Problem 36
Question
Gender Makeup of a Family Suppose a family has 5 children. Suppose also that the probability of having a girl is \(\frac{1}{2} .\) Find the probability that the family has the following children. (picture cannot copy) No more than 4 girls
Step-by-Step Solution
Verified Answer
The probability that the family has no more than 4 girls is \(\frac{31}{32}\).
1Step 1: Understanding the Binomial Distribution
In this problem, the number of children in the family (each child being either male or female) can be treated as a binomial experiment. Each individual child can be either a girl (success) or a boy (failure) with probability \(p = \frac{1}{2}\). The number of trials, \(n\), is 5 since there are 5 children.
2Step 2: Identifying "No More Than 4 Girls"
The phrase "no more than 4 girls" means that the possible outcomes include having 0, 1, 2, 3, or 4 girls. We need to calculate the probability of these cases and sum them up.
3Step 3: Binomial Probability Formula
The probability of getting exactly \(k\) successes (girls, in this case) in \(n\) trials is given by the binomial formula: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \(\binom{n}{k}\) is the binomial coefficient, calculated as \(\frac{n!}{k!(n-k)!}\).
4Step 4: Probability for Each Outcome
Calculate the probability of getting 0, 1, 2, 3, and 4 girls using the formula:- \(P(0\text{ girls}) = \binom{5}{0} \left(\frac{1}{2}\right)^0 \left(\frac{1}{2}\right)^5 = \frac{1}{32}\)- \(P(1\text{ girl}) = \binom{5}{1} \left(\frac{1}{2}\right)^1 \left(\frac{1}{2}\right)^4 = \frac{5}{32}\)- \(P(2\text{ girls}) = \binom{5}{2} \left(\frac{1}{2}\right)^2 \left(\frac{1}{2}\right)^3 = \frac{10}{32}\)- \(P(3\text{ girls}) = \binom{5}{3} \left(\frac{1}{2}\right)^3 \left(\frac{1}{2}\right)^2 = \frac{10}{32}\)- \(P(4\text{ girls}) = \binom{5}{4} \left(\frac{1}{2}\right)^4 \left(\frac{1}{2}\right)^1 = \frac{5}{32}\)
5Step 5: Summing the Probabilities
Add the probabilities calculated in Step 4 together to find the probability of having no more than 4 girls:\[ P(X \leq 4) = P(0) + P(1) + P(2) + P(3) + P(4) = \frac{1}{32} + \frac{5}{32} + \frac{10}{32} + \frac{10}{32} + \frac{5}{32} = \frac{31}{32} \]
Key Concepts
Probability TheoryBinomial CoefficientBinomial Experiment
Probability Theory
Probability theory is the mathematical framework that helps us understand and predict random events. It's like a set of rules for how likely different outcomes are, under given conditions. In the family example, each child born represents a random event with a probability of being a girl or a boy. The probability, indicated as \( p \), is \( \frac{1}{2} \) for each outcome, meaning there is an equal chance of having a boy or a girl. This simplicity helps in calculating multiple child outcomes.
- Event: An occurrence like having a girl.
- Probability of an Event: The chance that a particular event occurs, between 0 and 1.
- Random Experiment: Repeating an event, like having children, several times to see different outcomes.
Binomial Coefficient
The binomial coefficient plays a crucial role in calculating probabilities in situations like the family example. The binomial coefficient, denoted as \( \binom{n}{k} \), helps determine how many ways \( k \) successes (girls, here) can occur in \( n \) total events (children).
To calculate the binomial coefficient, use the formula:\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] where \( n! \) represents \( n \) factorial, the product of all positive integers up to \( n \). For example, \( \binom{5}{3} = \frac{5!}{3! \, 2!} = 10 \), indicating there are 10 ways to have 3 girls out of 5 children.
To calculate the binomial coefficient, use the formula:\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \] where \( n! \) represents \( n \) factorial, the product of all positive integers up to \( n \). For example, \( \binom{5}{3} = \frac{5!}{3! \, 2!} = 10 \), indicating there are 10 ways to have 3 girls out of 5 children.
- Selection of Events: Number of ways to pick successes from trials.
- Facilitates Probability Computation: Used in the binomial distribution formula.
Binomial Experiment
A binomial experiment is a statistical experiment that satisfies certain criteria, making it suitable for binomial distribution calculations. In our family example, each child's birth is a trial with two possible outcomes. The binomial experiment checks these conditions:
- Fixed Number of Trials (\( n \)): Here, 5 children or trials.
- Two Possible Outcomes: Success (girl) or failure (boy).
- Constant Probability: Each child has a probability \( p = \frac{1}{2} \) for being a girl.
- Independent Trials: Birth outcomes of individual children don't influence each other.
Other exercises in this chapter
Problem 35
Use a formula to find the sum of each series. $$\sum_{k=4}^{10}(-2)^{k}$$
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Find the sum for each series. $$\sum_{i=1}^{4} i^{i}$$
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Prove each statement by mathematical induction. \(4 n
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Determine the positive integer values of \(n\), where the arithmetic sequence \(a_{n}\) satisfies the inequality. $$a_{n} \geq 30, \text { where } a_{n}=100-2 n
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