Problem 36
Question
In \(32-37,\) determine the number of different arrangements. Making a row of coins using 4 pennies, 3 nickels, and 3 dimes
Step-by-Step Solution
Verified Answer
There are 4200 different arrangements of the coins.
1Step 1: Recognize the Counting Problem
This problem is about arranging objects where some of them are identical. We need to find out how many distinct ways we can arrange these identical coins in a row.
2Step 2: Identify Total Coins
First, count the total number of coins. We have 4 pennies, 3 nickels, and 3 dimes, which adds up to a total of 10 coins.
3Step 3: Use the Formula for Arrangements with Repetition
The formula for arranging n objects where there are repetitions is given by the multinomial coefficient: \[ \frac{n!}{n_1! \cdot n_2! \cdot n_3! \ldots} \] In this case, \( n = 10 \). The repetitions are 4 pennies (\( n_1 = 4 \)), 3 nickels (\( n_2 = 3 \)), and 3 dimes (\( n_3 = 3 \)).
4Step 4: Calculate Factorials
Calculate the factorials needed: \( 10! = 3628800 \), \( 4! = 24 \), and \( 3! = 6 \). These calculations can often be done using a calculator.
5Step 5: Plug into the Formula
Substitute the factorial values into the formula: \[ \frac{10!}{4! \cdot 3! \cdot 3!} = \frac{3628800}{24 \cdot 6 \cdot 6} \]
6Step 6: Simplify the Expression
Calculate the denominator: \( 24 \cdot 6 \cdot 6 = 864 \). Now perform the division: \( \frac{3628800}{864} = 4200 \).
7Step 7: Conclude the Calculation
The number of different arrangements for the coins is 4200.
Key Concepts
Arrangements with RepetitionFactorialsCombinatorics
Arrangements with Repetition
In our daily lives, we often come across situations where we need to arrange items, such as coins or letters, but some of these items might be indistinguishable from others. For instance, if you have a collection of 4 pennies, 3 nickels, and 3 dimes, you'll need to figure out how many unique ways you can lay them out in a line.
This is where the concept of **arrangements with repetition** becomes crucial. When some of the items are identical, it's important to use a specific formula that can account for these repetitions, ensuring each unique arrangement is counted correctly.
The formula for arranging a total of "n" items where some items are repeated is given by the multinomial coefficient:
Using this formula allows for all possible positions or arrangements of these items to be explored and calculated, respecting the indistinguishable nature of similar items.
This is where the concept of **arrangements with repetition** becomes crucial. When some of the items are identical, it's important to use a specific formula that can account for these repetitions, ensuring each unique arrangement is counted correctly.
The formula for arranging a total of "n" items where some items are repeated is given by the multinomial coefficient:
- \[ \frac{n!}{n_1! \cdot n_2! \cdot n_3! \ldots} \]
Using this formula allows for all possible positions or arrangements of these items to be explored and calculated, respecting the indistinguishable nature of similar items.
Factorials
A key part of calculating arrangements with repetition involves understanding factorials. But, what exactly is a factorial?
In mathematics, a factorial (denoted by the symbol "!") of a non-negative integer "n" is the product of all positive integers less than or equal to "n". For example, the factorial of 3, written as "3!", is the product 3 x 2 x 1, which equals 6.
Factorials grow very quickly as "n" increases, and they play an integral role in permutations and combinations problems. In our coin example, to find how many ways you can arrange pennies, nickels, and dimes, you'll calculate:
In mathematics, a factorial (denoted by the symbol "!") of a non-negative integer "n" is the product of all positive integers less than or equal to "n". For example, the factorial of 3, written as "3!", is the product 3 x 2 x 1, which equals 6.
Factorials grow very quickly as "n" increases, and they play an integral role in permutations and combinations problems. In our coin example, to find how many ways you can arrange pennies, nickels, and dimes, you'll calculate:
- The total number of coins factorial, "10!" (which gives us all possible arrangements without considering identical items),
- And the factorial of each set of identical coins: "4!" for pennies, and "3!" each for nickels and dimes.
- \( 10! = 3628800 \)
- \( 4! = 24 \)
- \( 3! = 6 \) for nickels and dimes.
Combinatorics
Combinatorics is a fascinating and broad area within mathematics that deals with counting, arranging, and combining objects. It answers how many ways you can choose or arrange a specific number of objects from a given set when order or repetition may or may not matter.
In situations like arranging coins, combinatorics provides structured methods and formulas to efficiently solve complex problems that involve large numbers of objects.
One of the common applications of combinatorics is solving permutation problems, where the sequence or order of arrangement is important. For our example, where we're arranging 10 coins that include repeats of pennies, nickels, and dimes, it helps determine the distinct arrangements possible through the use of permutations with repetition formula.
Combinatorics isn't just about numbers and formulas; it enhances problem-solving skills and enables the tackling of diverse scenarios ranging from simple arrangements to intricate puzzles in real-life situations.
In situations like arranging coins, combinatorics provides structured methods and formulas to efficiently solve complex problems that involve large numbers of objects.
One of the common applications of combinatorics is solving permutation problems, where the sequence or order of arrangement is important. For our example, where we're arranging 10 coins that include repeats of pennies, nickels, and dimes, it helps determine the distinct arrangements possible through the use of permutations with repetition formula.
Combinatorics isn't just about numbers and formulas; it enhances problem-solving skills and enables the tackling of diverse scenarios ranging from simple arrangements to intricate puzzles in real-life situations.
Other exercises in this chapter
Problem 35
In \(32-37,\) determine the number of different arrangements. The order in which a student answers 8 out of 10 test questions
View solution Problem 35
On a certain ski run, there are 8 places where a skier can choose to go to the left or to the right. In how many different ways can the skier cover the run?
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Stan has letter tiles AMTE. a. How many different ways can Stan arrange all four tiles? b. How many different arrangements begin with a vowel?
View solution Problem 37
In \(32-37,\) determine the number of different arrangements. Rating 6 employees in order of their friendliness
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