Problem 355
Question
Use a calculator with CAS to answer the questions. Consider \(\frac{x^{k}-1}{x-1}\) with \(k=1, 2, 3 .\) What do you expect the result to be if \(k=4 ?\)
Step-by-Step Solution
Verified Answer
The result for \( k=4 \) is \( x^3 + x^2 + x + 1 \).
1Step 1: Examine the Expression for k=1
Start by considering the expression \( \frac{x^k - 1}{x - 1} \) for \( k=1 \). This simplifies to \( \frac{x^1 - 1}{x - 1} = \frac{x - 1}{x - 1} = 1 \).
2Step 2: Examine the Expression for k=2
Next, consider \( k=2 \). The expression becomes \( \frac{x^2 - 1}{x - 1} \), which can be factored as \( \frac{(x-1)(x+1)}{x-1} = x + 1 \).
3Step 3: Examine the Expression for k=3
For \( k=3 \), the expression is \( \frac{x^3 - 1}{x - 1} \). This can be factored as \( \frac{(x-1)(x^2 + x + 1)}{x-1} = x^2 + x + 1 \).
4Step 4: Generalize the Pattern
Based on the previous results, notice a pattern:- For \( k=1 \), the result was \( 1 \).- For \( k=2 \), the result was \( x+1 \).- For \( k=3 \), the result was \( x^2 + x + 1 \).The pattern indicates that for \( k \), it results in a polynomial of degree \( k-1 \).
5Step 5: Predict the Result for k=4
Following the identified pattern, for \( k=4 \), the expression \( \frac{x^4 - 1}{x - 1} \) should become a polynomial of degree 3. Using the polynomial pattern, it becomes: \( x^3 + x^2 + x + 1 \).
Key Concepts
Polynomial ExpressionsCAS (Computer Algebra System)Factoring Expressions
Polynomial Expressions
Polynomial expressions are mathematical expressions that consist of variables and coefficients. They are built from adding, subtracting, and multiplying these elements, with non-negative integer exponents.
For instance, in \((x^3 + x^2 + x + 1)\), we see a polynomial of degree 3, where degree refers to the highest exponent of the variable present. Each term in this polynomial has its significance:
When working with polynomial expressions, one might need to simplify, expand, or factor them to reach a desired format. This is often guided by recognizing patterns like those observed in our original exercise, where a series of simplifying expressions grew organically from evaluating \((x^k-1)/(x-1)\).
For instance, in \((x^3 + x^2 + x + 1)\), we see a polynomial of degree 3, where degree refers to the highest exponent of the variable present. Each term in this polynomial has its significance:
- \(x^3\) is a cubic term.
- \(x^2\) is a quadratic term.
- \(x\) is a linear term.
- \(1\) is a constant term.
When working with polynomial expressions, one might need to simplify, expand, or factor them to reach a desired format. This is often guided by recognizing patterns like those observed in our original exercise, where a series of simplifying expressions grew organically from evaluating \((x^k-1)/(x-1)\).
CAS (Computer Algebra System)
A Computer Algebra System (CAS) is a powerful tool used to manipulate mathematical expressions and solve complex algebraic equations.
These systems can handle a wide range of tasks from simple arithmetic to complex integration. By using a CAS, students and professionals can focus more on understanding the concepts rather than getting bogged down by lengthy calculations.
For instance, when tasked with simplifying or evaluating expressions like \((x^k-1)/(x-1)\), a CAS can automate the process of factoring, expanding, or reducing these expressions efficiently.
These systems can handle a wide range of tasks from simple arithmetic to complex integration. By using a CAS, students and professionals can focus more on understanding the concepts rather than getting bogged down by lengthy calculations.
For instance, when tasked with simplifying or evaluating expressions like \((x^k-1)/(x-1)\), a CAS can automate the process of factoring, expanding, or reducing these expressions efficiently.
- CAS softwares are designed to provide general solutions to algebraic problems.
- They can be used to efficiently find results for multiple scenarios, such as the progression with different values of \k\.
Factoring Expressions
Factoring expressions is a fundamental skill in algebra. It involves breaking down a complex expression into simpler, multipliable components.
In many cases, factoring is used to simplify polynomials, making them easier to handle, analyze, and solve.
To illustrate, let's consider the factorization steps for \((x^k-1)/(x-1)\). When \k=2\, the expression \((x^2-1)/(x-1)\) can be factored as \((x-1)(x+1)/(x-1)\), leading to \(x+1\).
In many cases, factoring is used to simplify polynomials, making them easier to handle, analyze, and solve.
To illustrate, let's consider the factorization steps for \((x^k-1)/(x-1)\). When \k=2\, the expression \((x^2-1)/(x-1)\) can be factored as \((x-1)(x+1)/(x-1)\), leading to \(x+1\).
- Factoring unveils hidden structures in algebraic expressions.
- It simplifies the process of solving equations by reducing complexity.
- It is often a prerequisite step before applying other algebraic operations.
Other exercises in this chapter
Problem 353
Use synthetic division to find the quotient and remainder. $$\frac{-4 x^{3}-x^{2}-12}{x+4}$$
View solution Problem 354
Use synthetic division to find the quotient and remainder. $$\frac{x^{4}-22}{x+2}$$
View solution Problem 357
Use a calculator with CAS to answer the questions. Consider \(\frac{x^{4}-k^{4}}{x-k}\) for \(k=1, 2, 3,\) What do you expect the result to be if \(k=4 ?\)
View solution Problem 359
Use a calculator with CAS to answer the questions. Consider \(\frac{x^{k}}{x-1}\) with \(k=1, 2, 3 .\) What do you expect the result to be if \(k=4 ?\)
View solution