Problem 35
Question
The common ratio in a geometric sequence is \(\frac{2}{5},\) and the fourth term is \(\frac{5}{2} .\) Find the third term.
Step-by-Step Solution
Verified Answer
The third term is \( \frac{25}{4} \).
1Step 1: Understanding the Geometric Sequence Formula
A geometric sequence is defined by the formula for the nth term: \( a_n = a_1 imes r^{(n-1)} \), where \( a_1 \) is the first term, \( r \) is the common ratio, and \( n \) is the term number. Our objective is to find the third term.
2Step 2: Establish the Known Information
We know that the fourth term \( a_4 = \frac{5}{2} \) and the common ratio \( r = \frac{2}{5} \). We will use these known values to find the third term.
3Step 3: Apply the Fourth Term Formula
Using \( a_4 = a_1 imes r^{3} = \frac{5}{2} \), substitute for \( r \) to get: \( a_1 \times \left( \frac{2}{5} \right)^3 = \frac{5}{2} \).
4Step 4: Simplify and Solve for \( a_1 \)
Simplify \( \left( \frac{2}{5} \right)^3 = \frac{8}{125} \), so the equation becomes: \( a_1 \times \frac{8}{125} = \frac{5}{2} \). Multiply both sides by \( \frac{125}{8} \) to solve for \( a_1 \). We find that \( a_1 = \frac{5}{2} \times \frac{125}{8} \).
5Step 5: Calculate \( a_1 \)
Calculate \( a_1 = \frac{5 \times 125}{2 \times 8} = \frac{625}{16} \). Thus, the first term \( a_1 = \frac{625}{16} \).
6Step 6: Find the Third Term
Using the formula for the third term \( a_3 = a_1 \times r^{2} \), substitute \( a_1 = \frac{625}{16} \) and \( r = \frac{2}{5} \). So, \( a_3 = \frac{625}{16} \times \left( \frac{2}{5} \right)^2 = \frac{625}{16} \times \frac{4}{25} \).
7Step 7: Simplify the Third Term
Calculate \( a_3 = \frac{625 \times 4}{16 \times 25} = \frac{2500}{400} = \frac{250}{40} = \frac{25}{4} \). Therefore, the third term is \( \frac{25}{4} \).
Key Concepts
Common RatioNth Term FormulaFourth TermThird Term
Common Ratio
In a geometric sequence, the common ratio is a key concept. It is the constant factor that you multiply by to get from one term to the next. For example, in the problem provided, the common ratio is \( \frac{2}{5} \). This means that each term in the sequence is \( \frac{2}{5} \) times the previous term.
The common ratio can be any non-zero number, and it determines the direction and rate of growth or decay of the sequence:
The common ratio can be any non-zero number, and it determines the direction and rate of growth or decay of the sequence:
- If \( r > 1 \), the sequence grows exponentially.
- If \( 0 < r < 1 \), the sequence decreases and approaches zero but never reaches it.
- If \( r = 1 \), all terms are equal to the first term.
- If \( r < 0 \), terms will alternate in sign.
Nth Term Formula
The nth term formula for a geometric sequence is a fundamental tool to find any term in the sequence. It is given by \( a_n = a_1 \times r^{(n-1)} \), where:
For example, using the nth term formula, you can find the third term (\( a_3 \)) or the fourth term (\( a_4 \)) once you have \( a_1 \) and \( r \) handy.
- \( a_n \) is the nth term you're trying to find.
- \( a_1 \) is the first term of the sequence.
- \( r \) is the common ratio.
- \( n \) is the position of the term in the sequence.
For example, using the nth term formula, you can find the third term (\( a_3 \)) or the fourth term (\( a_4 \)) once you have \( a_1 \) and \( r \) handy.
Fourth Term
To find the fourth term in a geometric sequence, you use the nth term formula, substituting \( n = 4 \). For instance, in our scenario, the fourth term \( a_4 \) is given as \( \frac{5}{2} \).
This information is crucial because it acts as a checkpoint, allowing us to reverse-engineer the sequence and find other terms.
By rewriting the formula to express \( a_1 \) in terms of the given fourth term, we acknowledge:
This information is crucial because it acts as a checkpoint, allowing us to reverse-engineer the sequence and find other terms.
By rewriting the formula to express \( a_1 \) in terms of the given fourth term, we acknowledge:
- \( a_4 = a_1 \times r^3 \)
Third Term
The task of finding the third term of a geometric sequence is an interesting exercise in applying the nth term formula. In our example, once we know the first term \( a_1 \) and the common ratio \( r \), we can use the formula \( a_3 = a_1 \times r^2 \) to find the third term.
Start by substituting the values you have:
This step-by-step approach reinforces your understanding of geometric sequences and highlights the importance of using known values correctly to find unknown terms.
Start by substituting the values you have:
- \( a_1 = \frac{625}{16} \)
- \( r = \frac{2}{5} \)
- \( a_3 = \frac{625}{16} \times \left( \frac{2}{5} \right)^2 \)
This step-by-step approach reinforces your understanding of geometric sequences and highlights the importance of using known values correctly to find unknown terms.
Other exercises in this chapter
Problem 35
Find the term containing \(x^{4}\) in the expansion of \((x+2 y)^{10}\)
View solution Problem 35
Determine whether each statement is true or false. If you think the statement is true, prove it. If you think it is false, give an example where it fails. (a) \
View solution Problem 35
The 100th term of an arithmetic sequence is \(98,\) and the common difference is \(2 .\) Find the first three terms.
View solution Problem 35
Find the first four partial sums and the \(n\)th partial sum of the sequence \(a_{n} .\) \(a_{n}=\frac{2}{3^{n}}\)
View solution