises \(35-46,\) determine the constant that should be added to the binomial so that it becomes a perfect square trinomial. Then write and factor the tri
View solution Problem 36
Use interval notation to express solution sets and graph each solution set on a number line. Solve each linear inequality. $$8 x+3>3(2 x+1)+x+5$$
View solution