Problem 36
Question
If the sum of \(n\) terms of an AP is \(2 n^{2}+5 n\), then show that its \(n t h\) term is \(4 n+3\).
Step-by-Step Solution
Verified Answer
The nth term of the given AP is \(a_n = 4n + 3\).
1Step 1: Recall AP Definitions and Formulas
Recall the basic definition of an AP along with the sum formula:
1. The general term of an AP is given by \(a_n = a_1 + (n-1)d\),
where \(a_n\) is the nth term, \(a_1\) is the first term, \(n\) is the number of terms and \(d\) is the common difference between terms.
2. The sum of n terms of an AP is given by: \(S_n=\frac{n}{2}(2a_1+(n-1)d)\).
2Step 2: Substitute Given Sum in the AP Sum Formula
In this exercise, we are given the sum of n terms of the AP as \(S_n = 2n^2 + 5n\). We will substitute this value into the AP sum formula.
So, \(2n^2 + 5n = \frac{n}{2}(2a_1 + (n-1)d)\).
3Step 3: Simplify Equation and Solve
Multiply both sides by 2 to eliminate fractions:
\(4n^2 + 10n = n(2a_1 + (n-1)d)\).
Now we can simplify and distribute n on the right side:
\(4n^2 + 10n = 2na_1 + n^2d - nd\).
4Step 4: Compare Coefficients
In order to find the formula for the nth term, we need to compare the coefficients of the powers of n in the equation:
For \(n^2\) term: \(4 = d\)
For \(n\) term: \(10 = 2a_1 - d\)
Substitute the \(d\) value obtained from the \(n^2\) term equation:
\(10 = 2a_1 - 4\)
Now, solve for \(a_1\):
\(2a_1 = 14\)
\(a_1 = 7\)
Thus, we have the values of \(a_1\) and \(d\) as \(7\) and \(4\) respectively.
5Step 5: Find the nth term Formula
Now, substitute the values of \(a_1\) and \(d\) in the general term formula,
\(a_n = a_1 + (n-1)d\)
\(a_n = 7 + (n-1)4\)
Simplify to find the nth term formula:
\(a_n = 7 + 4n - 4\)
\(a_n = 4n + 3\)
Therefore, the nth term of this AP is indeed given by the formula \(4n + 3\).
Key Concepts
AP nth term formulaSum of n terms in APCommon difference in AP
AP nth term formula
In an Arithmetic Progression (AP), each term increases by a constant amount, called the common difference. The formula to find the nth term of an AP (denoted as \( a_n \)) is essential for determining specific terms in a sequence. It is given by:\[ a_n = a_1 + (n-1) \cdot d \]where:
- \( a_n \) is the nth term we want to find.
- \( a_1 \) is the first term of the sequence.
- \( n \) is the term number.
- \( d \) is the common difference between consecutive terms.
Sum of n terms in AP
The sum of the first \( n \) terms in an AP is one of the key formulas in arithmetic sequences. This sum provides us with the total of adding up the first \( n \) numbers in the series. The formula is represented as:\[ S_n = \frac{n}{2} (2a_1 + (n-1) \cdot d) \]Here, \( S_n \) is the sum of the first \( n \) terms, and the other variables \( a_1 \), \( n \), and \( d \) are as previously defined:
- \( a_1 \) is the first term of the sequence.
- \( n \) is the total number of terms to be added.
- \( d \) is the common difference.
Common difference in AP
The common difference in an Arithmetic Progression (AP) is a crucial component that dictates how the sequence's terms increase. It is defined as the difference between any two consecutive terms in the sequence. Mathematically, if you have a sequence with terms \( a_1, a_2, a_3, \ldots \), the common difference \( d \) can be calculated by:\[ d = a_2 - a_1 \]This difference remains constant throughout the sequence. In the context of the problem solved, after equating and comparing the sum of \( n \) terms to the sum formula, the common difference \( d \) was determined to be 4:
- By matching the coefficient of \( n^2 \) in both expressions, it was established that \( d = 4 \).
Other exercises in this chapter
Problem 34
The sum of \(n\) term of a series is \(3 n^{2}+4 n\). Show that the series is an A.P. and find the first term and common difference. What will be its \(n\) th t
View solution Problem 35
If the sum of \(n\) terms of an AP be \(3 n^{2}-n\), then find its first term and common difference.
View solution Problem 37
Find the sum of all natural numbers between 250 and 1000 which are exactly divisible by \(3 .\)
View solution Problem 38
If \(\frac{3+5+7+\ldots \ldots+n \text { terms }}{5+8+11+\ldots \ldots+10 \text { terms }}=7\), then find the value of \(n\).
View solution