Problem 35
Question
Use row operations on an augmented matrix to solve each system of equations. Round to nearest thousandth when appropriate. $$\begin{aligned} &2 x-3 y=10\\\ &2 x+2 y=5 \end{aligned}$$
Step-by-Step Solution
Verified Answer
The solution is \(x = 3.5\), \(y = -1\).
1Step 1: Write the Augmented Matrix
First, write the system of linear equations as an augmented matrix. For the given system \(2x - 3y = 10\) and \(2x + 2y = 5\), the augmented matrix is: \[\begin{bmatrix} 2 & -3 & | & 10 \2 & 2 & | & 5 \end{bmatrix}\]
2Step 2: Perform Row Operations to Eliminate x
To eliminate the \(x\) variable from the second row, subtract the first row from the second row:\[R_2 = R_2 - R_1\]This gives the new augmented matrix:\[\begin{bmatrix} 2 & -3 & | & 10 \0 & 5 & | & -5 \end{bmatrix}\]
3Step 3: Solve for y
Use the second row of the matrix \(0y + 5y = -5\) to solve for \(y\). By simplifying, we find:\[5y = -5\]Divide both sides by 5:\[y = -1\]
4Step 4: Substitute y Back to Find x
Substitute \(y = -1\) into one of the original equations, for example, \(2x - 3y = 10\):\[2x - 3(-1) = 10\]Simplify and solve for \(x\):\[ 2x + 3 = 10\]\[2x = 7\]Divide both sides by 2:\[x = 3.5\]
5Step 5: Verify the Solution
Substitute \(x = 3.5\) and \(y = -1\) back into the second original equation to verify the solution:\[2(3.5) + 2(-1) = 5\]\[7 - 2 = 5\]This is true, confirming that the solution is correct.
Key Concepts
Understanding Row OperationsSolving Systems of EquationsThe Basics of Linear EquationsMatrix Solutions and Their Importance
Understanding Row Operations
Row operations are crucial when working with augmented matrices to solve systems of equations. They allow us to manipulate the rows of a matrix to achieve a desired form without actually changing the solution to the system. This is just like solving the equations by hand but in a structured and organized way.There are three primary row operations:
Just as with solving equations by hand, these operations help simplify and progress towards the solution.
- Swapping two rows
- Multiplying a row by a non-zero constant
- Adding or subtracting the multiples of one row to another row
Just as with solving equations by hand, these operations help simplify and progress towards the solution.
Solving Systems of Equations
A system of equations involves finding the values of variables that satisfy multiple equations at once. In our example, we have two equations with two unknowns: \(x\) and \(y\). Systems of equations can generally be solved through:
- Substitution
- Elimination
- Graphical methods
- Using matrices and row operations
The Basics of Linear Equations
Linear equations are equations where the variables are in the first degree, meaning they are not squared, cubed, etc. They appear in the form \(ax + by = c\). In our example, such linear equations are \(2x - 3y = 10\) and \(2x + 2y = 5\).Important points about linear equations:
- Each solution represents a point on a coordinate plane where the two lines intersect
- If two lines are parallel, they have no points in common, leading to no solution
- If two lines coincide, there are infinitely many solutions
Matrix Solutions and Their Importance
Matrices are an organized way of representing and solving equations, especially useful for systems with multiple equations. With an augmented matrix, we're incorporating both the coefficients of variables and the constants—everything needed to solve the system into one table-like array.
Using augmented matrices to find solutions provides several benefits:
- Reduces computational error by structuring the process
- Makes it easier to handle large systems of equations
- Facilitates using computers and calculators for solving complex systems efficiently
Other exercises in this chapter
Problem 35
Solve each system by elimination. $$\begin{array}{c}4 x-y=9 \\\\-8 x+2 y=-18\end{array}$$
View solution Problem 35
Checking Analytic Skills Graph the solution set of each system of inequalities by hand. Do not use a calculator. $$\begin{array}{r}x+y \geq 0 \\\2 x-y \geq 3\en
View solution Problem 35
Solve each system by using the matrix inverse method. $$\begin{aligned} &2 x-y=-8\\\ &3 x+y=-2 \end{aligned}$$
View solution Problem 35
\(\begin{aligned} &\frac{2}{x}-\frac{2}{y}+\frac{1}{z}=-1\\\ &\frac{4}{x}+\frac{1}{y}-\frac{2}{z}=-9\\\ &\frac{1}{x}+\frac{1}{y}-\frac{3}{z}=-9 \end{aligned}\)
View solution