Problem 35
Question
Write each matrix equation as a system of linear equations without matrices. $$\left[\begin{array}{rrr}2 & 0 & -1 \\\0 & 3 & 0 \\\1 & 1 & 0\end{array}\right]\left[\begin{array}{l} x \\\y \\\z\end{array}\right]=\left[\begin{array}{l}6 \\\9 \\\5\end{array}\right]$$
Step-by-Step Solution
Verified Answer
\[2x - z = 6, 3y = 9, x + y = 5\]
1Step 1: Formulate first equation
From the first row of the matrix, form a linear equation by multiplying: \(2x + 0y -1z = 6\). This simplifies to: \(2x - z = 6\).
2Step 2: Formulate second equation
From the second row of the matrix, a linear equation can be formed by multiplying: \(0x + 3y + 0z = 9\). This simplifies to: \(3y = 9\).
3Step 3: Formulate third equation
From the third row of the matrix, a linear equation can be formed by multiplying: \(x + y + 0z = 5\). This simplifies to: \(x + y = 5\).
Key Concepts
Matrix EquationLinear AlgebraSolving Systems of Equations
Matrix Equation
A matrix equation is a compact way of representing multiple linear equations. It uses matrices and vectors to simplify the presentation of a system of equations. Suppose you have a matrix \( A \) and a vector \( \mathbf{x} \), the product \( A\mathbf{x} \) results in another vector. This vector is equivalent to a series of linear combinations of \( \mathbf{x} \). This combination translates into separate linear equations. In our exercise, the equation \(\left[\begin{array}{rrr}2 & 0 & -1 \0 & 3 & 0 \1 & 1 & 0\end{array}\right]\left[\begin{array}{l} x \y \z\end{array}\right]=\left[\begin{array}{l}6 \9 \5\end{array}\right]\) can be split into separate linear equations.
- The first row results in the equation \(2x - z = 6\)
- The second row gives \(3y = 9\)
- The third row translates to \(x + y = 5\)
Linear Algebra
Linear algebra is a vibrant branch of mathematics that focuses on vectors, matrices, and linear mappings between spaces. It provides the groundwork for many areas such as computer science, physics, and engineering. This field allows us to handle a set of equations using matrices which simplifies computations greatly. Key Elements of Linear Algebra:
- Matrices: Rectangular arrays of numbers or expressions.
- Vectors: Lists of numbers that can represent points, directions, or other quantities.
- Linear transformations: Functions mapping vectors to vectors following this rule: \(T(ax + by) = aT(x) + bT(y)\).
Solving Systems of Equations
Solving systems of linear equations involves finding values for variables that satisfy all equations simultaneously. This can be approached using several methods, and here are a few:
Methods to Solve Systems:
- Substitution: Solve one equation for one variable, then substitute into another equation.
- Elimination: Add or subtract equations to eliminate variables step-by-step.
- Matrix Method: Use row operations on matrices to reach solutions efficiently.
Other exercises in this chapter
Problem 34
solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{array}{l} 3 x+2 y+
View solution Problem 35
Use Cramer's Rule to solve each system. $$\left\\{\begin{aligned}x+\quad 2 z &=4 \\\2 y-z &=5 \\\2 x+3y\quad &=13\end{aligned}\right.$$
View solution Problem 35
solve each system of equations using matrices. Use Gaussian elimination with back-substitution or Gauss-Jordan elimination. $$ \left\\{\begin{array}{c} w+x+y+z=
View solution Problem 36
Find (if possible) the following matrices: \(a, A B\) \(\boldsymbol{b}, B A\) $$A=\left[\begin{array}{rrrr}2 & -1 & 3 & 2 \\\1 & 0 & -2 & 1\end{array}\right], \
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