Problem 36
Question
A function \(f\) is given. (a) Use a graphing calculator to draw the graph of \(f .\) (b) Find the domain and range of \(f\) from the graph. $$ f(x)=\sqrt{x+2} $$
Step-by-Step Solution
Verified Answer
Domain: \([-2, \infty)\); Range: \([0, \infty)\).
1Step 1: Understanding the Function
The function given is \( f(x) = \sqrt{x + 2} \). This is a square root function, which means the expression under the square root, \(x + 2\), must be greater than or equal to zero to avoid complex numbers.
2Step 2: Finding the Domain
To find the domain, solve the inequality \( x + 2 \geq 0 \). Solve for \( x \):\[ x + 2 \geq 0 \] Subtract 2 from both sides: \[ x \geq -2 \] Thus, the domain of \( f(x) \) is all real numbers \( x \) such that \( x \geq -2 \), which can be written as \([-2, \infty)\).
3Step 3: Graphing the Function
Using a graphing calculator, plot the function \( f(x) = \sqrt{x + 2} \). This graph starts from the point (-2, 0) since the square root becomes 0 when \( x = -2 \), and it increases as \( x \) increases.
4Step 4: Determining the Range
Based on the graph, the smallest value of \( f(x) \) occurs at \( x = -2 \), which is \( f(-2) = \sqrt{-2 + 2} = 0 \). As \( x \) increases, \( f(x) \) increases without bound. Thus, the range is \([0, \infty)\).
Key Concepts
Understanding Domain and RangeUsing a Graphing CalculatorExamining Inequalities in Functions
Understanding Domain and Range
In the function \( f(x) = \sqrt{x+2} \), the domain and range are key concepts to grasp. The **domain** refers to all the possible input values \( x \) that make the function work, i.e., not resulting in complex numbers.
In square root functions like this, you must ensure that the expression under the root is non-negative. Solve the inequality \( x + 2 \geq 0 \) to find that \( x \geq -2 \). Thus, the domain is all real numbers greater than or equal to -2, written as \([-2, \infty)\).
The **range** instead is about output values. Since the smallest output happens at \( x = -2 \) where \( f(x) = 0 \) and grows as \( x \) increases, the range is \([0, \infty)\). This tells you \( f(x) \) starts at zero and increases without limit.
In square root functions like this, you must ensure that the expression under the root is non-negative. Solve the inequality \( x + 2 \geq 0 \) to find that \( x \geq -2 \). Thus, the domain is all real numbers greater than or equal to -2, written as \([-2, \infty)\).
The **range** instead is about output values. Since the smallest output happens at \( x = -2 \) where \( f(x) = 0 \) and grows as \( x \) increases, the range is \([0, \infty)\). This tells you \( f(x) \) starts at zero and increases without limit.
Using a Graphing Calculator
A graphing calculator can greatly simplify understanding the function \( f(x) = \sqrt{x+2} \). By plotting the function, you gain a visual representation that helps you see the function's behavior through its graph. To achieve this:
- Input the function \( \sqrt{x+2} \) into the calculator's graphing section.
- Set an appropriate scale to include the domain \( x \geq -2 \).
- Observe the graph forming a curve starting from the point \((-2, 0)\), moving upwards as it stretches endlessly to the right.
Examining Inequalities in Functions
Understanding inequalities in functions like \( f(x) = \sqrt{x+2} \) involves recognizing which values satisfy the inequality. Given that square roots must be non-negative, solve for \( x \) by working with inequalities. It's as follows:
When graphed, these inequalities assure the line starts right where \( x = -2 \), and values stretch infinitely forward, making the math both visual and intuitive.
- Consider the expression under the square root: \( x+2 \).
- The inequality is \( x + 2 \geq 0 \), ensuring no negative roots.
- Subtract 2 from both sides, yielding \( x \geq -2 \).
When graphed, these inequalities assure the line starts right where \( x = -2 \), and values stretch infinitely forward, making the math both visual and intuitive.
Other exercises in this chapter
Problem 36
\(29-40\) Find the functions \(f \circ g, g \circ f, f \circ f,\) and \(g \circ g\) and their domains. $$ f(x)=x-4, \quad g(x)=|x+4| $$
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\(29-38=\) Find the maximum or minimum value of the function. $$ f(x)=-\frac{x^{2}}{3}+2 x+7 $$
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33–48 ? Sketch the graph of the function, not by plotting points, but by starting with the graph of a standard function and applying transformations. $$ f(x)=1-
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Find the inverse function of \(f\). \(f(x)=\frac{1}{x^{2}}, \quad x>0\)
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