Problem 36
Question
Guess an antiderivative for the integrand function. Validate your guess by differentiation and then evaluate the given definite integral. (Hint: Keep in mind the Chain Rule in guessing an antiderivative. You will learn how to find such antiderivatives in the next section.) $$\int_{1}^{2} \frac{\ln x}{x} d x$$
Step-by-Step Solution
Verified Answer
The value is \(\frac{(\ln 2)^2}{2}\).
1Step 1: Identify the Integrand
The given integrand is \( \frac{\ln x}{x} \). We need to find an antiderivative for this function.
2Step 2: Guess the Antiderivative
Notice that the derivative of \( \ln x \) is \( \frac{1}{x} \). By considering the structure of the integrand, we can guess that an antiderivative of \( \frac{\ln x}{x} \) might be \( (\ln x)^2/2 \).
3Step 3: Validate the Antiderivative
Differentiate \( (\ln x)^2/2 \) with respect to \( x \):\[ \frac{d}{dx} \left( \frac{(\ln x)^2}{2} \right) = \frac{1}{2} \cdot 2 \ln x \cdot \frac{1}{x} = \frac{\ln x}{x}. \]This confirms our guess is correct, as the derivative matches the integrand.
4Step 4: Evaluate the Definite Integral
Now, evaluate the definite integral:\[ \int_{1}^{2} \frac{\ln x}{x} \, dx = \left[ \frac{(\ln x)^2}{2} \right]_1^2. \]Calculate:1. For \( x = 2 \), \( \frac{(\ln 2)^2}{2} \).2. For \( x = 1 \), \( \frac{(\ln 1)^2}{2} = 0 \) because \( \ln 1 = 0 \).Subtract:\[ \frac{(\ln 2)^2}{2} - 0 = \frac{(\ln 2)^2}{2}. \]
5Step 5: Final Answer
The value of the definite integral from 1 to 2 of \( \frac{\ln x}{x} \) is \( \frac{(\ln 2)^2}{2} \). This is the evaluated result.
Key Concepts
AntiderivativesChain RuleDifferentiationIntegrand
Antiderivatives
Finding antiderivatives is like uncovering the original function from its rate of change. In our problem, the core task is to determine the antiderivative of the function \( \frac{\ln x}{x} \).
This process is essentially reversing differentiation. How do we approach this?
This process is essentially reversing differentiation. How do we approach this?
- First, understand that the antiderivative of a function is a new function whose derivative is the original function.
- For example, differentiating \( \ln x \) gives \( \frac{1}{x} \), so reversing it gives insight into the antiderivative of related functions.
Chain Rule
The chain rule is a vital tool in both differentiation and integration. It helps to differentiate compositions of functions, essentially functions within functions.
Why is it important?
Why is it important?
- Because it allows us to handle complex expressions like \( (\ln x)^2 \)x within differentiation.
- In our exercise, differentiating \( \frac{(\ln x)^2}{2} \) requires the chain rule.
Differentiation
Differentiation is the process of finding the derivative, or the rate at which a function is changing at any given point. It's crucial for verifying antiderivatives.
In our step-by-step solution:
In our step-by-step solution:
- We guessed that \( \frac{(\ln x)^2}{2} \) was the antiderivative for \( \frac{\ln x}{x} \).
- By differentiating \( \frac{(\ln x)^2}{2} \) step by step, we confirmed it returned back to the original integrand.
Integrand
The integrand is the function you want to integrate, the main focus of any integral problem. In our exercise, the integrand is \( \frac{\ln x}{x} \). Knowing how to approach an integrand is crucial.
- At first glance, the structure can give hints about its antiderivative. Do you see that both \( \ln x \) and \( \frac{1}{x} \) are related?
- This connection often indicates which function might unroll during differentiation.
Other exercises in this chapter
Problem 36
Use the Substitution Formula in Theorem 7 to evaluate the integrals in Exercises \(1-46\). $$\int_{0}^{\pi / 12} 6 \tan 3 x d x$$
View solution Problem 36
Evaluate the integrals. $$\int \frac{\cos \sqrt{\theta}}{\sqrt{\theta} \sin ^{2} \sqrt{\theta}} d \theta$$
View solution Problem 36
Graph each function \(f(x)\) over the given interval. Partition the interval into four subintervals of equal length. Then add to your sketch the rectangles asso
View solution Problem 37
Use the Substitution Formula in Theorem 7 to evaluate the integrals in Exercises \(1-46\). $$\int_{-\pi / 2}^{\pi / 2} \frac{2 \cos \theta d \theta}{1+(\sin \th
View solution