Problem 36
Question
Determine the slope field and some representative solution curves for the given differential equation. $$\diamond y^{\prime}=\frac{1-y^{2}}{2+0.5 x^{2}}$$
Step-by-Step Solution
Verified Answer
The given differential equation is \[y^{\prime} = \frac{1-y^{2}}{2+0.5 x^{2}}.\] To find the slope field and representative solution curves, we first calculate the slope at different points in the xy-plane using the equation for the slope field: \(m(x, y) = \frac{1-y^{2}}{2+0.5 x^{2}}\).
Next, we plot the slope field by choosing a set of points in the xy-plane and drawing small line segments at each point with the corresponding slope calculated using the slope field equation.
Finally, once the slope field is plotted, we can visually identify representative solution curves by following the tangent lines drawn at each point. These curves give us an idea of how different solution curves to the differential equation would behave in the plane.
1Step 1: Identify the differential equation
Given differential equation is \[\ x^{\prime}=\frac{1-y^{2}}{2+0.5 x^{2}}.\]
2Step 2: Calculate the slope at different points in the xy-plane
To calculate the slope at different points, we can substitute the coordinates (x, y) of the points in the given differential equation.
Slope-field, \(m(x, y) =\frac{1-y^{2}}{2+0.5 x^{2}} \)
Here, m(x, y) represents the slope of the tangent to the solution curve at a specific point (x, y).
3Step 3: Plot the slope field
To plot the slope field, choose a set of points in the xy-plane. For each point, substitute the coordinates (x, y) in the slope field equation to determine the slope. Draw small line segments at each point with the corresponding slope.
For example, at the point (0, 0), the slope is:
\(m(0, 0) =\frac{1-0^{2}}{2+0.5 \cdot 0^{2}} =\frac{1}{2}\)
Therefore, draw a small line segment at the origin (0, 0) with a slope of 1/2.
Repeat this process for multiple points on the xy-plane. A better understanding of the problem is achieved by including more points.
4Step 4: Identify representative solution curves based on the slope field
Once the slope field is plotted, we can identify representative solution curves by following the tangent lines drawn at each point. These curves give us an idea of how different solution curves to the differential equation would behave in the plane.
Note that this is usually done visually, either by sketching out the curves manually or using a graphical approach (e.g., computer software).
Key Concepts
Slope FieldSolution CurvesTangent Line Approximation
Slope Field
A slope field, also known as a direction field, is a visual representation of differential equations on the xy-plane. It provides insight into the behavior of solutions without solving the equation analytically. In a slope field, each point \((x, y)\) in the plane is associated with a small line segment or tangent whose slope is given by the differential equation.
Here is how you can understand and use slope fields:
Here is how you can understand and use slope fields:
- Identify the differential equation, such as \(rac{dy}{dx} = rac{1-y^{2}}{2+0.5x^{2}}\).
- For each point in the xy-plane, substitute its coordinates into the equation to find the slope of the tangent line at that point.
- Draw a small line segment at each chosen point reflecting the calculated slope. This creates a grid of vectors indicating the direction of solutions.
Solution Curves
Solution curves are the actual trajectories or paths that solutions of the differential equation follow on the xy-plane. Once you have your slope field, you can sketch these curves by following the pattern of the small line segments.
Here's how you can explore solution curves:
Here's how you can explore solution curves:
- Start drawing a curve by choosing a point on the slope field as a starting point.
- Follow the direction of the nearby tangent vectors step by step to trace the path of the curve.
- Observe how the curve behaves at different sections of the slope field to understand how solutions change with respect to initial conditions.
Tangent Line Approximation
Tangent line approximation involves using the slope at a point to estimate the behavior of a solution curve near that point. This approximation is a straight line that touches the curve at a specific point and has the same slope.
To perform a tangent line approximation:
To perform a tangent line approximation:
- Calculate the slope of the tangent line at the given point from the differential equation.
- Use the point and slope to write the equation of the tangent line in the form \(y - y_1 = m(x - x_1)\), where \(m\) is the slope and \((x_1, y_1)\) is the point.
- This approximation provides insights into how the solution curve behaves in a small region around the point without needing detailed calculations.
Other exercises in this chapter
Problem 35
Determine the slope field and some representative solution curves for the given differential equation. $$\diamond y^{\prime}=\frac{2+y^{2}}{3+0.5 x^{2}}$$
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The differential equation governing a trimolecular reaction is $$ \frac{d Q}{d t}=k(\alpha-Q)(\beta-Q)(\gamma-Q) $$ where \(k, \alpha, \beta, \gamma\) are const
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Solve the given initial-value problem. $$y^{\prime}=x^{2} \ln x, \quad y(1)=2$$.
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