Problem 36
Question
Evaluate the expression and write the result in the form \(a+b i .\) $$ \frac{-3+5 i}{15 i} $$
Step-by-Step Solution
Verified Answer
The result is \(-\frac{1}{3} + \frac{1}{5}i\).
1Step 1: Multiply the Numerator and Denominator by the Conjugate of the Denominator
The current expression is \( \frac{-3+5i}{15i} \). Multiplying both the numerator and the denominator by \(-i\) (the conjugate of \(15i\)) helps remove the imaginary component from the denominator. Thus, we will perform the following operation:\(\frac{(-3+5i)(-i)}{15i(-i)} = \frac{3i-5}{-15}\).
2Step 2: Simplify the Denominator
The denominator now is \(-15\), since \(15i(-i) = 15(-i^2) = 15(1) = 15\). So, the expression simplifies to:\(\frac{-3i + 5}{15}\).
3Step 3: Simplify Each Part of the Result
Separate the numerator and divide each term by \(-15\):- Real part: \(\frac{5}{-15} = -\frac{1}{3}\)- Imaginary part: \(\frac{-3i}{-15} = \frac{1}{5}i\)Thus, the expression becomes \(-\frac{1}{3} + \frac{1}{5}i\).
Key Concepts
Understanding the Imaginary UnitExploring Complex ConjugatesRationalizing Denominators
Understanding the Imaginary Unit
When exploring complex numbers, the imaginary unit is a key player. Denoted by the letter \( i \), the imaginary unit is defined with the property that \( i^2 = -1 \).
This is crucial because it allows the extension of the number system beyond real numbers, enabling solutions to equations that don’t have real solutions, such as \( x^2 + 1 = 0 \).
Here's how it works in practice:
This is crucial because it allows the extension of the number system beyond real numbers, enabling solutions to equations that don’t have real solutions, such as \( x^2 + 1 = 0 \).
Here's how it works in practice:
- Imaginary numbers are essentially real numbers multiplied by the imaginary unit \( i \). For example, \(5i\) means 5 times the imaginary unit.
- Imaginary numbers combine with real numbers to form complex numbers, which can be expressed as \(a + bi\), where \(a\) and \(b\) are real numbers.
Exploring Complex Conjugates
A complex conjugate is a straightforward yet powerful tool in complex number calculations.
For a given complex number \(a + bi\), its complex conjugate is \(a - bi\).
The role of a complex conjugate is pivotal for eliminating the imaginary parts from denominators when dividing complex numbers. Using a complex conjugate, we achieve a real number in the denominator.
The product of a complex number and its conjugate is always a real number, specifically:
For a given complex number \(a + bi\), its complex conjugate is \(a - bi\).
The role of a complex conjugate is pivotal for eliminating the imaginary parts from denominators when dividing complex numbers. Using a complex conjugate, we achieve a real number in the denominator.
The product of a complex number and its conjugate is always a real number, specifically:
- The sum of the squares of its real and imaginary parts, formulated as \((a+bi)(a-bi) = a^2 + b^2\).
Rationalizing Denominators
Rationalizing the denominator involves a technique used to clear complex numbers or radicals from the denominator of a fraction.
For complex numbers, this typically involves using the concept of the complex conjugate.
The aim is to achieve a real number in the denominator, making the fraction more manageable and standard.
This process involves:
Rationalizing helps present complex numbers in a more conventional form, improving comprehension and manipulation.
For complex numbers, this typically involves using the concept of the complex conjugate.
The aim is to achieve a real number in the denominator, making the fraction more manageable and standard.
This process involves:
- Identifying the complex number or radical in the denominator.
- Multiplying both the numerator and the denominator by the conjugate of the denominator.
Rationalizing helps present complex numbers in a more conventional form, improving comprehension and manipulation.
Other exercises in this chapter
Problem 36
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Find all real solutions of the equation. \(x^{2}-6 x+1=0\)
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