Problem 36
Question
Find an equation for the parabola that has its vertex at the origin and satisfies the given condition(s). Directrix: \(x=-\frac{1}{8}\)
Step-by-Step Solution
Verified Answer
The equation of the parabola is \(y^2 = \frac{1}{2}x\).
1Step 1: Understanding the Parabola's Orientation
Since the directrix of the parabola is a vertical line, the parabola opens horizontally. This positioning means that the parabola has the form \(y^2 = 4px\), with its vertex at the origin \((0,0)\). Here, \(p\) represents the distance from the vertex to the focus or from the vertex to the directrix.
2Step 2: Determine the Value of p
The equation of the directrix is given as \(x = -\frac{1}{8}\). The vertex is at \(x = 0\). Thus, the distance \(p\) is \(\frac{1}{8}\). Since the parabola opens to the right (directrix is to the left of the vertex), \(p\) is \(\frac{1}{8}\).
3Step 3: Substitute p into the Standard Form Equation
With \(p = \frac{1}{8}\), substitute into the standard form equation of a horizontal parabola: \(y^2 = 4px\). This gives \(y^2 = 4\times\frac{1}{8}\times x\), which simplifies to \(y^2 = \frac{1}{2}x\).
Key Concepts
Vertex at OriginDirectrix of a ParabolaHorizontal Parabola
Vertex at Origin
In the context of parabolas, the term 'vertex' refers to the point at which the curve changes direction. The vertex is a critical point for any parabola, as it dictates its starting position and orientation. When the vertex is at the origin, this means that the parabola begins at the coordinate point
For instance, a parabola with its vertex at the origin that opens upwards or downwards follows the equation format:
- (0,0)
For instance, a parabola with its vertex at the origin that opens upwards or downwards follows the equation format:
- \( x^2 = 4py \)
- \( y^2 = 4px \)
Directrix of a Parabola
The directrix of a parabola is a specific line used to define and construct the parabola along with the focus. It's a line that is equally distant from all points on the curve to the parabola's focus, helping set the curve's width and direction. In this exercise, the given directrix is
- \( x = -\frac{1}{8} \)
- If the directrix is vertical (like in this case), the parabola opens horizontally.
- If the directrix is horizontal, the parabola opens vertically.
- \( p = \frac{1}{8} \)
Horizontal Parabola
A horizontal parabola has a distinct orientation compared to its more commonly known vertical counterpart. In our case, the parabola opens horizontally due to the vertical orientation of the directrix. This leads to a characteristic equation format, aligned along the y-axis:
- \( y^2 = 4px \)
- \( x = -\frac{1}{8} \)
- \( y^2 = \frac{1}{2}x \)
Other exercises in this chapter
Problem 36
Find an equation for the ellipse that satisfies the given conditions. Length of major axis: \(6,\) length of minor axis: \(4,\) foci on \(x\) -axis
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Use a graphing device to graph the conic. $$4 x^{2}+9 y^{2}-36 y=0$$
View solution Problem 37
Find an equation for the hyperbola that satisfies the given conditions. Foci: \((0, \pm 8),\) asymptotes: \(y=\pm \frac{1}{2} x\)
View solution Problem 37
A polar equation of a conic is given. (a) Find the eccentricity and the directrix of the conic. (b) If this conic is rotated about the origin through the given
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