Problem 36
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(5 y-2)(5 y+2)$$
Step-by-Step Solution
Verified Answer
The product is \(25y^2 - 4\).
1Step 1: Identify the Binomial Pattern
Recognize that the expression \((5y - 2)(5y + 2)\) fits the pattern of the difference of squares \((a-b)(a+b) = a^2 - b^2\). Here, \(a = 5y\) and \(b = 2\).
2Step 2: Apply the Difference of Squares Formula
Substitute \(a = 5y\) and \(b = 2\) into the difference of squares formula, giving us \((5y)^2 - (2)^2\).
3Step 3: Calculate Each Square
Calculate \((5y)^2\), which is \((5y)(5y) = 25y^2\), and \(2^2\), which is \(4\).
4Step 4: Subtract the Squares
Subtract the smaller square from the larger one: \(25y^2 - 4\). This is the simplified form of the expression.
Key Concepts
Difference of SquaresSimplifying ExpressionsAlgebraic Patterns
Difference of Squares
The difference of squares is a special algebraic pattern that simplifies the multiplication of specific binomials. When you see an expression like \((a-b)(a+b)\), it can be transformed using the formula \(a^2 - b^2\). This pattern arises because multiplying opposites leads to the cancellation of the middle terms in the expansion.
- For example, with \((5y - 2)(5y + 2)\), the expression fits the difference of squares pattern.
- Here, \(a = 5y\) and \(b = 2\).
- Applying the formula, you get \((5y)^2 - (2)^2 = 25y^2 - 4\).
Simplifying Expressions
Simplifying expressions is about making them more manageable, usually by reducing them to fewer terms or simpler forms. When you simplify using algebraic patterns, you aim to express the equation as cleanly and efficiently as possible.
- You can see an example of this in the expression \(25y^2 - 4\), which is the result after applying the difference of squares.
- This means no further combination or factorization is necessary; you've reached a simplified and final state.
- Sometimes, simplifying may also involve techniques like combining like terms or reducing fractions to their simplest form.
Algebraic Patterns
Algebraic patterns are consistent, predictable arrangements in mathematical expressions that help us identify the most efficient processing method.
- The difference of squares is one such pattern, allowing for neat solutions to certain binomial multiplications.
- Recognizing these patterns instantly can aid in streamlining mathematical operations.
- For students, practicing these allows them to notice other algebraic patterns like the perfect square trinomial or the sum/difference of cubes.
Other exercises in this chapter
Problem 36
Factor each of the following polynomials completely. Indicate any that are not factorable using integers. Don't forget to look first for a common monomial facto
View solution Problem 36
Factor completely. $$6 x^{5}-18 x^{3}+24 x$$
View solution Problem 36
Find each product. $$(-12 x)(3 y)\left(-\frac{3}{4} x y^{6}\right)$$
View solution Problem 36
Subtract the polynomials using the vertical format. \(4 x^{2}-3 x-7\) from \(-x^{2}-6 x+9\)
View solution