Problem 36
Question
Find the intervals on which the given Ir function is increasing and those on which it is decreasing. $$ f(x)=x|x| $$
Step-by-Step Solution
Verified Answer
The function is increasing on \((0, \infty)\) and decreasing on \((-\infty, 0)\).
1Step 1: Understand the Function
The function given is \( f(x) = x|x| \). Note that \(|x|\) denotes the absolute value of \(x\). Thus, \(f(x)\) can be rewritten as follows depending on the sign of \(x\): \(f(x) = x^2\) when \(x \geq 0\) and \(f(x) = -x^2\) when \(x < 0\).
2Step 2: Differentiate the Piecewise Function
To determine where the function is increasing or decreasing, we need its derivative. The derivative of \( f(x) = x^2 \) for \( x \geq 0 \) is \( f'(x) = 2x \). For \( f(x) = -x^2 \) when \( x < 0 \), the derivative is \( f'(x) = -2x \).
3Step 3: Analyze the Derivative for Intervals
For \( x \geq 0 \), the derivative \( f'(x) = 2x \), so the function is increasing when \( 2x > 0 \), i.e., \( x > 0 \). For \( x < 0 \), the derivative \( f'(x) = -2x \), so the function is increasing when \( -2x > 0 \) or \( x < 0 \). However, here it's decreasing because the inequality is not satisfied.
4Step 4: Summarize Intervals of Increase/Decrease
Thus, \( f(x) \) is increasing on the interval \((0, \infty)\) and decreasing on the interval \((-\infty, 0)\). The function changes direction at \(x = 0\), which acts as a boundary point in the analysis but isn't included explicitly in either increasing or decreasing intervals.
Key Concepts
Piecewise FunctionsDerivativesIntervals of Increase and DecreaseAbsolute Value Functions
Piecewise Functions
Piecewise functions are a type of function constructed by piecing together different expressions. These expressions are defined over different intervals of the domain. When working with piecewise functions, it's crucial to understand that each piece applies to specific values of the variable. For example:
- For a function like \(f(x) = x|x|\), it behaves as \(x^2\) when \(x \geq 0\).
- When \(x < 0\), it takes the form \(-x^2\).
Derivatives
Derivatives play a vital role in understanding the behavior of functions. They provide information about the rate at which a function's output value changes relative to changes in the input.
To find the derivative of a piecewise function like \(f(x) = x|x|\), you differentiate each distinct piece separately:
To find the derivative of a piecewise function like \(f(x) = x|x|\), you differentiate each distinct piece separately:
- For \(x \geq 0\), where \(f(x) = x^2\), the derivative is \(f'(x) = 2x\).
- For \(x < 0\), where \(f(x) = -x^2\), the derivative becomes \(f'(x) = -2x\).
Intervals of Increase and Decrease
To determine where a function increases or decreases, we analyze the sign of its derivative. When identifying intervals of increase and decrease:
- For \(x \geq 0\), the derivative \(2x > 0\) when \(x > 0\), implying the function is increasing.
- For \(x < 0\), the derivative \(-2x < 0\), means the function is decreasing.
Absolute Value Functions
Absolute value functions are essential in calculus as they transform any input into its non-negative value. In the context of \(f(x) = x |x|\), the absolute value helps in defining the function across different intervals:
- The absolute value \(|x|\) creates the piecewise nature of the function, differentiating behavior as \(x^2\) for non-negative \(x\) and \(-x^2\) for negative \(x\).
- This transformation allows the function to smoothly transition at \(x = 0\), without a jump or discontinuity, which is typical in functions involving absolute values.
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