Problem 35
Question
Solve each equation and inequality. \(|5 x+9| \leq 16\)
Step-by-Step Solution
Verified Answer
The solution is
\[-5 \leq x \leq \frac{7}{5}\].
1Step 1: Understand the Absolute Value Inequality
An absolute value inequality such as \[|5x + 9| \leq 16\] means that the expression inside the absolute value can be between \[-16\] and \[16\] inclusive. This expresses that the distance from zero is less than or equal to \[16.\]
2Step 2: Set Up the Compound Inequality
Rewrite the absolute value inequality as a compound inequality without the absolute value.\[-16 \leq 5x + 9 \leq 16\]This shows two separate inequalities combined into one. The expression \[5x + 9\] must be greater than or equal to \[-16\] and less than or equal to \[16.\]
3Step 3: Solve the First Inequality
Let's solve the first inequality:\[-16 \leq 5x + 9\]Subtract \[9\] from both sides:\[-16 - 9 \leq 5x\] which simplifies to:\[-25 \leq 5x\]Now, divide by \[5\]:\[-5 \leq x\]
4Step 4: Solve the Second Inequality
Now, solve the second part of the compound inequality:\[5x + 9 \leq 16\]Subtract \[9\] from both sides:\[5x \leq 16 - 9\]This simplifies to:\[5x \leq 7\]Divide by \[5\]:\[x \leq \frac{7}{5}\]
5Step 5: Combine the Solutions
Combine the solutions from Step 3 and Step 4 to get the final solution for the inequality:\[-5 \leq x \leq \frac{7}{5}\]This means \[x\] can be any value between \[-5\] and \[\frac{7}{5}\], inclusive.
Key Concepts
Compound InequalitiesSolving InequalitiesAlgebraic Expressions
Compound Inequalities
Compound inequalities are a powerful tool in algebra. They allow us to combine two inequalities into one statement. This can often simplify the problem-solving process by giving you a more holistic view of the possible values for your variable. In the context of the original exercise, the absolute value inequality \(|5x + 9| \leq 16\) translates to a compound inequality: \(-16 \leq 5x + 9 \leq 16\). Here, the compound inequality is made up of two separate statements joined by the word "and." Our goal is to satisfy both conditions simultaneously.
- First, we have \(-16 \leq 5x + 9\).
- Second, \(5x + 9 \leq 16\).
Solving Inequalities
When it comes to solving inequalities, it's essential to follow similar steps as solving equations, with a few key differences. In inequalities, you are often working with a range of values rather than a specific number. Here, for our compound inequality \(-16 \leq 5x + 9 \leq 16\), we handle each part of the compound inequality individually.Let's break it down:
- For \(-16 \leq 5x + 9\), subtract \(9\) from both sides to isolate the term with \(x\), giving \(-25 \leq 5x\).
- Next, divide by \(5\) to solve for \(x\), resulting in \(-5 \leq x\).
- For the other part, \(5x + 9 \leq 16\), similarly subtract \(9\) from both sides to get \(5x \leq 7\).
- Dividing by \(5\), we find \(x \leq \frac{7}{5}\).
Algebraic Expressions
Understanding algebraic expressions is essential in solving absolute value inequalities like the one in the exercise. Here, the expression \(5x + 9\) plays a central role and needs careful handling.An algebraic expression, simply put, is a combination of numbers, variables, and operational signs. In our case:
- Number: \(9\)
- Variable term: \(5x\)
- Operations involve addition and multiplication.
Other exercises in this chapter
Problem 34
Solve each equation. \(n-\frac{3 n+1}{6}-1=\frac{2 n+4}{12}\)
View solution Problem 34
Solve each equation. \(-5(x-1)=12\)
View solution Problem 35
For Problems \(35-44\), solve each compound inequality and graph the solution sets. Express the solution sets in interval notation. \(x-2>-1 \quad\) and \(\quad
View solution Problem 35
Express each interval as an inequalit using the variable \(x\). For example, we can express the inter val \([5, \infty)\) as \(x \geq 5\). \(-10 \leq 2+4 x\)
View solution