Problem 36
Question
\(35-38\) Use a graphing device to graph the conic. $$ 4 x^{2}+9 y^{2}-36 y=0 $$
Step-by-Step Solution
Verified Answer
The conic section is an ellipse centered at (0, 2) with semi-major axis length 2 and semi-minor axis length 3.
1Step 1: Rewrite the Equation
First, rewrite the equation \(4x^2 + 9y^2 - 36y = 0\) in a more familiar conic form by isolating the constant on one side. This becomes \(4x^2 + 9(y^2 - 4y) = 0\).
2Step 2: Complete the Square for the y-term
Take the y-term \(y^2 - 4y\) and complete the square. Add and subtract \(4\) inside the parentheses: \(y^2 - 4y + 4 - 4 = (y-2)^2 - 4\). The equation now looks like \(4x^2 + 9((y-2)^2 - 4) = 0\).
3Step 3: Simplify the Equation
Substitute \((y-2)^2 - 4\) into the equation: \(4x^2 + 9(y-2)^2 - 36 = 0\). Add \(36\) to both sides: \(4x^2 + 9(y-2)^2 = 36\).
4Step 4: Divide by the Constant
Divide the entire equation by \(36\) to get \(\frac{4x^2}{36} + \frac{9(y-2)^2}{36} = 1\) or \(\frac{x^2}{9} + \frac{(y-2)^2}{4} = 1\).
5Step 5: Identify the Conic Section
The final form \(\frac{x^2}{9} + \frac{(y-2)^2}{4} = 1\) is recognizable as an ellipse centered at \((0, 2)\). The semi-major axis in the y-direction has a length of \(2\) and the semi-minor axis in the x-direction has a length of \(3\).
6Step 6: Graph the Equation
Using a graphing device, plot the ellipse with the center at \((0, 2)\). Draw the semi-major axis along the vertical from \(y = 0\) to \(y = 4\) and the semi-minor axis along the horizontal from \(x = -3\) to \(x = 3\). Ensure the shape is symmetrical about the center.
Key Concepts
EllipseCompleting the SquareGraphing Conic Sections
Ellipse
An ellipse is one of the four types of conic sections, which are curves obtained by intersecting a cone with a plane. Ellipses appear in various natural and scientific contexts, from the orbits of planets to the shape of certain lenses. In mathematics, an ellipse is a set of points where the sum of the distances from two fixed points, called foci, is constant.
An ellipse is defined by its general equation:
An ellipse is defined by its general equation:
- If \(a > b\), the ellipse is oriented horizontally, and the equation is \(\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1\).
- If \(b > a\), the ellipse is oriented vertically, and the equation is \(\frac{(x-h)^2}{b^2} + \frac{(y-k)^2}{a^2} = 1\).
Completing the Square
Completing the square is a fundamental algebraic technique used to transform a quadratic equation into a perfect square trinomial. This method is especially useful for rewriting conic section equations in their standard forms, which makes identifying the type of conic easier.
Here's how it works when applied to a quadratic term, for instance in the example \(y^2 - 4y\):
Here's how it works when applied to a quadratic term, for instance in the example \(y^2 - 4y\):
- Identify the coefficient of the linear term, which is \(4\), halve it to get \(2\), and square it to obtain \(4\).
- Add and subtract this squared term inside the parentheses resulting in \(y^2 - 4y + 4 - 4\).
- This transforms into \( (y-2)^2 - 4\).
Graphing Conic Sections
Graphing conic sections, like ellipses, involves recognizing the type of conic and plotting it correctly on the coordinate plane. Each conic section—circle, ellipse, parabola, or hyperbola—has a distinct shape and equation.
For an ellipse, the equation tells us:
For an ellipse, the equation tells us:
- The center of the ellipse, derived from the terms \(h,k\) in the equation \((x-h)^2 + (y-k)^2\).
- The lengths of the axes, with the larger denominator indicating the direction of the major axis.
- The center is at \(0,2\).
- The x-axis (horizontal axis) extends \(3\) units on either side of the center, and the y-axis (vertical axis) extends \(2\) units up and down from the center.
- Plot these points and draw a smooth, symmetrical curve around the center to make the ellipse.
Other exercises in this chapter
Problem 36
Find an equation for the hyperbola that satisfies the given conditions. Vertices: \((0, \pm 6),\) asymptotes: \(y=\pm \frac{1}{3} X\)
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(a) Find the eccentricity and identify the conic. (b) Sketch the conic and label the vertices. $$ r=\frac{8}{3+\cos \theta} $$
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Show that the graph of the equation $$ \sqrt{x}+\sqrt{y}=1 $$ is part of a parabola by rotating the axes through an angle of \(45^{\circ} .[\text { Hint: First
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Find an equation for the ellipse that satisfies the given conditions. Length of major axis: \(6,\) length of minor axis: \(4,\) foci on \(x\) -axis
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