Problem 36
Question
For the following problems, solve the equations, if possible. $$ x^{2}-4=0 $$
Step-by-Step Solution
Verified Answer
Answer: The solutions are x = 2 and x = -2.
1Step 1: Write the equation in the standard form
Let's write the given equation in the standard quadratic form as:
$$x^2 - 4 = 0$$
2Step 2: Factor the quadratic expression
The difference of squares can be factored into two binomials as:
$$(x-2)(x+2)=0$$
3Step 3: Solve for x using the Zero Product Property
The Zero Product Property states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor to zero and solve for x:
$$x - 2 = 0 \Rightarrow x = 2$$
$$x + 2 = 0 \Rightarrow x = -2$$
4Step 4: Write the final solution
The solutions of the quadratic equation, $$x^2-4=0$$, are:
$$x = 2 \text{ and } x = -2$$
Key Concepts
Understanding Factoring in Quadratic EquationsApplying the Zero Product PropertyRecognizing and Using the Difference of Squares
Understanding Factoring in Quadratic Equations
Factoring is a method used to simplify quadratic equations into a set of simple expressions that can be easily solved. When you factor an equation, you're essentially breaking it down into its components or ‘factors’ that, when multiplied together, yield the original equation.
In the context of our quadratic equation, \(x^2 - 4 = 0\), we can recognize a special pattern called a 'difference of squares'.
This allows us to express the equation as the product of two binomials: \((x-2)(x+2)\).
In the context of our quadratic equation, \(x^2 - 4 = 0\), we can recognize a special pattern called a 'difference of squares'.
This allows us to express the equation as the product of two binomials: \((x-2)(x+2)\).
- The expression \(x^2 - 4\) is split into \((x-2)\) and \((x+2)\).
- Notice how each factor contains an \(x\) term and a constant, which, when multiplied together, return to the original quadratic expression.
Applying the Zero Product Property
The Zero Product Property is a fundamental principle in algebra that simplifies the process of solving equations like our quadratic equation.
This property states that if the product of two numbers is zero, then at least one of the numbers must also be zero.
For our factored equation \((x-2)(x+2)=0\), we apply this principle as follows:
This property states that if the product of two numbers is zero, then at least one of the numbers must also be zero.
For our factored equation \((x-2)(x+2)=0\), we apply this principle as follows:
- Set each factor equal to zero: \(x-2=0\) and \(x+2=0\).
- Solving these two simple equations, we find that \(x = 2\) and \(x = -2\).
Recognizing and Using the Difference of Squares
The difference of squares is a special pattern in algebra that occurs when we subtract one squared number from another: \(a^2 - b^2\).
This pattern can be expressed as the product of two binomials: \((a-b)(a+b)\).
Using this pattern, our original quadratic equation \(x^2 - 4 = 0\) can be rewritten.
This pattern can be expressed as the product of two binomials: \((a-b)(a+b)\).
Using this pattern, our original quadratic equation \(x^2 - 4 = 0\) can be rewritten.
- Here, \(a^2\) is \(x^2\), and \(b^2\) is \(4\) or \(2^2\).
- Using the difference of squares formula, we rewrite it as \((x-2)(x+2)\).
Other exercises in this chapter
Problem 36
For the following problems, solve the equations using the quadratic formula. $$ x^{2}=-3 x+7 $$
View solution Problem 36
One pipe can fill a tank in 120 seconds and another pipe can fill the same tank in 90 seconds. How long will it take both pipes working together to fill the tan
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For the following problems, solve each of the quadratic equations using the method of extraction of roots. $$ 4 a^{2}=40 $$
View solution Problem 36
For the following problems, use the zero-factor property to solve the equations. $$ -5(x+4)=0 $$
View solution