Problem 36
Question
Geometry The perimeter of a triangle is 105 inches. The longest side is 22 inches longer than the shortest side. The sum of the lengths of the two shorter sides is 15 inches more than the length of the longest side. Find the lengths of the sides of the triangle.
Step-by-Step Solution
Verified Answer
The sides are 27, 31, and 47 inches.
1Step 1: Understanding the Problem
We are given that the perimeter of the triangle is 105 inches. The longest side is 22 inches longer than the shortest side. Moreover, the sum of the lengths of the two shorter sides is 15 inches more than the longest side. We need to find the length of each side.
2Step 2: Setting Up Variables
Let's denote the shortest side as \( x \). According to the problem, the longest side will be \( x + 22 \). Let's denote the middle side as \( y \). Then the perimeter equation is \( x + y + (x + 22) = 105 \).
Key Concepts
triangle perimetergeometry problemsalgebra in geometry
triangle perimeter
In geometry, the perimeter of a shape is the total length around its boundary. For a triangle, which has three sides, the perimeter is the sum of the lengths of all its sides. Knowing how to calculate the perimeter is crucial, as it helps in solving various geometry problems.
When you have the perimeter of a triangle, like 105 inches in this exercise, and additional information about the sides, you can use these details to find unknown side lengths. The basic formula for the perimeter of a triangle is:
When you have the perimeter of a triangle, like 105 inches in this exercise, and additional information about the sides, you can use these details to find unknown side lengths. The basic formula for the perimeter of a triangle is:
- Perimeter = Side 1 + Side 2 + Side 3
geometry problems
Solving geometry problems often involves understanding and interpreting the relationships between different elements of a shape. In the case of triangles, being able to translate word problems into mathematical expressions is essential. This not only involves recognizing the data given but also identifying what additional information can be derived from it.
For instance, in this exercise, we understand that the longest side is 22 inches longer than the shortest. Therefore, if you choose to represent the shortest side as \( x \), the longest side can be expressed as \( x + 22 \).
Additionally, the sum of the lengths of the two shorter sides is 15 inches more than the longest side. This gives another equation where \( x + y = x + 22 + 15 \). Solving these equations requires careful attention, ensuring each piece of information is used accurately to form equations that reflect the problem's requirements. Understanding such relationships forms the basis of solving geometry problems.
For instance, in this exercise, we understand that the longest side is 22 inches longer than the shortest. Therefore, if you choose to represent the shortest side as \( x \), the longest side can be expressed as \( x + 22 \).
Additionally, the sum of the lengths of the two shorter sides is 15 inches more than the longest side. This gives another equation where \( x + y = x + 22 + 15 \). Solving these equations requires careful attention, ensuring each piece of information is used accurately to form equations that reflect the problem's requirements. Understanding such relationships forms the basis of solving geometry problems.
algebra in geometry
Algebra can be a powerful tool when solving geometry problems. Using algebraic expressions to represent the unknown sides of a triangle can simplify complex problems. Assigning variables to different parts of the problem helps to express relationships and constraints algebraically.
In this particular problem, the variables help to set up equations based on the perimeter and the relationships between the sides. We used:
In this particular problem, the variables help to set up equations based on the perimeter and the relationships between the sides. We used:
- \( x \) for the shortest side
- \( x + 22 \) for the longest side
- \( y \) for the middle side
- \( x + y + (x + 22) = 105 \)
- \( x + y = x + 22 + 15 \)
Other exercises in this chapter
Problem 36
LetA be the given matrix. Find \(A^{-1}\). $$ \left[\begin{array}{rrr} 2 & -3 & 1 \\ 5 & -6 & 3 \\ 3 & 2 & 0 \end{array}\right] $$
View solution Problem 36
Use Gaussian elimination with backward substitution to solve the system of linear equations. Write the solution as an ordered pair or an ordered triple whenever
View solution Problem 36
Graph each system of equations and find any solutions. Check your answers. Identify the system as consistent or inconsistent. If the system is consistent, state
View solution Problem 37
If possible, find \(A B\) and \(B A\). $$A=\left[\begin{array}{rrr}1 & -1 & 0 \\\2 & -1 & 5 \\\6 & 1 & -4\end{array}\right], \quad B=\left[\begin{array}{rrr}-1
View solution