Problem 36
Question
\(25-48=\) Write the complex number in polar form with argument \(\theta\) between 0 and 2\(\pi .\) $$ 8 i $$
Step-by-Step Solution
Verified Answer
The polar form is \( 8(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}) \).
1Step 1: Identify the Real and Imaginary Parts
The given complex number is just the imaginary part, which is \(8i\). Thus, the real part \(x = 0\) and the imaginary part \(y = 8\).
2Step 2: Calculate the Magnitude
The magnitude \(r\) of a complex number \(x + yi\) is given by the formula \( r = \sqrt{x^2 + y^2} \). Substituting the values, we get \( r = \sqrt{0^2 + 8^2} = \sqrt{64} = 8 \).
3Step 3: Determine the Argument \(\theta\)
Since the real part \(x = 0\) and the imaginary part \(y = 8\) is positive, the complex number lies on the positive imaginary axis. In this case, \( \theta = \frac{\pi}{2} \).
4Step 4: Write the Polar Form
Having found both the magnitude and the argument, the polar form of the complex number is given by \( 8 \left(\cos \frac{\pi}{2} + i \sin \frac{\pi}{2}\right) \).
Key Concepts
Polar FormMagnitude of Complex NumbersArgument of Complex NumbersImaginary Part
Polar Form
Complex numbers can be represented in different forms. One of these forms is the polar form. This representation is great for understanding the geometric properties of complex numbers. Instead of expressing complex numbers in their rectangular form, which is usually as \(x + yi\), the polar form uses the magnitude of the number and an angle known as the argument.
The polar form of a complex number is given by:
The polar form of a complex number is given by:
- \( r(\cos \theta + i \sin \theta) \)
- The parameter \( r \) is the magnitude of the complex number.
- The angle \( \theta \) is the argument.
Magnitude of Complex Numbers
The magnitude of a complex number is a measure of its size or length from the origin in the complex plane. For a complex number \(x + yi\), the magnitude is calculated using the formula:
In the context of our example, for \(8i\):
- \[ r = \sqrt{x^2 + y^2} \]
In the context of our example, for \(8i\):
- The real part is 0, so \(x = 0\).
- The imaginary part is 8, so \(y = 8\).
- Magnitude is \( r = \sqrt{0^2 + 8^2} = 8 \).
Argument of Complex Numbers
The argument of a complex number is the angle formed with the positive real axis in the complex plane. It's a way to express the direction of the complex number.
For \(x + yi\), to find the argument \(\theta\):
For \(x + yi\), to find the argument \(\theta\):
- Use \(\theta = \tan^{-1}\left(\frac{y}{x}\right)\).
- \(\theta = \frac{\pi}{2}\) or \(90^\circ\).
Imaginary Part
The imaginary part of a complex number is the coefficient of \(i\), which is the unit imaginary number defined as \(i^2 = -1\). In a complex number form \(x + yi\), \(y\) is known as the imaginary part.
Consider the complex number \(8i\):
Consider the complex number \(8i\):
- The real part \(x = 0\), which means there is no horizontal component.
- The imaginary part is \(y = 8\), so it simply represents the vertical component on the imaginary plane.
Other exercises in this chapter
Problem 36
33-36 Let \(\mathbf{u}, \mathbf{v},\) and \(\mathbf{w}\) be vectors and let \(a\) be a scalar. Prove the given property. $$(\mathbf{u}-\mathbf{v}) \cdot(\mathbf
View solution Problem 36
Convert the rectangular coordinates to polar coordinates with \(r>0\) and \(0 \leq \theta
View solution Problem 36
15–36 Sketch the graph of the polar equation. $$r=\sin \theta \tan \theta \quad \text {(cissoid)}$$
View solution Problem 37
Find the magnitude and direction (in degrees) of the vector. $$ \mathbf{v}=\mathbf{i}+\sqrt{3} \mathbf{j} $$
View solution