Problem 36
Question
\(21-44\) . Sketch the graph of the function, not by plotting points, but by starting with the graph of a standard function and applying transformations. $$ y=\frac{1}{2}|\boldsymbol{X}| $$
Step-by-Step Solution
Verified Answer
The graph of \( y = \frac{1}{2}|x| \) is a V-shape with a vertex at (0,0) and arms with slope 0.5.
1Step 1: Identify the Standard Function
The given function is based on the absolute value function \( |x| \), which is a well-known V-shaped graph with its vertex at the origin (0, 0). The arms of the V symmetrically extend upwards with a slope of 1.
2Step 2: Recognize the Vertical Scaling Transformation
The function \( y = \frac{1}{2}|x| \) involves a vertical scaling transformation of the standard absolute value function. Instead of the slope being 1 on each side of the vertex, the slope will be \( \frac{1}{2} \). This transformation compresses the graph vertically by half.
3Step 3: Sketch the Transformed Graph
Start at the origin (0, 0), which remains the vertex of the graph. For the right arm (when x > 0), instead of increasing by 1 unit for each unit increase in x, the y-values increase by \( \frac{1}{2} \) times the x-values. For the left arm (when x < 0), the same reduced slope applies, mirroring the right arm.
Key Concepts
Understanding the Absolute Value FunctionEssentials of Graph SketchingVertical Scaling and Its Effects
Understanding the Absolute Value Function
The absolute value function, represented as \(|x|\), forms the basis of our graph. It is easily recognizable by its V-shape, which is symmetrical about the y-axis. The graph's vertex is at the origin \((0,0)\), which serves as a pivot point where the direction of the graph changes. This function calculates the distance of any number from zero without considering the sign of the number. This means that for any input \(x\), the value \(|x|\) is always non-negative. Key characteristics of the absolute value function include:
- A V-shaped appearance.
- A vertex at the origin.
- Both arms of the V extending upwards with a slope of 1.
Essentials of Graph Sketching
Graph sketching is an important skill that combines understanding of standard functions and applying transformations to visualize different functional forms. Instead of plotting individual points, graph sketching starts from a basic, well-known graph—like the absolute value function—and applies transformations systematically. Here's how it works:
- Identify the Base Graph: Begin with a simple graph such as the absolute value function.
- Determine Transformations: Recognize any changes to this base graph, such as translations, reflections, or scalings.
- Visualize the Adjustments: Apply the transformations mentally or on paper to see the new shape of the graph.
Vertical Scaling and Its Effects
Vertical scaling is a type of transformation that affects how a graph stretches or compresses in the y-direction. When dealing with the function \(y = \frac{1}{2}|x|\), you are performing a vertical scaling on the standard absolute value function graph.In vertical scaling:
- Scaling Factor Less Than 1: The function is compressed. In our example, the factor is \(\frac{1}{2}\), meaning the graph is squished towards the x-axis by half.
- Scaling Factor Greater Than 1: The graph would stretch away from the x-axis, becoming taller and steeper.
- The vertex remains unchanged, ensuring the graph's focus point stays at the origin \((0,0)\).
Other exercises in this chapter
Problem 36
Use the Inverse Function Property to show that \(f\) and \(g\) are inverses of each other. $$ f(x)=\frac{x-5}{3 x+4}, \quad g(x)=\frac{5+4 x}{1-3 x} $$
View solution Problem 36
Sketch the graph of the piecewise defined function. \(f(x)=\left\\{\begin{array}{ll}{1-x} & {\text { if } x
View solution Problem 36
\(35-42\) A function is given. (a) Find all the local maximum and minimum values of the function and the value of \(x\) at which each occurs. State each answer
View solution Problem 36
Find \(f(a), f(a+h),\) and the difference quotient \(\frac{f(a+h)-f(a)}{h},\) where \(h \neq 0\) $$ f(x)=x^{2}+1 $$
View solution