Problem 36
Question
Graph each function. $$f(x)=\log _{10}(3-x)$$
Step-by-Step Solution
Verified Answer
The function has a domain of \((-\infty, 3)\), a vertical asymptote at \(x = 3\), and passes through \((0, \log_{10}(3))\).
1Step 1: Identify the Domain
The domain of the function is the set of all x-values for which the function is defined. For the function \( f(x) = \log_{10}(3-x) \), the logarithm is only defined for positive arguments. Therefore, we need \( 3-x > 0 \), which simplifies to \( x < 3 \). Thus, the domain of the function is \( (-\infty, 3) \).
2Step 2: Identify Vertical Asymptote
The vertical asymptote occurs where the argument of the logarithm is zero because the logarithm is undefined at zero. Therefore, set \( 3-x = 0 \), which gives \( x = 3 \). Hence, there is a vertical asymptote at \( x = 3 \).
3Step 3: Find Intercept
To find the y-intercept, evaluate the function at \( x = 0 \). \[ f(0) = \log_{10}(3-0) = \log_{10}(3) \]. This gives the y-intercept as \( (0, \log_{10}(3)) \).
4Step 4: Analyze Behavior Near Asymptote
As \( x \) approaches 3 from the left (\( x \to 3^{-} \)), the argument of the log, \( 3-x \), approaches zero. The function \( \log_{10}(3-x) \) will go to \(-\infty\) as \( x \to 3^{-} \).
5Step 5: Plot a few key points and draw the graph
Use the information from previous steps to graph the function. Key points include the y-intercept at \( (0, \log_{10}(3)) \). As \( x \to 3^{-} \), the function approaches \(-\infty\), and as \( x \to -\infty \), the function approaches \( \log_{10}(3) \). Connect these points smoothly and ensure the curve becomes steep as it approaches the vertical asymptote at \( x = 3 \).
Key Concepts
Domain of a functionVertical AsymptoteY-interceptGraphing techniques
Domain of a function
The domain of a function refers to the complete set of possible input values (or x-values) that will produce a valid output from a mathematical function. For logarithmic functions like \( f(x) = \log_{10}(3-x) \), it is crucial to identify which x-values will allow the logarithmic function to be defined.
In this specific case, the expression inside the logarithm \( 3-x \) must be positive because the logarithm of zero or a negative number is undefined in the realm of real numbers. To find when \( 3-x \) is greater than zero, we set up the inequality:
In this specific case, the expression inside the logarithm \( 3-x \) must be positive because the logarithm of zero or a negative number is undefined in the realm of real numbers. To find when \( 3-x \) is greater than zero, we set up the inequality:
- \( 3 - x > 0 \)
- Solving for \( x \) gives \( x < 3 \)
Vertical Asymptote
A vertical asymptote in the graph of a function is a line that the graph approaches but never actually touches. It typically occurs when the function becomes undefined, which for logarithmic functions, happens when their argument is zero.
In our function \( f(x) = \log_{10}(3-x) \), the vertical asymptote is found by setting the argument of the logarithm to zero:
In our function \( f(x) = \log_{10}(3-x) \), the vertical asymptote is found by setting the argument of the logarithm to zero:
- \( 3 - x = 0 \)
- Solving for \( x \) reveals \( x = 3 \)
Y-intercept
The y-intercept of a graph represents the point where the graph of the function intersects the y-axis. This occurs when \( x = 0 \), since the y-axis corresponds to all points where the x-coordinate is zero.
To find the y-intercept for \( f(x) = \log_{10}(3-x) \), we substitute \( x = 0 \) into the function:
To find the y-intercept for \( f(x) = \log_{10}(3-x) \), we substitute \( x = 0 \) into the function:
- \( f(0) = \log_{10}(3 - 0) = \log_{10}(3) \)
Graphing techniques
When graphing the function \( f(x) = \log_{10}(3-x) \), we use several techniques to ensure accuracy and clarity. Having identified key features such as the domain, vertical asymptote, and y-intercept, these guide the shape of the graph.
Begin by plotting significant points and noting behaviors:
Begin by plotting significant points and noting behaviors:
- Plot the y-intercept \( (0, \log_{10}(3)) \).
- Recognize the vertical asymptote at \( x = 3 \), indicating that as the graph approaches this line from the left, it drops sharply downward.
- Note that as \( x \) tends to negative infinity, the values of the function slightly increase because the function approaches \( \log_{10}(3) \).
- Start from the left of the graph, tracing the rise towards \( \log_{10}(3) \) but ensure it doesn't level, indicating a slight logarithmic curve.
- As you approach \( x = 3 \), show the curve dropping steeply toward minus infinity, reflecting the behavior near the asymptote.
Other exercises in this chapter
Problem 35
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