Problem 36
Question
Does the function have an inverse? Explain. Domain Range \(1 / 2\) hour \(\longrightarrow \$ 40\) 1 hour 2 hours \(\longrightarrow . \$ 70\) 4 hours \(\longrightarrow \$ 120\)
Step-by-Step Solution
Verified Answer
Yes, the function does have an inverse because it is both one-to-one (injective) and onto (surjective)
1Step 1: Verify if the function is injective (one-to-one)
To check if the function is injective, we need to make sure that no two different inputs produce the same output. Looking at the given input-output pairs, none of the outputs repeat for different inputs, thus this function is indeed injective.
2Step 2: Verify if the function is surjective (onto)
To confirm if the function is surjective, it should cover all the elements of the range. However, in this exercise, a specific range has not been given. In such cases, we can say that the range is just the set of outputs that we have, thus this function will effectively be considered as surjective.
3Step 3: Conclusion about the Inverse
Since the function is both injective (one-to-one) and surjective (onto), according to the definition of a bijective function, we can conclude that the function does indeed have an inverse.
Key Concepts
Injective FunctionsSurjective FunctionsBijective Functions
Injective Functions
An injective function, also known as a one-to-one function, is one where each element of the domain maps to a unique element in the range. This means no two different inputs in the domain will map to the same output in the range.
- Example Observation: Consider the mapping from time worked to earnings. If working for 1 hour earns you $50, and working for 2 hours earns you $100, then no two different time intervals should result in the same earnings in a truly injective function.
- Verification Method: Check the provided input-output pairs. If each input is linked to a unique outcome and no output is repeated unless it's from the same input, then the function is injective.
Surjective Functions
Surjective functions, or onto functions, are those in which every element of the function's range is associated with some element in the domain. In simpler terms, every possible result is covered by some input.
- Example Realization: Picture a scenario where each earning amount on a chart corresponds to at least one period of work duration. If you see an earning like $70 and can identify a corresponding (even theoretical) time worked, the function fulfills the criteria of being surjective.
- Verification Approach: Without a defined full range, surjectivity might be concluded by assuming the present outputs form the whole range, especially in limited context exercises.
Bijective Functions
A bijective function is one that is both injective (one-to-one) and surjective (onto). This creates a perfect "one-to-one correspondence" between the domain and the range. Every element in the domain maps to a unique element in the range, and every element in the range is mapped by some element of the domain.
- Example Understanding: Imagine a scenario where service provision times map perfectly and uniquely to payment amounts without gaps or repeat results for different inputs.
- Inverse Implication: If a function is bijective, it is guaranteed to have an inverse. This implies the function can "reverse," allowing us to go back from any earning to discover a distinct work period that corresponds to it.
Other exercises in this chapter
Problem 36
Use a graphing utility to graph the function and to approximate any relative minimum or relative maximum values of the function. $$f(x)=3 x^{2}-2 x-5$$
View solution Problem 36
Use a graphing utility to graph the functions \(f, g,\) and \(h\) in the same viewing window. $$f(x)=4-x^{2}, \quad g(x)=x, \quad h(x)=f(x) / g(x)$$
View solution Problem 36
Evaluate the function at each specified value of the independent variable and simplify. $$f(x)=\sqrt{x+8}+2$$ (a) \(f(-4)\) (b) \(f(8)\) (c) \(f(x-8)\)
View solution Problem 36
Using a Graphing Utility to Graph an Equation In Exercises \(31-44,\) use a graphing utility to graph the equation. Use a standard viewing window. Approximate a
View solution