Problem 35
Question
Solve the quadratic equation by completing the square. $$x^{2}-2 x=4$$
Step-by-Step Solution
Verified Answer
The solutions to the equation are \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \).
1Step 1: Arrangement of terms
Rearrange the equation to the form \( ax^{2} + bx + c = 0 \) by moving the constant term to the right side. So, \( x^{2} - 2x = 4 \) becomes \( x^{2} - 2x - 4 = 0 \).
2Step 2: Completing the square
To complete the square, the idea is to make the left side of the equation a perfect square. The square of \((x - m)\) can be written as \( x^{2} - 2mx + m^{2} \), where m is the half of the coefficient of x in the quadratic equation. Here \( m = 1 \). Therefore the equation can be written as \( (x - 1)^{2} - 1^{2} = 0 +1^{2} \) which gives \( (x - 1)^{2} = 5 \).
3Step 3: Solving for x
Taking square root on both sides, there are two solutions for \(x -1 \), which are \( \sqrt{5} \) and \( -\sqrt{5} \). Adding 1 to both sides we get \( x = 1 + \sqrt{5} \) and \( x = 1 - \sqrt{5} \).
Key Concepts
Quadratic equationsPerfect squareSolving equations
Quadratic equations
Quadratic equations are a special type of polynomial equation. They have the general form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( x \) represents an unknown variable. The defining feature of quadratic equations is that the highest degree (or the power) of \( x \) is 2.
These equations are fundamental in algebra and come up often because they describe parabola shapes when graphed on a coordinate plane.
You might encounter them in real-world scenarios, such as calculating the trajectory of a projectile or optimizing areas.
These equations are fundamental in algebra and come up often because they describe parabola shapes when graphed on a coordinate plane.
You might encounter them in real-world scenarios, such as calculating the trajectory of a projectile or optimizing areas.
- When solving quadratic equations, there are multiple methods available: factoring, using the quadratic formula, and completing the square.
- Each method has its use, depending on the characteristics of the equation.
Perfect square
A perfect square is a number that can be expressed as the product of an integer with itself. In the context of quadratic equations, a perfect square trinomial is an expression that takes the form \( (x - m)^2 \). Completing the square involves rewriting part of the quadratic as a perfect square trinomial.
The process of completing the square includes:
The process of completing the square includes:
- Starting with the quadratic expression, rearrange it into the form \( ax^2 + bx \).
- Identify the coefficient of \( x \), then take half of this coefficient (let’s call it \( m \)), and square it to get \( m^2 \).
- Add and subtract \( m^2 \) inside the equation to form a complete square.
Solving equations
Solving an equation involves finding the value(s) of the unknown variables that make the equation true. For quadratic equations, once they are arranged in a solvable form (like a perfect square), we employ algebraic manipulations to arrive at solutions.
When a quadratic is set up as a perfect square trinomial, we can solve for \( x \) by taking the square root of both sides. Remember, squaring introduces both positive and negative solutions. This is why we consider both \( \sqrt{5} \) and \( -\sqrt{5} \) as part of solving the equation in our example.
When a quadratic is set up as a perfect square trinomial, we can solve for \( x \) by taking the square root of both sides. Remember, squaring introduces both positive and negative solutions. This is why we consider both \( \sqrt{5} \) and \( -\sqrt{5} \) as part of solving the equation in our example.
- Taking square roots is a critical step that gives two possible solutions.
- After computing the square root, rearrange the equation by isolating \( x \), which may involve adding or subtracting terms on both sides.
Other exercises in this chapter
Problem 35
Find the complex conjugate of each number. $$i^{2}$$
View solution Problem 35
In Exercises \(17-40,\) let \(f(x)=-x^{2}+x, g(x)=\frac{2}{x+1},\) and \(h(x)=-2 x+1 .\) Evaluate each of the following. $$\left(\frac{f}{g}\right)(-2)$$
View solution Problem 35
Decide if each function is odd, even, or neither by using the definitions. $$f(x)=(x+1)^{2}$$
View solution Problem 36
Solve the inequality algebraically or graphically. $$-x^{2}-4>0$$
View solution